PERSAMAAN GARIS LURUS (kls.8)

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| By AndreasRusdiTure

AndreasRusdiTure

Community Contributor

Quizzes Created: 6 | Total Attempts: 24,211

Pertanyaan: 7 | Attempts: 2,118 | Updated: Mar 21, 2023

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Questions and Answers

1.

Persamaan garis yang tegak lurus terhadap sumbu x adalah ... .
- A.
  
  X = y
- B.
  
  Y = 0
- C.
  
  X - 3 = 0
- D.
  
  Y - 2x = 0
Correct Answer
C. X - 3 = 0

Explanation
The equation x - 3 = 0 represents a line that is perpendicular to the x-axis. This is because the equation is in the form of x = constant, which means that the line is parallel to the y-axis. Since the y-axis is perpendicular to the x-axis, any line parallel to the y-axis will be perpendicular to the x-axis. Therefore, the equation x - 3 = 0 represents a line that is perpendicular to the x-axis.

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2.

Gradien garis 3x + 5y - 6 = 0 adalah ... .
- A.
- B.
- C.
- D.
Correct Answer
C.

Explanation
The gradient of the line 3x + 5y - 6 = 0 is -3/5.

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3.

Gradien garis yang sejajar dengan garis 2x + 6y + 8 = 0 adalah ... .
- A.
- B.
- C.
- D.
Correct Answer
C.

Explanation
Garis yang sejajar dengan garis 2x + 6y + 8 = 0 akan memiliki gradien yang sama. Dalam persamaan garis umum Ax + By + C = 0, gradien garis dapat ditemukan dengan membagi koefisien x dengan koefisien y, yaitu -A/B. Dalam hal ini, gradien garis sejajar dengan 2x + 6y + 8 = 0 adalah -2/6 atau -1/3.

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4.

Gradien garis yang melalui titik (2, 1) dan (4,7) adalah ... .
- A.
- B.
- C.
  
  2
- D.
  
  3
Correct Answer
D. 3

Explanation
The gradient of a line is calculated by finding the change in y-coordinates divided by the change in x-coordinates between two points on the line. In this case, the change in y-coordinates is 7 - 1 = 6, and the change in x-coordinates is 4 - 2 = 2. Therefore, the gradient is 6/2 = 3.

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5.

Garis p tegak lurus terhadap garis h yang mempunyai persamaan 3x + 6y + 5 = 0. Gradien garis p adalah ... .
- A.
  
  -2
- B.
- C.
- D.
  
  2
Correct Answer
D. 2

Explanation
The gradient of a line perpendicular to another line is the negative reciprocal of the gradient of that line. The given line has the equation 3x + 6y + 5 = 0. To find the gradient of this line, we can rearrange the equation into the slope-intercept form y = mx + c, where m is the gradient. By rearranging the equation, we get y = (-1/2)x - 5/6. Therefore, the gradient of the given line is -1/2. The negative reciprocal of -1/2 is 2. Therefore, the gradient of the line p perpendicular to the given line is 2.

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0
6.

Persamaan garis lurus yang melalui titik (2, 1) dan (-2, -7) adalah ... .
- A.
  
  Y = -2x + 5
- B.
  
  Y = 2x - 3
- C.
  
  Y = 3x - 5
- D.
  
  Y = -3x + 7
Correct Answer
B. Y = 2x - 3

Explanation
The equation of a straight line passing through two points (x1, y1) and (x2, y2) can be found using the formula: y - y1 = (y2 - y1) / (x2 - x1) * (x - x1). In this case, the points are (2, 1) and (-2, -7). Plugging in these values into the formula, we get: y - 1 = (1 - (-7)) / (2 - (-2)) * (x - 2). Simplifying the equation gives us y - 1 = 8/4 * (x - 2), which further simplifies to y - 1 = 2(x - 2). Rearranging the equation gives us y = 2x - 3, which matches the given answer.

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7.

Persamaan garis yang sejajar dengan garis yang melalui titik-titik (-3, 4) dan (2, -1) adalah ... .
- A.
  
  2x + y = 4
- B.
  
  X - y = 4
- C.
  
  X + y = 4
- D.
  
  -x - y = 4
Correct Answer
B. X - y = 4

Explanation
The equation of a line parallel to a given line will have the same slope. The slope of the line passing through the points (-3, 4) and (2, -1) can be found using the formula (y2 - y1) / (x2 - x1). Plugging in the values, we get (-1 - 4) / (2 - (-3)) = -5 / 5 = -1. Therefore, the slope of the line is -1. The equation x - y = 4 has a slope of 1, which is the negative reciprocal of -1. So, this equation represents a line parallel to the line passing through the given points.

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