Describe the graph of f(x) = log x changed to f(x) = 3log(x + 1) - 5.

vertical stretch by 3 and shift left 1 and 5 units down

vertical stretch by 3 and shift right 1 and 5 units down

vertical compress by 3 and shift left 1 and 5 units down

Graphing logarithmic functions Quiz

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Graphing Logarithmic Functions Quiz - Quiz

Are you good at graphing logarithmic functions? Take this quiz, and see how much you know about the graphs of logarithmic functions. We have covered the basics here, making it easier for you to practice the basics of logarithmic functions on graphs. You should give this quiz a try to analyze yourself in this module of math and functions. See if you can get a perfect score on this quiz. All the best! Do not forget to share your quiz result with others.

Questions and Answers

1.

Find the domain (all possible inputs) of -ln(x-2)+3
- A.
  
  (2,∞)
- B.
  
  (-∞,2)
- C.
  
  (-∞,3)
- D.
  
  All real numbers
Correct Answer
A. (2,∞)

Explanation
The given expression is -ln(x-2)+3. Since the natural logarithm is only defined for positive numbers, the expression inside the logarithm, (x-2), must be greater than 0. Solving for x, we find that x must be greater than 2. Therefore, the domain of the expression is (2, infinity).

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2.

Find the Range (all possible outputs) of -ln(x-2)+3
- A.
  
  (-∞,2)
- B.
  
  All real
- C.
  
  (-∞,3)
- D.
  
  (2,∞)
Correct Answer
B. All real

Explanation
The given function is -ln(x-2)+3. The natural logarithm function ln(x) is defined for all positive real numbers. In this case, the function is -ln(x-2), which means that the argument (x-2) must be positive. Since there are no restrictions on the value of x in the given options, the range of the function is all real numbers.

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3.

Describe the graph of f(x) = log x changed to f(x) = 3log(x + 1) - 5.
- A.
  
  Vertical stretch by 3 and shift right 1 and 5 units down
- B.
  
  Vertical stretch by 3 and shift left 1 and 5 units down
- C.
  
  Vertical stretch by 3 and shift right 1 and 5 units down
- D.
  
  Vertical compress by 3 and shift left 1 and 5 units down
Correct Answer
B. Vertical stretch by 3 and shift left 1 and 5 units down

Explanation
The graph of the function f(x) = log x is vertically stretched by a factor of 3, meaning that the y-values are multiplied by 3. Additionally, the graph is shifted 1 unit to the left, meaning that all x-values are decreased by 1. Finally, the graph is shifted 5 units down, meaning that all y-values are decreased by 5.

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4.

What is the asymptote of y = log₂x - 3?
- A.
  
  X = 0
- B.
  
  Y = -3
- C.
  
  Y = 0
- D.
  
  X = -3
Correct Answer
A. X = 0

Explanation
The asymptote of the given equation y = log2x - 3 is x = 0. This means that as x approaches 0, the value of y approaches negative infinity. The logarithmic function has a vertical asymptote at x = 0, which means that the graph of the equation will approach but never touch this vertical line.

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5.

Select all the transformations that apply here. y = log ₆ (x - 1) - 5
- A.
  
  Horizontal shift right 1
- B.
  
  Horizontal shift left 1
- C.
  
  Vertical shift down 5
- D.
  
  Vertical shift up 5
Correct Answer(s)
A. Horizontal shift right 1
C. Vertical shift down 5

Explanation
The given equation is y = log 6 (x - 1) - 5. The term (x - 1) inside the logarithm function indicates a horizontal shift right 1 unit, as it shifts the entire graph of the function 1 unit to the right. The term -5 at the end of the equation indicates a vertical shift down 5 units, as it shifts the entire graph of the function 5 units downwards. Therefore, the correct transformations that apply here are a horizontal shift right 1 and a vertical shift down 5.

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6.

Select all the transformations that apply here. y = log ₅(x + 1) +1
- A.
  
  Horizontal shift right 1
- B.
  
  Horizontal shift left 1
- C.
  
  Vertical shift up 1
- D.
  
  Vertical shift down 1
Correct Answer(s)
B. Horizontal shift left 1
C. Vertical shift up 1

Explanation
The given equation is y = log 5 (x + 1) + 1. The term (x + 1) inside the logarithm function indicates a horizontal shift to the left by 1 unit. This means that the graph of the equation will be shifted to the left by 1 unit compared to the standard logarithmic function. Additionally, the term +1 outside the logarithm function indicates a vertical shift upward by 1 unit. This means that the graph of the equation will be shifted upward by 1 unit compared to the standard logarithmic function. Therefore, the correct transformations that apply here are a horizontal shift left 1 and a vertical shift up 1.

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7.

Select all the transformations that apply here. y = -2 log _1/2x
- A.
  
  Vertical shrink by 1/2
- B.
  
  Reflection across the y-axis
- C.
  
  Vertical stretch by 2
- D.
  
  Reflection across the x-axis
Correct Answer(s)
C. Vertical stretch by 2
D. Reflection across the x-axis

Explanation
The given equation is y = -2 log (1/2)x. The coefficient -2 in front of the logarithm function indicates a vertical stretch by a factor of 2. This means that the graph of the equation is stretched vertically, making it appear taller. The negative sign in front of the logarithm function indicates a reflection across the x-axis. This means that the graph is flipped upside down. Therefore, the correct transformations that apply here are a vertical stretch by 2 and a reflection across the x-axis.

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8.

Select all the transformations that apply here. y = 3log ₃ (2x)
- A.
  
  Vertical stretch by 3
- B.
  
  Vertical shrink by 1/3
- C.
  
  Horizontal shrink by 1/2
- D.
  
  Horizontal stretch by 2
Correct Answer(s)
A. Vertical stretch by 3
C. Horizontal shrink by 1/2

Explanation
The given equation is in the form y = 3log3(2x), where the base of the logarithm is 3. This means that there is a vertical stretch by a factor of 3, which is indicated by the coefficient in front of the logarithm. Additionally, there is a horizontal shrink by a factor of 1/2, which is indicated by the coefficient in front of the x. Therefore, the correct transformations that apply here are a vertical stretch by 3 and a horizontal shrink by 1/2.

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9.

Logarithmic functions are the inverse of
- A.
  
  Linear Functions
- B.
  
  Polynomial Functions
- C.
  
  Quadratic Functions
- D.
  
  Exponential Functions
Correct Answer
D. Exponential Functions

Explanation
Logarithmic functions are the inverse of exponential functions. This means that if we have an exponential function, we can find its corresponding logarithmic function by switching the roles of the base and the exponent. In other words, if y = a^x is an exponential function, then its inverse logarithmic function is given by x = log_a(y).

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10.

Which of the following functions has a vertical asymptote?
- A.
  
  Logarithm
- B.
  
  Exponential
- C.
  
  Both
- D.
  
  None
Correct Answer
A. Logarithm

Explanation
The logarithm function has a vertical asymptote. This is because as the input approaches negative infinity, the output of the logarithm function approaches negative infinity. Similarly, as the input approaches positive infinity, the output approaches positive infinity. Therefore, the logarithm function has a vertical asymptote at x = 0.

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Current Version
Aug 16, 2023

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Oct 31, 2022

Quiz Created by
Sophia Smith

Graphing logarithmic functions Quiz

Find the domain (all possible inputs) of -ln(x-2)+3

Find the Range (all possible outputs) of -ln(x-2)+3

Describe the graph of f(x) = log x changed to f(x) = 3log(x + 1) - 5.

What is the asymptote of y = log2x - 3?

Select all the transformations that apply here. y = log 6 (x - 1) - 5

Select all the transformations that apply here. y = log 5 (x + 1) +1

Select all the transformations that apply here. y = -2 log 1/2 x

Select all the transformations that apply here. y = 3log 3 (2x)

Logarithmic functions are the inverse of

Which of the following functions has a vertical asymptote?

What is the asymptote of y = log₂x - 3?

Select all the transformations that apply here. y = log ₆ (x - 1) - 5

Select all the transformations that apply here. y = log ₅(x + 1) +1

Select all the transformations that apply here. y = -2 log _1/2x

Select all the transformations that apply here. y = 3log ₃ (2x)