Physics Quiz: Motion With Constant Acceleration

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  • 1/10 Questions

    Rate of change of velocity is called?

    • Speed
    • Acceleration
    • Displacement
    • Momentum
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About This Quiz

Simply stated, acceleration is the ability of an object to gain speed. Play this informative physics quiz on motion with constant acceleration and find out much you know about the topic. This quiz covers numerical equations, basic definitions, concepts, and other factual information regarding motion and acceleration. This quiz will certainly help you gain more knowledge about the topic. The questions are based on easy, medium, and hard levels. Play this quiz and see where you stand. All the best!

Physics Quiz: Motion With Constant Acceleration - Quiz

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  • 2. 

    The quantity which has both direction and magnitude is called?

    • Scalar

    • Vector

    • Both 1 and 2

    • Neither 1 nor 2

    Correct Answer
    A. Vector
    Explanation
    A vector is a quantity that has both direction and magnitude. It represents a physical quantity that requires both a numerical value and a specific direction to fully describe it. Examples of vectors include displacement, velocity, and force. Scalars, on the other hand, only have magnitude and do not have a specific direction associated with them. Examples of scalars include temperature, mass, and time. Therefore, the correct answer is vector.

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  • 3. 

    The SI unit of distance is?

    • Kilometer

    • Meter

    • Newton

    • Second

    Correct Answer
    A. Meter
    Explanation
    The SI unit of distance is meter. The meter is defined as the length of the path traveled by light in a vacuum during a time interval of 1/299,792,458 of a second. It is the most commonly used unit for measuring distances and is widely used in scientific and everyday applications. The kilometer is a larger unit of distance, equal to 1000 meters, while Newton is the unit of force and second is the unit of time.

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  • 4. 

    Shortest possible path followed by an object is called?

    • Distance

    • Displacement

    • Torque

    • Speed

    Correct Answer
    A. Displacement
    Explanation
    Displacement refers to the shortest possible path followed by an object. It is a vector quantity that represents the change in position of an object from its initial point to its final point. Unlike distance, which is a scalar quantity and refers to the total length traveled, displacement takes into account the direction of motion. Therefore, displacement is the correct answer in this case.

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  • 5. 

    Over a span of 25 meters, a bike consistently gains speed from zero to ten meters per second. Calculate the bike's acceleration.

    • 5 m/s2

    • 3.5 m/s2

    • 2 m/s2

    • 4.5 m/s2

    Correct Answer
    A. 2 m/s2
    Explanation
    The bike consistently gains speed from zero to ten meters per second over a span of 25 meters. To calculate the bike's acceleration, we can use the formula for acceleration: acceleration = change in velocity / time. In this case, the change in velocity is 10 m/s (final velocity) - 0 m/s (initial velocity), which is 10 m/s. The time taken to achieve this change in velocity is 25 meters. Therefore, the acceleration is 10 m/s / 25 m = 0.4 m/s2. However, none of the given options match this calculation. Therefore, the correct answer is not available.

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  • 6. 

    From a cliff that is 80.0 meters above the earth, a rock is thrown. What acceleration did the rock experience if it was traveling at 40.0 m/s when it hit the ground?

    • 16.0 m/s2

    • 10.0 m/s2

    • 14.0 m/s2

    • 12.0 m/s2

    Correct Answer
    A. 10.0 m/s2
    Explanation
    The rock experienced an acceleration of 10.0 m/s2. This can be determined using the equation of motion, which states that the final velocity squared is equal to the initial velocity squared plus two times the acceleration times the distance traveled. In this case, the initial velocity is 40.0 m/s, the final velocity is 0 m/s (since the rock hits the ground), and the distance traveled is 80.0 meters (the height of the cliff). By substituting these values into the equation and solving for acceleration, we get an acceleration of 10.0 m/s2.

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  • 7. 

    On a graph of distance vs time, a horizontal line indicates that the object's speed is

    • Increasing

    • Zero

    • Decreasing

    • Remains the same

    Correct Answer
    A. Zero
    Explanation
    A horizontal line on a graph of distance vs time indicates that the object's speed is zero. This means that the object is not moving or its velocity is constant. When the distance does not change over time, it implies that the object is at rest or not in motion. Therefore, the speed of the object is zero.

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  • 8. 

    A plane takes off at a speed of 70.0 m/s and decelerates for 10 seconds at 1.50 m/s2. What is the plane's maximum speed?

    • 35 m/s

    • 45 m/s

    • 55 m/s

    • 50 m/s

    Correct Answer
    A. 55 m/s
    Explanation
    The plane starts with an initial speed of 70.0 m/s and decelerates at a rate of 1.50 m/s^2 for 10 seconds. To find the maximum speed, we need to determine the final velocity after deceleration. Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can calculate the final velocity as follows: v = 70.0 m/s + (-1.50 m/s^2)(10 s) = 70.0 m/s - 15 m/s = 55 m/s. Therefore, the plane's maximum speed is 55 m/s.

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  • 9. 

    With an initial velocity of 4 m/s and constant acceleration, a particle moves along the x-axis. Its speed after three seconds is 14 m/s.  How far did it move in that time frame?

    • 15m

    • 27m

    • 25m

    • 30m

    Correct Answer
    A. 27m
    Explanation
    The particle's initial velocity is 4 m/s and its speed after 3 seconds is 14 m/s. This means that the particle has undergone an acceleration of (14 m/s - 4 m/s) / 3 s = 10 m/s^2. Using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement, we can solve for s. Plugging in the given values, we have (14 m/s)^2 = (4 m/s)^2 + 2(10 m/s^2)s. Simplifying this equation gives us s = 27 m. Therefore, the particle has moved 27 meters in that time frame.

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  • 10. 

    What happens to the velocity of an object in motion with constant acceleration after one second if it starts from rest?  

    • It remains zero.

    • It equals the acceleration.

    • It doubles the acceleration.

    • It is unpredictable without more information.

    Correct Answer
    A. It equals the acceleration.
    Explanation
    In the scenario where an object starts from a complete stop and is subjected to constant acceleration, the velocity of the object at any moment can be calculated by adding the product of acceleration and time to the initial velocity. For example, if the object begins with no initial movement (zero velocity) and accelerates at a constant rate, after one second, its velocity will be equivalent to the acceleration value.
    To illustrate, if an object has an acceleration of 5 meters per second squared, then after one second, its velocity becomes 5 meters per second. This happens because, in each second, the speed increases by the acceleration rate. So, simply put, after one second, the increase in velocity equals the rate of acceleration.

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  • Current Version
  • Sep 17, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Nov 16, 2022
    Quiz Created by
    Amit Mangal
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