If a dielectric is inserted between the parallel plate capacitor. What happens to the capacitance?

It first decreases then increases

What is the relationship between the capacitance of the capacitor and relative permittivity?

They both are inversely proportional

An Interesting Quiz On Calculating Total Capacitance

Created by ProProfs Editorial Team

The editorial team at ProProfs Quizzes consists of a select group of subject experts, trivia writers, and quiz masters who have authored over 10,000 quizzes taken by more than 100 million users. This team includes our in-house seasoned quiz moderators and subject matter experts. Our editorial experts, spread across the world, are rigorously trained using our comprehensive guidelines to ensure that you receive the highest quality quizzes.

Learn about Our Editorial Process

| By Tanya Mishra

Tanya Mishra

Community Contributor

Quizzes Created: 606 | Total Attempts: 1,453,991

Questions: 10 | Attempts: 104 | Updated: Aug 16, 2023

Questions

Settings

Feedback

During the Quiz End of Quiz

Difficulty

Sequential Easy First Hard First

Play as

Quiz Flashcard

Create your own Quiz

Share on Facebook Share on Twitter Share on Whatsapp Share on Pinterest Share on Email Copy to Clipboard Embed on your website

An Interesting Quiz On Calculating Total Capacitance - Quiz

We welcome you to this interesting quiz on calculating total capacitance. Capacitance is the property of the object or device to store electric charge. It's usually measured change in charge in response to a difference in electric potential. The questions in our quiz will surely make you learn more about the concept in a fun way! Please make sure to read all the questions carefully before answering. We are sure that you'll love the quiz! Hope you have fun! Good Luck!

Questions and Answers

1.

There are 3 capacitors C1, C2, and C3 that are associated with the parallel connection. Which of the following formulas represents the total capacitance of the connection?
- A.
  
  1/C1+1/C2+1/C3
- B.
  
  C1/(C2+C3)
- C.
  
  C1+C2+C3
- D.
  
  C1/(C2-C3)
Correct Answer
C. C1+C2+C3

Explanation
The correct answer is C1+C2+C3. In a parallel connection, the total capacitance is equal to the sum of the individual capacitances. Therefore, the total capacitance of the connection is given by the formula C1+C2+C3.

Rate this question:
2.

A capacitor is connected to a battery. What happens to the force of attraction between the plates when the separation between them is halved?
- A.
  
  It becomes half
- B.
  
  It becomes four times
- C.
  
  It doubles
- D.
  
  There is no change
Correct Answer
B. It becomes four times

Explanation
When the separation between the plates of a capacitor is halved, the capacitance (C) of the capacitor increases by a factor of four according to the formula C = εA/d, where ε is the permittivity of the material between the plates, A is the area of the plates, and d is the separation between them. As the capacitance increases, the force of attraction between the plates (F) also increases, since F is directly proportional to the capacitance. Therefore, the force of attraction between the plates becomes four times stronger when the separation between them is halved.

Rate this question:
3.

If a dielectric is inserted between the parallel plate capacitor. What happens to the capacitance?
- A.
  
  It increases
- B.
  
  It decreases
- C.
  
  It remains the same throughout
- D.
  
  It first decreases then increases
Correct Answer
A. It increases

Explanation
When a dielectric is inserted between the plates of a parallel plate capacitor, the capacitance increases. This is because the dielectric material reduces the electric field between the plates, allowing more charge to be stored for a given potential difference. The presence of the dielectric increases the capacitance by a factor equal to the dielectric constant of the material. Therefore, the capacitance increases when a dielectric is inserted between the parallel plate capacitor.

Rate this question:
4.

A capacitor has a capacitance of about 5 microfarads. If a DC current of 100V is applied to it, what is the stored energy of the capacitor?
- A.
  
  100 Joules
- B.
  
  50/100 Joules
- C.
  
  2.5/100 Joules
- D.
  
  35/50 Joules
Correct Answer
C. 2.5/100 Joules

Explanation
The stored energy of a capacitor can be calculated using the formula: E = 1/2 * C * V^2, where E is the energy, C is the capacitance, and V is the voltage. In this case, the capacitance is given as 5 microfarads (5 * 10^-6 F) and the voltage is 100V. Plugging these values into the formula, we get: E = 1/2 * 5 * 10^-6 * 100^2 = 2.5/100 Joules. Therefore, the stored energy of the capacitor is 2.5/100 Joules.

Rate this question:
5.

Which of the following does not affect the capacitance of the capacitor?
- A.
  
  The nature of dielectric
- B.
  
  The thickness of the plate
- C.
  
  The plate area
- D.
  
  The plate separation
Correct Answer
B. The thickness of the plate

Explanation
The thickness of the plate does not affect the capacitance of the capacitor because capacitance is determined by the area of the plates, the separation between them, and the permittivity of the dielectric material. The thickness of the plate does not play a role in determining the capacitance value.

Rate this question:
6.

Three capacitors of the capacitance of 4F are arranged in parallel. Can you calculate the total capacitance of the circuit?
- A.
  
  12F
- B.
  
  20F
- C.
  
  30F
- D.
  
  100F
Correct Answer
A. 12F

Explanation
When capacitors are arranged in parallel, the total capacitance is equal to the sum of the individual capacitances. In this case, since the three capacitors have a capacitance of 4F each, the total capacitance would be 4F + 4F + 4F = 12F. Therefore, the correct answer is 12F.

Rate this question:
7.

The capacitance of two capacitors is 2f, they are connected in series. What is the total capacitance of the connection?
- A.
  
  4F
- B.
  
  2F
- C.
  
  1/4F
- D.
  
  1F
Correct Answer
D. 1F

Explanation
When capacitors are connected in series, the total capacitance is given by the reciprocal of the sum of the reciprocals of the individual capacitances. In this case, since the capacitance of both capacitors is 2F, the reciprocal of the sum of the reciprocals is 1/2F + 1/2F = 1F. Therefore, the total capacitance of the connection is 1F.

Rate this question:

1
0
8.

A capacitor with capacitance C is charged with a potential difference of ∆V. The capacitor has the energy U. Now, the potential difference and capacitance are doubled in the circuit. What happens to the stored energy now?
- A.
  
  1/2 U
- B.
  
  2U
- C.
  
  8U
- D.
  
  16U
Correct Answer
C. 8U

Explanation
When the potential difference and capacitance of a capacitor are doubled, the stored energy in the capacitor increases by a factor of 8. This can be explained by the formula for the energy stored in a capacitor, which is given by U = (1/2) * C * ∆V^2. When both C and ∆V are doubled, the energy becomes U' = (1/2) * (2C) * (2∆V)^2 = 8 * (1/2) * C * ∆V^2 = 8U. Therefore, the stored energy in the capacitor is now 8 times the original energy.

Rate this question:
9.

What is the relationship between the capacitance of the capacitor and relative permittivity?
- A.
  
  They both are inversely proportional
- B.
  
  They don't have any relation
- C.
  
  They are directly proportional
- D.
  
  None of the above
Correct Answer
C. They are directly proportional

Explanation
The relationship between the capacitance of the capacitor and relative permittivity is that they are directly proportional. This means that as the relative permittivity of the material between the capacitor plates increases, the capacitance also increases. Conversely, if the relative permittivity decreases, the capacitance decreases as well. This relationship is described by the equation C = ε₀εᵣA/d, where C is the capacitance, ε₀ is the permittivity of free space, εᵣ is the relative permittivity, A is the area of the capacitor plates, and d is the distance between the plates.

Rate this question:
10.

The capacitance of a capacitor opposes the sudden change in what?
- A.
  
  Temperature
- B.
  
  Voltage
- C.
  
  Current
- D.
  
  Energy
Correct Answer
B. Voltage

Explanation
The capacitance of a capacitor opposes the sudden change in voltage. Capacitance is a measure of a capacitor's ability to store charge, and it is directly related to the amount of charge that can be stored per unit of voltage. When the voltage across a capacitor changes suddenly, the capacitance resists this change by either absorbing or releasing charge, thereby maintaining a more constant voltage. This property makes capacitors useful in smoothing out voltage fluctuations and stabilizing electrical circuits.

Rate this question:

Quiz Review Timeline +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

Current Version
Aug 16, 2023

Quiz Edited by
ProProfs Editorial Team
Nov 18, 2022

Quiz Created by
Tanya Mishra

An Interesting Quiz On Calculating Total Capacitance

There are 3 capacitors C1, C2, and C3 that are associated with the parallel connection. Which of the following formulas represents the total capacitance of the connection?

A capacitor is connected to a battery. What happens to the force of attraction between the plates when the separation between them is halved?

If a dielectric is inserted between the parallel plate capacitor. What happens to the capacitance?

A capacitor has a capacitance of about 5 microfarads. If a DC current of 100V is applied to it, what is the stored energy of the capacitor?

Which of the following does not affect the capacitance of the capacitor?

Three capacitors of the capacitance of 4F are arranged in parallel. Can you calculate the total capacitance of the circuit?

The capacitance of two capacitors is 2f, they are connected in series. What is the total capacitance of the connection?

A capacitor with capacitance C is charged with a potential difference of ∆V. The capacitor has the energy U. Now, the potential difference and capacitance are doubled in the circuit. What happens to the stored energy now?

What is the relationship between the capacitance of the capacitor and relative permittivity?

The capacitance of a capacitor opposes the sudden change in what?