Quiz Induksi Magnetik
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Questions and Answers
- 1.
Kutub selatan magnet jarum pada kompas menunjuk arah . . . .
- A.
Kutub Selatan magnet bumi
- B.
Kutub Utara Magnet bumi
- C.
Kutub Utara
- D.
Khatulistiwa
- E.
Tidak tentu
Correct Answer
B. Kutub Utara Magnet bumiExplanation
The correct answer is "Kutub Utara Magnet bumi". The explanation for this answer is that the south pole of a compass needle is attracted to the north magnetic pole of the Earth's magnetic field. This means that the south pole of the compass needle points towards the Earth's magnetic north pole, which is located near the geographic North Pole. Therefore, the compass needle points in the direction of the Earth's magnetic north pole, which is the correct answer.Rate this question:
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- 2.
Perhatikan pernyataan-pernyataan berikut! 1. Keluar dari kutub utara 2. Tolak menolak antara kutub yang sejenis 3. Masuk ke kutub selatan 4. Tarik menarik antara kutub yang sejenis Pernyataan yang benar tentang medan magnet, magnetbatang adalah nomor . . . .
- A.
1, 2, dan 3
- B.
1 dan 3
- C.
2 dan 4
- D.
4 saja
- E.
Semuanya
Correct Answer
A. 1, 2, dan 3Explanation
Pernyataan nomor 1, 2, dan 3 benar tentang medan magnet, magnet batang. Pernyataan nomor 1 menyatakan bahwa medan magnet keluar dari kutub utara, yang sesuai dengan sifat kutub utara magnet. Pernyataan nomor 2 menyatakan bahwa ada tolak menolak antara kutub yang sejenis, yang berarti kutub utara magnet akan tolak menolak dengan kutub utara magnet lainnya. Pernyataan nomor 3 menyatakan bahwa medan magnet masuk ke kutub selatan, yang sesuai dengan sifat kutub selatan magnet. Oleh karena itu, jawaban yang benar adalah 1, 2, dan 3.Rate this question:
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- 3.
Titik P berjarak 10 cm dari suatu kawat penghantar yang sangat panjang dan berarus I. Jika besar induksi magnetik di titik P sebesar 2 x 10–6 T maka besarnya arus I yang mengalir pada kawat adalah . . . .
- A.
1 Ampere
- B.
2 Ampere
- C.
3 Ampere
- D.
4 Ampere
- E.
5 Ampere
Correct Answer
A. 1 AmpereExplanation
The correct answer is 1 Ampere because the question states that the distance between point P and the long conductor is 10 cm, and the magnetic field at point P is given as 2 x 10^-6 T. The magnetic field at a distance r from a long conductor carrying current I is given by B = (μ0 * I) / (2πr), where μ0 is the permeability of free space. Plugging in the given values, we can solve for I and find that it is equal to 1 Ampere.Rate this question:
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- 4.
Seutas kawat berarus membentang diantara dua tiang listrik. Jika arah arus listrik yang mengalir dalam kawat dari arah Utara ke Selatan, maka medan magnet yang terletak tepat di bawah kawat akan berarah ke . . . .
- A.
Utara
- B.
Selatan
- C.
Barat
- D.
Timur
- E.
Atas
Correct Answer
D. TimurExplanation
When a current flows through a wire, it creates a magnetic field around the wire. According to the right-hand rule, if you point your thumb in the direction of the current (from North to South in this case), then the fingers of your right hand will curl in the direction of the magnetic field. In this scenario, if the current is flowing from North to South, the magnetic field will be directed towards the East, which is the direction of "Timur" in Indonesian.Rate this question:
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- 5.
Suatu kawat melingkar seperti ditunjukkan pada gambar. Besar induksi magnetic di titik O adalah . . . .
- A.
π.10–7 wb/m2
- B.
2π.10–7 wb/m2
- C.
3π.10–7 wb/m2
- D.
4π.10–7 wb/m2
- E.
5π.10–7 wb/m2
Correct Answer
E. 5π.10–7 wb/m2Explanation
The correct answer is 5π.10–7 wb/m2. This is because the magnitude of the magnetic field produced by a current-carrying wire in a circular loop is given by B = μ0I/2r, where μ0 is the permeability of free space, I is the current flowing through the wire, and r is the radius of the loop. In this case, the magnitude of the magnetic field at point O is given by B = μ0I/2r = (4π.10–7)(I)/(2r) = 2π.10–7 wb/m2. Since the question asks for the magnitude of the magnetic field, the correct answer is 2π.10–7 wb/m2.Rate this question:
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- 6.
The magnitude of magnetic induction at point P on the figure below is . . . .
- A.
![Quiz Induksi Magnetik - Quiz]()
- B.
![Quiz Induksi Magnetik - Quiz]()
- C.
![Quiz Induksi Magnetik - Quiz]()
- D.
![Quiz Induksi Magnetik - Quiz]()
- E.
![Quiz Induksi Magnetik - Quiz]()
Correct Answer
A. -
- 7.
Suatu solenoida yang panjangnya 2 meter memiliki 800 lilitan dan jari-jari 2 cm. Solenoida itu dialiri arus listrik sebesar 0,5 A. Induksi magnetik pada ujung solenoida adalah . . . .
- A.
8π.10–7 wb/m2
- B.
4π.10–5 wb/m2
- C.
8π.10–5 wb/m2
- D.
4π.10–6 wb/m2
- E.
4π.10–4 wb/m2
Correct Answer
B. 4π.10–5 wb/m2Explanation
The correct answer is 4π.10–5 wb/m2. The magnetic field inside a solenoid can be calculated using the formula B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space (8π.10–7 wb/Am), n is the number of turns per unit length, and I is the current. In this case, the length of the solenoid is not given, so we assume it is long enough to be considered infinite. Therefore, the magnetic field at the end of the solenoid is the same as the magnetic field inside the solenoid, which is 4π.10–5 wb/m2.Rate this question:
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- 8.
Suatu toroida berjari-jari 5 cm terdiri dari 750 lilitan. Arus yang mengalir pada toroida agar induksi magnetic yang terjadi di dalam toroida 1,8 x10–3 T adalah . . . .
- A.
0,3 Ampere
- B.
0,6 Ampere
- C.
1 Ampere
- D.
1,8 Ampere
- E.
2,5 Ampere
Correct Answer
B. 0,6 AmpereExplanation
The formula to calculate the magnetic field inside a toroid is B = (μ₀ * N * I) / (2π * r), where B is the magnetic field, μ₀ is the permeability of free space, N is the number of turns, I is the current, and r is the radius of the toroid. Given that the radius is 5 cm and the magnetic field is 1.8 x 10⁻³ T, we can rearrange the formula to solve for I. Plugging in the known values, we get (1.8 x 10⁻³ T) = (4π * 10⁻⁷ Tm/A * 750 * I) / (2π * 0.05 m). Simplifying this equation, we find that I ≈ 0.6 Ampere. Therefore, the correct answer is 0.6 Ampere.Rate this question:
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- 9.
Pada dua buah kawat sejajar yang masing-masing dialiri arus listrik yang sama besar, timbul gaya yang besarnya 2.10–7 N/m. Jarak antara kedua kawat itu 1 meter. Besar arus dalam setiap kawat adalah . . . .
- A.
1/8 Ampere
- B.
1/4 Ampere
- C.
1/2 Ampere
- D.
1 Ampere
- E.
2 Ampere
Correct Answer
D. 1 AmpereExplanation
The force between two parallel wires carrying the same current is given by the equation F = (μ0 * I1 * I2 * L) / (2 * π * d), where F is the force, μ0 is the permeability of free space, I1 and I2 are the currents in the wires, L is the length of the wires, and d is the distance between the wires. In this case, the force is given as 2.10-7 N/m, the distance is 1 meter, and the currents in both wires are the same. By rearranging the equation and substituting the given values, we can solve for the current, which is 1 Ampere.Rate this question:
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- 10.
If electric current I in the direction x+, the direction of B to z+, then the Lorentz force in direction . . . .
- A.
Z -
- B.
Z +
- C.
Y -
- D.
Y +
- E.
X -
Correct Answer
C. Y -Explanation
If the electric current is flowing in the positive x direction and the magnetic field is pointing in the positive z direction, the Lorentz force will be in the negative y direction. This can be determined using the right-hand rule, where the thumb represents the direction of the current, the index finger points in the direction of the magnetic field, and the middle finger indicates the direction of the force. In this case, the thumb points in the positive x direction, the index finger points in the positive z direction, and the middle finger points in the negative y direction.Rate this question:
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- 11.
Suatu partikel bermuatan 0,04 C bergerak sejajar dengan kawat berarus listrik 10 A. Jika jarak partikel ke kawat 5 cm, laju partikel 5 m/s, maka gaya yang dialami partikel adalah . . . .
- A.
0 N
![Quiz Induksi Magnetik - Quiz]()
- B.
2 N
![Quiz Induksi Magnetik - Quiz]()
- C.
4 N
![Quiz Induksi Magnetik - Quiz]()
- D.
6 N
![Quiz Induksi Magnetik - Quiz]()
- E.
8 N
![Quiz Induksi Magnetik - Quiz]()
Correct Answer
E. 8 NExplanation
The force experienced by a charged particle moving parallel to a current-carrying wire can be calculated using the formula F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire. In this case, the particle is moving parallel to the wire, so the force is given by F = BIL. Given that the current is 10 A, the distance from the particle to the wire is 5 cm, and the velocity of the particle is 5 m/s, we can calculate the magnetic field strength using B = μ₀I/2πd, where μ₀ is the permeability of free space and d is the distance from the wire. Plugging in the values, we find that B = 2 x 10^-5 T. Finally, we can calculate the force using F = BIL, which gives us F = 8 N.Rate this question:
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- 12.
Bahan-bahan berikut ini yang termasuk bahan paramagnetic adalah . . . .
- A.
Besi
- B.
Bismuth
- C.
Platina
- D.
Ferrit
- E.
Cobalt
Correct Answer
C. PlatinaExplanation
Platina is the correct answer because it is a paramagnetic material. Paramagnetic materials are those that have unpaired electrons in their atomic or molecular orbitals, which causes them to be weakly attracted to a magnetic field. Iron, cobalt, and nickel are also examples of paramagnetic materials. Bismuth and ferrite, on the other hand, are diamagnetic materials, which are weakly repelled by a magnetic field.Rate this question:
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- 13.
Jika suatu muatan yang bergerak sejajar terhadap medan magnetic, maka lintasan muatan tersebut akan berupa . . . .
- A.
Garis lurus
- B.
Lingkaran
- C.
Tidak beraturan
- D.
Parabola
- E.
Spiral
Correct Answer
A. Garis lurusExplanation
When a charged particle moves parallel to a magnetic field, it experiences a force perpendicular to both its velocity and the magnetic field direction. This force causes the charged particle to move in a curved path. However, if the charged particle's initial velocity is parallel to the magnetic field, the force acting on it becomes zero. As a result, the charged particle will continue to move in a straight line, unaffected by the magnetic field. Therefore, the correct answer is "garis lurus" which means "straight line" in English.Rate this question:
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- 14.
Dua buah partikel massanya m1 : m2 = 2 : 1 dan muatannya q1 : q2 = 2 : 1. Kedua partikel itu bergerak melingkar dalam bidang tegak lurus medan magnetic homogen, maka nilai perbandingan r1 : r2 adalah . . . .
- A.
4 : 1
- B.
2 : 1
- C.
1 : 1
- D.
1 : 2
- E.
1 : 4
Correct Answer
C. 1 : 1Explanation
The correct answer is 1 : 1 because the ratio of the masses (m1 : m2 = 2 : 1) and the ratio of the charges (q1 : q2 = 2 : 1) are both equal. This implies that the centripetal force acting on both particles is the same, resulting in equal radii of their circular motion.Rate this question:
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- 15.
Produk teknologi berikut ini yang menggunakan aplikasi dari elektromagnetic adalah . . . . 1. Galvanometer 3. Pengeras suara 2. Motor listrik 4. Kompas Pernyataan yang benar adalah pernyataan noomor . . . .
- A.
1, 2, dan 3
- B.
1 dan 3
- C.
2 dan 4
- D.
4 saja
- E.
Semuanya
Correct Answer
A. 1, 2, dan 3Explanation
The correct answer is 1, 2, and 3. Galvanometer, motor listrik, dan pengeras suara menggunakan aplikasi dari elektromagnetik.Rate this question:
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.jpg "The magnitude of magnetic induction at point P on the figure below is . . . .")
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Mar 21, 2023Quiz Edited by
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Nov 08, 2012Quiz Created by
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