Quiz Induksi Magnetik

Pernyataan nomor 1, 2, dan 3 benar tentang medan magnet, magnet batang. Pernyataan nomor 1 menyatakan bahwa medan magnet keluar dari kutub utara, yang sesuai dengan sifat kutub utara magnet. Pernyataan nomor 2 menyatakan bahwa ada tolak menolak antara kutub yang sejenis, yang berarti kutub utara magnet akan tolak menolak dengan kutub utara magnet lainnya. Pernyataan nomor 3 menyatakan bahwa medan magnet masuk ke kutub selatan, yang sesuai dengan sifat kutub selatan magnet. Oleh karena itu, jawaban yang benar adalah 1, 2, dan 3.

Platina is the correct answer because it is a paramagnetic material. Paramagnetic materials are those that have unpaired electrons in their atomic or molecular orbitals, which causes them to be weakly attracted to a magnetic field. Iron, cobalt, and nickel are also examples of paramagnetic materials. Bismuth and ferrite, on the other hand, are diamagnetic materials, which are weakly repelled by a magnetic field.

When a charged particle moves parallel to a magnetic field, it experiences a force perpendicular to both its velocity and the magnetic field direction. This force causes the charged particle to move in a curved path. However, if the charged particle's initial velocity is parallel to the magnetic field, the force acting on it becomes zero. As a result, the charged particle will continue to move in a straight line, unaffected by the magnetic field. Therefore, the correct answer is "garis lurus" which means "straight line" in English.

The correct answer is 1, 2, and 3. Galvanometer, motor listrik, dan pengeras suara menggunakan aplikasi dari elektromagnetik.

The correct answer is "Kutub Utara Magnet bumi". The explanation for this answer is that the south pole of a compass needle is attracted to the north magnetic pole of the Earth's magnetic field. This means that the south pole of the compass needle points towards the Earth's magnetic north pole, which is located near the geographic North Pole. Therefore, the compass needle points in the direction of the Earth's magnetic north pole, which is the correct answer.

The correct answer is 1 Ampere because the question states that the distance between point P and the long conductor is 10 cm, and the magnetic field at point P is given as 2 x 10^-6 T. The magnetic field at a distance r from a long conductor carrying current I is given by B = (μ0 * I) / (2πr), where μ0 is the permeability of free space. Plugging in the given values, we can solve for I and find that it is equal to 1 Ampere.

When a current flows through a wire, it creates a magnetic field around the wire. According to the right-hand rule, if you point your thumb in the direction of the current (from North to South in this case), then the fingers of your right hand will curl in the direction of the magnetic field. In this scenario, if the current is flowing from North to South, the magnetic field will be directed towards the East, which is the direction of "Timur" in Indonesian.

The force between two parallel wires carrying the same current is given by the equation F = (μ0 * I1 * I2 * L) / (2 * π * d), where F is the force, μ0 is the permeability of free space, I1 and I2 are the currents in the wires, L is the length of the wires, and d is the distance between the wires. In this case, the force is given as 2.10-7 N/m, the distance is 1 meter, and the currents in both wires are the same. By rearranging the equation and substituting the given values, we can solve for the current, which is 1 Ampere.

If the electric current is flowing in the positive x direction and the magnetic field is pointing in the positive z direction, the Lorentz force will be in the negative y direction. This can be determined using the right-hand rule, where the thumb represents the direction of the current, the index finger points in the direction of the magnetic field, and the middle finger indicates the direction of the force. In this case, the thumb points in the positive x direction, the index finger points in the positive z direction, and the middle finger points in the negative y direction.

The correct answer is 1 : 1 because the ratio of the masses (m1 : m2 = 2 : 1) and the ratio of the charges (q1 : q2 = 2 : 1) are both equal. This implies that the centripetal force acting on both particles is the same, resulting in equal radii of their circular motion.

The correct answer is 4π.10–5 wb/m2. The magnetic field inside a solenoid can be calculated using the formula B = μ₀nI, where B is the magnetic field, μ₀ is the permeability of free space (8π.10–7 wb/Am), n is the number of turns per unit length, and I is the current. In this case, the length of the solenoid is not given, so we assume it is long enough to be considered infinite. Therefore, the magnetic field at the end of the solenoid is the same as the magnetic field inside the solenoid, which is 4π.10–5 wb/m2.

The force experienced by a charged particle moving parallel to a current-carrying wire can be calculated using the formula F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire. In this case, the particle is moving parallel to the wire, so the force is given by F = BIL. Given that the current is 10 A, the distance from the particle to the wire is 5 cm, and the velocity of the particle is 5 m/s, we can calculate the magnetic field strength using B = μ₀I/2πd, where μ₀ is the permeability of free space and d is the distance from the wire. Plugging in the values, we find that B = 2 x 10^-5 T. Finally, we can calculate the force using F = BIL, which gives us F = 8 N.

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The correct answer is 5π.10–7 wb/m2. This is because the magnitude of the magnetic field produced by a current-carrying wire in a circular loop is given by B = μ0I/2r, where μ0 is the permeability of free space, I is the current flowing through the wire, and r is the radius of the loop. In this case, the magnitude of the magnetic field at point O is given by B = μ0I/2r = (4π.10–7)(I)/(2r) = 2π.10–7 wb/m2. Since the question asks for the magnitude of the magnetic field, the correct answer is 2π.10–7 wb/m2.

The formula to calculate the magnetic field inside a toroid is B = (μ₀ * N * I) / (2π * r), where B is the magnetic field, μ₀ is the permeability of free space, N is the number of turns, I is the current, and r is the radius of the toroid. Given that the radius is 5 cm and the magnetic field is 1.8 x 10⁻³ T, we can rearrange the formula to solve for I. Plugging in the known values, we get (1.8 x 10⁻³ T) = (4π * 10⁻⁷ Tm/A * 750 * I) / (2π * 0.05 m). Simplifying this equation, we find that I ≈ 0.6 Ampere. Therefore, the correct answer is 0.6 Ampere.