Soal On Line Fisika Kelas Xii Semester I ( Gelombang Berjalan )

The given question asks for the difference in phase between two waves with a wavelength difference of 10 cm and a wavelength of 50 cm. The phase difference between two waves can be calculated using the formula: phase difference = (wavelength difference / wavelength) * 2π. Plugging in the values, we get (10 cm / 50 cm) * 2π = 1/5. Therefore, the correct answer is 1/5.

The correct answer is B. Sinus. This is because in wave equations, sinus functions are commonly used to describe the oscillatory behavior of waves. The sine function represents a smooth, periodic oscillation that is commonly observed in wave phenomena. It is a fundamental function in trigonometry and is used to describe various waveforms such as sound waves, electromagnetic waves, and water waves. Therefore, the correct answer for the given question is B. Sinus.

Amplitudo adalah simpangan maksimum dalam sebuah gelombang berjalan. Simpangan maksimum ini menggambarkan jarak maksimum partikel dalam gelombang bergerak dari posisi keseimbangan. Dalam hal ini, simpangan maksimum mengacu pada jarak maksimum yang dicapai oleh partikel dalam gelombang saat bergerak. Frekuensi, periode, dan kecepatan sudut adalah konsep-konsep yang berbeda dalam gelombang dan tidak mencerminkan simpangan maksimum.

The given equation for a traveling wave is Y = 0.5 Sin 2 (4t - 8phi.x) meter. To find the period of the wave, we need to determine the value of phi. In the equation, the coefficient of x is -8phi. Comparing this with the standard equation for a wave y = A Sin (kx - wt), we can see that the coefficient of x is related to the wave number k by the equation k = 8phi. The period of the wave is given by the formula T = 2pi/k. Substituting the value of k, we get T = 2pi/(8phi). Simplifying this expression, we find T = 1/(4phi). Therefore, the period of the wave is 1/4 phi.

The given question is asking for the angular velocity of a wave with a period of 5 seconds. The angular velocity is calculated by dividing 2π (phi) by the period. In this case, 2π divided by 5 seconds is equal to 0.4π rad/sec. Therefore, the correct answer is 0.4 phi rad/sec.

The given equation represents a wave with a sinusoidal form. In the equation, the coefficient in front of the x term (2phi) represents the angular wave number, which is related to the spatial frequency of the wave. The angular wave number is equal to 2π times the number of wavelengths per unit distance. Therefore, the correct answer is 4phi, which represents a wave with a spatial frequency of 4 wavelengths per unit distance.

The given question is asking for the wave number of a traveling wave with a wavelength of 2π meters. The wave number is defined as the number of waves per unit distance. Since the wavelength is given as 2π meters, which is the full wavelength of one wave, the wave number would be 1 per meter.

The given equation for a traveling wave is Y = 8 Sin (3phi.t + 5 phi.x) cm. In this equation, the term 3phi.t represents the phase of the wave in the time direction, while the term 5phi.x represents the phase of the wave in the spatial direction. Since the coefficient of x is positive (5phi), it indicates that the wave is propagating in the negative x-direction or to the left. Therefore, the correct answer is "ke kiri" which means "to the left" in English.

The given equation for the wave is Y = 8 Sin (3phi.t - 5 phi.x) cm. The wave equation is in the form Y = A Sin (kx - wt), where A is the amplitude, k is the wave number, x is the position, w is the angular frequency, and t is the time. Comparing the given equation with the standard form, we can see that the wave number is 5 phi /cm.

The given equation of the wave is Y = -8 Sin (3phi.t - 5phi.x) cm. The negative sign in front of the Sin function indicates that the wave is moving downwards. Therefore, the initial direction of vibration of the wave is downwards.