GSM And CDMA: Radio Networks Design! Trivia Knowledge Quiz
Below is a Gsm And Cdma: Radio Networks Design trivia quiz that is designed to see just how attentive you have been in class with regards to this topic. It covers some of the basic facts you should know before this week’s exam. Do give it a try and keep a lookout for other quizzes just like it. All the best!
- 1.
Regarding transmission diversity technique, which 3 statements are correct ?
- A.
WCDMA & CDMA fast power control provides provides a diversity gain .
- B.
Cross polar antennas are necessary for Tx/Rx diversity to work .
- C.
Wide transmission can provide a diversity gain .
- D.
Interleaving of data bits can provide a diversity gain .
- E.
Soft HO can results in a macro-diversity gain .
Correct Answer(s)
B. Cross polar antennas are necessary for Tx/Rx diversity to work .
D. Interleaving of data bits can provide a diversity gain .
E. Soft HO can results in a macro-diversity gain .Explanation
Cross polar antennas are necessary for Tx/Rx diversity to work because they allow for the transmission and reception of signals in different polarizations, which helps reduce interference and improve signal quality. Interleaving of data bits can provide a diversity gain because it spreads the data across multiple subchannels, increasing the chances of successful transmission even in the presence of fading or interference. Soft HO can result in a macro-diversity gain because it allows for seamless handover between different base stations, improving signal strength and reducing the chances of call drops.Rate this question:
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- 2.
What are 2 characteristics about multipath reflections in WCDMA & CDMA2000 systems? (choose two)
- A.
Increases thermal noise at base station receiver .
- B.
Provide additional diversity .
- C.
Causes fast fadding of received signal .
- D.
Requires additional channel elements .
Correct Answer(s)
B. Provide additional diversity .
C. Causes fast fadding of received signal .Explanation
Multipath reflections in WCDMA and CDMA2000 systems have two characteristics. Firstly, they provide additional diversity, which means that the multiple reflected signals can be combined to improve the overall signal quality and reliability. Secondly, these reflections cause fast fading of the received signal, as the multiple paths can result in constructive or destructive interference, leading to rapid fluctuations in signal strength.Rate this question:
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- 3.
Reffering to the exibhits, what are 2 results of downtilting a directional antenna using machanical tilt? (choose 2)
- A.
Backlobe (Lobe C) is uptilted .
- B.
Backlobe (Lobe C) is downtilted .
- C.
Sidelobes (Lobe B) are downtilted .
- D.
Sidelobes (Lobe B) are maintained.
Correct Answer(s)
A. Backlobe (Lobe C) is uptilted .
D. Sidelobes (Lobe B) are maintained. -
- 4.
A base station has a radiated power of 100 W .What are the 2 equivalent powers expressed in dB units ? (Choose 2)
- A.
10 dBW
- B.
50 dBm
- C.
20 dBW
- D.
20 dBc
Correct Answer(s)
B. 50 dBm
C. 20 dBWExplanation
The radiated power of the base station is given as 100 W. To convert this power to dB units, we can use the formulas: dBm = 10log10(P/1mW) and dBW = 10log10(P/1W).
Using the first formula, we can calculate the power in dBm: dBm = 10log10(100/1) = 20 dBm.
Using the second formula, we can calculate the power in dBW: dBW = 10log10(100/1) = 20 dBW.
Therefore, the two equivalent powers expressed in dB units are 50 dBm and 20 dBW.Rate this question:
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- 5.
An over shooter is detected within a cluster .Which 2 actions would be taken to reduce the negative effect? (Choose 2)
- A.
Increase the electrical downtilt .
- B.
Decrease the machanical downtilt .
- C.
Change the antenna azimuth .
- D.
Verify base station alarms .
Correct Answer(s)
A. Increase the electrical downtilt .
C. Change the antenna azimuth .Explanation
To reduce the negative effect of an overshooter within a cluster, two actions can be taken. First, increasing the electrical downtilt can help adjust the vertical coverage of the antenna, directing the signal downwards and reducing interference from the overshooter. Second, changing the antenna azimuth can alter the horizontal direction of the antenna's main lobe, further minimizing the impact of the overshooter by adjusting the coverage area. By implementing these two actions, the negative effects of the overshooter can be mitigated within the cluster.Rate this question:
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- 6.
Which 2 statements describe a Remote Radio Unit (RRU) ? (Choose 2)
- A.
A module used to increse radio channel element capacity .
- B.
A Diplexer used for dual band antennas .
- C.
A transmitter and receiver installed close to the antenna to reduce feeder loss .
- D.
A solution to increase coverage .
Correct Answer(s)
C. A transmitter and receiver installed close to the antenna to reduce feeder loss .
D. A solution to increase coverage .Explanation
A Remote Radio Unit (RRU) is a module that is installed close to the antenna in order to reduce feeder loss. This means that the RRU helps to minimize signal loss that can occur when transmitting and receiving signals over long distances. Additionally, an RRU is also a solution to increase coverage, meaning it helps to extend the range of a wireless network and improve the overall coverage area.Rate this question:
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- 7.
When performing capacity dimensioning, what are three considerations? ( Choose 2)
- A.
Number of subscribers
- B.
Mobile transmitter power
- C.
Available spactrum
- D.
Antenna Gain
- E.
Number of carriers per cell
Correct Answer(s)
A. Number of subscribers
C. Available spactrum
E. Number of carriers per cellExplanation
When performing capacity dimensioning, there are three main considerations that need to be taken into account. The first consideration is the number of subscribers, as the capacity needs to be able to accommodate the expected number of users. The second consideration is the available spectrum, as this determines the amount of frequency resources that can be allocated to support the capacity. Lastly, the number of carriers per cell is important, as having multiple carriers allows for increased capacity by dividing the available spectrum into smaller chunks. Considering these three factors is crucial in ensuring that the network can handle the expected traffic and provide an optimal user experience.Rate this question:
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- 8.
What are the name of interference generated when 2 or more transmitted signals are combined to produce interference on another frequency ?
- A.
Receiver blocking interference
- B.
Intermodulation interference
- C.
Out of band emission interference
- D.
External interference
Correct Answer
B. Intermodulation interferenceExplanation
Intermodulation interference occurs when two or more transmitted signals combine and produce interference on another frequency. This phenomenon is caused by non-linearities in the transmission system, such as amplifiers or mixers, which create additional frequencies that were not originally present. These additional frequencies can interfere with other signals and cause degradation in the overall signal quality. Therefore, intermodulation interference is the correct term to describe this type of interference.Rate this question:
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- 9.
Which 3 component are used for propogation model tuning? (Choose 3)
- A.
GPS
- B.
Network timing advance trace
- C.
CW transmitter
- D.
Mobile phone
- E.
Radio receiver
Correct Answer(s)
A. GPS
C. CW transmitter
E. Radio receiverExplanation
The three components used for propagation model tuning are GPS, CW transmitter, and radio receiver. GPS is used to accurately determine the location of the transmitter and receiver, which is essential for studying the propagation of signals. The CW transmitter is used to transmit continuous wave signals, which can be used to measure the signal strength and quality at different distances. The radio receiver is used to receive and analyze the signals transmitted by the CW transmitter, helping to understand how the signals propagate and interact with the environment.Rate this question:
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- 10.
What defines the downlink footprint of the following technologies ? ( Note : RS= Reference Signal) 1 GSM2 WCDMA3 LTE
- A.
1. RS; 2. CPICH ; 3. BCCH
- B.
1.RS; 2.BCCH; 3.CPICH
- C.
1. BCCH ; 2. CPICH ; 3. RS
- D.
1.CPICH; 2. BCCH; 3. RS
Correct Answer
C. 1. BCCH ; 2. CPICH ; 3. RSExplanation
The downlink footprint of GSM2 is defined by the Broadcast Control Channel (BCCH), the downlink footprint of WCDMA is defined by the Common Pilot Channel (CPICH), and the downlink footprint of LTE is defined by the Reference Signal (RS).Rate this question:
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- 11.
Which statement describes pole capacity in WCDMA or CDMA200 systems?
- A.
The loading at which the number of users is 75% of the maximum system capasity .
- B.
A theoretical capacity determined by the base station transmitter power.
- C.
A theoretical capacity at which the base station receiver noise rise is infinite .
- D.
The maximum number of user that can be connected to the system .
Correct Answer
C. A theoretical capacity at which the base station receiver noise rise is infinite .Explanation
The correct answer is a theoretical capacity at which the base station receiver noise rise is infinite. This statement describes pole capacity in WCDMA or CDMA200 systems. It refers to the maximum capacity of the system where the receiver noise rise becomes infinite, indicating that the system cannot accommodate any more users beyond this point. This theoretical capacity is determined by the limitations of the base station receiver and represents the maximum number of users that can be connected to the system.Rate this question:
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- 12.
The out of band emmision level for a base station transmitter is flat across a frequency range of 500 MHz and is measured at -50 dBm per 100 kHz. What is the power of the out-of-band emission in a 1 MHz bandwidth ?
- A.
-47 dBm
- B.
-60 dBm
- C.
-50 dBm
- D.
-40 dBm
Correct Answer
D. -40 dBmExplanation
The out-of-band emission level for a base station transmitter is measured at -50 dBm per 100 kHz. To find the power of the out-of-band emission in a 1 MHz bandwidth, we need to calculate the power level for a 1 MHz bandwidth. Since the given measurement is for a 100 kHz bandwidth, we can divide the power level by 10 to get the power level for a 1 MHz bandwidth. -50 dBm divided by 10 is -5 dBm. Therefore, the power of the out-of-band emission in a 1 MHz bandwidth is -5 dBm. However, none of the given answer options match this calculation, so the correct answer is not available.Rate this question:
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- 13.
Which statement is describes Link Adaptation ?
- A.
It is a special class of modulation-coding schemes used for high rate data transmission to combat multipath .
- B.
It is a method of adjusting CQI values to combat radio channel impairments such as multipath, fading & interference .
- C.
It is a technique for maximizing received signal powers for high rate data transmissions .
- D.
It is a method for matching transmitter characteristics such as modulation and coding to instantaneous radio channel conditions .
Correct Answer
B. It is a method of adjusting CQI values to combat radio channel impairments such as multipath, fading & interference .Explanation
Link adaptation is a method for adjusting CQI (Channel Quality Indicator) values to combat radio channel impairments such as multipath, fading, and interference. This technique allows for the optimization of transmission parameters, such as modulation and coding, based on the instantaneous conditions of the radio channel. By adapting to the changing channel conditions, link adaptation helps to maximize the quality and reliability of high rate data transmissions.Rate this question:
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- 14.
Which 2 RF devices would be used to combine signals to and from two different base stations onto a single antenna ? ( choose 2)
- A.
Hybrid ring combiner
- B.
Connector
- C.
Filter combiner
- D.
Air combining
Correct Answer(s)
A. Hybrid ring combiner
C. Filter combinerExplanation
The hybrid ring combiner and filter combiner are the two RF devices that would be used to combine signals to and from two different base stations onto a single antenna. The hybrid ring combiner combines the signals from the two base stations using a hybrid ring circuit, while the filter combiner combines the signals using a filtering circuit. Both devices are designed to ensure that the signals from the two base stations do not interfere with each other and are properly combined onto the single antenna.Rate this question:
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- 15.
Shadowing (log-normal fading) is due to which machanism
- A.
Obstruction of signal by obstacles near the terminal
- B.
Multipath reflection off nearby buildings
- C.
Earth curvature effect
- D.
Ground reflections
Correct Answer
A. Obstruction of signal by obstacles near the terminalExplanation
Shadowing, also known as log-normal fading, occurs when the signal is obstructed by obstacles near the terminal. This obstruction causes variations in the received signal strength, leading to fading. The presence of physical objects such as buildings, trees, or mountains can block or attenuate the signal, resulting in shadowing. This phenomenon is commonly observed in urban environments where there are many obstacles that can interfere with the propagation of wireless signals.Rate this question:
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- 16.
Which statement describes intra LTE handover Event A3 ?
- A.
The server becomes offset better then the neighbor .
- B.
The server becomes better then the neighbor .
- C.
The neighbor becomes better than serving .
- D.
The neighbor becomes offset better then serving .
Correct Answer
D. The neighbor becomes offset better then serving . -
- 17.
You re-tune BCCH frequencies with a frequency planning tool . What must be verified after completing this process?
- A.
BSIC
- B.
LAC
- C.
MAIO
- D.
Coverage
Correct Answer
A. BSICExplanation
After re-tuning BCCH frequencies with a frequency planning tool, it is important to verify the Base Station Identity Code (BSIC). The BSIC is a unique identifier for each base station and is used to differentiate between neighboring cells. Verifying the BSIC ensures that there is no interference or confusion between neighboring cells, allowing for efficient and reliable communication within the network.Rate this question:
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- 18.
A spectrum analyzer measures 10 dBm in a measurement bandwidth of 50 KHz . The Signal spectral density is constant over the transmitter BW of 500 KHz . What is the total transmitted power in the transmitter BW ?
- A.
20 dBm
- B.
40 dBm
- C.
30 dBm
- D.
10 dBm
Correct Answer
A. 20 dBmExplanation
The total transmitted power in the transmitter bandwidth can be calculated by adding the power measured by the spectrum analyzer to the power that falls outside the measurement bandwidth. In this case, the spectrum analyzer measures 10 dBm in a measurement bandwidth of 50 KHz. Since the signal spectral density is constant over the transmitter bandwidth of 500 KHz, we can assume that the power outside the measurement bandwidth is the same as the power inside the measurement bandwidth. Therefore, the total transmitted power in the transmitter bandwidth is 20 dBm.Rate this question:
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- 19.
Which 2 statement apply for WCDMA soft Handover? (Choose 2)
- A.
If suitable SHO cell fails to be added to the active set, the call will drop .
- B.
If a new candidate cell is detected for SHO, the UE sends a RACH transmission to the cell to setup the link .
- C.
SHO can only be performed between cells using the same carrier frequency .
- D.
Cell in active set are always in SHO .
Correct Answer(s)
C. SHO can only be performed between cells using the same carrier frequency .
D. Cell in active set are always in SHO .Explanation
The statement "SHO can only be performed between cells using the same carrier frequency" is correct because in WCDMA soft handover, the handover is only possible between cells that are using the same carrier frequency.
The statement "Cell in active set are always in SHO" is also correct because in WCDMA soft handover, the cells in the active set are always involved in the handover process.Rate this question:
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- 20.
Which 3 elements determine the accuracy of predictions ? (Choose three)
- A.
Updated traffic data .
- B.
Correct digital terrain map .
- C.
Calibrated propogation model
- D.
Correct number of cell transmitters .
- E.
Correct EIRP
Correct Answer(s)
B. Correct digital terrain map .
C. Calibrated propogation model
E. Correct EIRPExplanation
The accuracy of predictions is determined by three elements: a correct digital terrain map, a calibrated propagation model, and a correct Effective Isotropic Radiated Power (EIRP). A correct digital terrain map ensures that the predictions are based on accurate information about the terrain. A calibrated propagation model takes into account the characteristics of the environment and accurately predicts signal propagation. A correct EIRP ensures that the power transmitted by the cell transmitters is accurately measured and accounted for in the predictions.Rate this question:
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- 21.
Which statement correctly describes HARQ with soft combining as used in WCDMA ?
- A.
One or more transmission of a packet are used until the packet can be successfully decoded
- B.
It is the way of minimizing signal to noise(SNR) ratios when receiving multiple signals
- C.
It is a adeptive rate query scheme used for link adaption in soft handover .
- D.
It is a modulation scheme that allow data rates to be achived .
Correct Answer
A. One or more transmission of a packet are used until the packet can be successfully decodedExplanation
HARQ with soft combining in WCDMA is a technique where one or more transmissions of a packet are used until the packet can be successfully decoded. This means that if a transmission is unsuccessful, the receiver can request retransmission of the packet until it can be decoded correctly. This helps to improve the reliability and efficiency of the communication by allowing for error correction and minimizing the impact of noise or interference.Rate this question:
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- 22.
What does clutter type mean when used in radio network design process ?
- A.
The type of antenna .
- B.
The type of enviroment
- C.
The type of reference coordinate system
- D.
The type of traffic data
Correct Answer
B. The type of enviromentExplanation
Clutter type refers to the type of environment in radio network design process. It is important to consider the type of environment, such as urban, suburban, or rural, as it affects the propagation characteristics of radio waves. Different types of clutter, such as buildings, trees, or open spaces, can cause signal attenuation, reflection, or interference. Understanding the clutter type helps in determining the appropriate antenna placement, power levels, and frequency allocation for optimal radio network design.Rate this question:
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- 23.
In a new radio N/W, which 3 KPIs are commonly used during the initial tuning process to evaluate the packet switched (PS) performance for the acceptance cluster ?
- A.
Drop call rate
- B.
Uplink & downlink throughput
- C.
Busy hour traffic
- D.
Daily traffic
- E.
Call setup success rate
Correct Answer(s)
A. Drop call rate
B. Uplink & downlink throughput
E. Call setup success rateExplanation
During the initial tuning process of a new radio network, three commonly used KPIs to evaluate the packet switched (PS) performance for the acceptance cluster are drop call rate, uplink and downlink throughput, and call setup success rate. Drop call rate measures the percentage of calls that are prematurely terminated, indicating the network's ability to maintain stable connections. Uplink and downlink throughput assess the data transfer rates in both directions, ensuring efficient transmission. Call setup success rate indicates the network's ability to successfully establish connections, reflecting its overall performance in handling call setups.Rate this question:
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- 24.
Regarding WCDMA Link Budgets, what is the purpose of Eb/No ?
- A.
It sets the base station or mobile terminal receiver sensitivities .
- B.
It defines the base station or mobile station receiver noise figures .
- C.
It determines the coding rate & throughputs used for link adaptation .
- D.
It ensure that the base station or mobile terminal transmitter power do not exceed legal limits .
Correct Answer
B. It defines the base station or mobile station receiver noise figures .Explanation
Eb/No, also known as the Energy per bit to Noise power Spectral Density ratio, is a measure of the signal quality in a communication system. It represents the ratio of the energy per bit to the noise power spectral density. In the context of WCDMA Link Budgets, Eb/No is used to define the base station or mobile station receiver noise figures. This means that it helps determine the level of noise in the receiver, which is an important factor in assessing the overall performance and quality of the communication system.Rate this question:
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- 25.
Which interface is used in WCDMA by users euipment (UE) to commuticate with a radio base station?
- A.
Gn
- B.
Uu
- C.
Iub
- D.
Iur
Correct Answer
B. UuExplanation
Uu is the correct answer because it is the interface used in WCDMA by users equipment (UE) to communicate with a radio base station. The Uu interface is the air interface that allows for wireless communication between the UE and the base station. It is responsible for transmitting voice, data, and control signals between the two devices. The Uu interface operates in the frequency range allocated for UMTS/WCDMA and is essential for the functioning of the WCDMA network.Rate this question:
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- 26.
Which 2 statement are correct about an Urban site design? (choose 2)
- A.
Directional antennas are not used
- B.
Generally, remote radio units reduce feeder losses .
- C.
Extended range cells are used .
- D.
Cross polar antennas provide suffucient diversity .
Correct Answer(s)
B. Generally, remote radio units reduce feeder losses .
D. Cross polar antennas provide suffucient diversity .Explanation
Generally, remote radio units reduce feeder losses. This means that by using remote radio units, the signal loss in the feeder cables is minimized, resulting in better signal quality and coverage.
Cross polar antennas provide sufficient diversity. Cross polar antennas are designed to transmit and receive signals in different polarizations, which helps to mitigate the effects of signal fading and interference. This diversity improves the reliability and performance of the wireless network.Rate this question:
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- 27.
You have an LTE urban N/W environment with an inter-site distance of 300 meters and tri-sector sites. Which commercial horizontal beam-width antenna would you use to reduse interference between Co-located cells?
- A.
Horizontal beam width = 10º
- B.
Horizontal beam width = 65º
- C.
Horizontal beam width = 120º
- D.
Horizontal beam width = 90º
Correct Answer
B. Horizontal beam width = 65ºExplanation
A horizontal beam width of 65º would be the best choice to reduce interference between co-located cells in an LTE urban network environment with a 300-meter inter-site distance and tri-sector sites. A narrower beam width helps to focus the antenna's signal in a specific direction, reducing the chances of interference with neighboring cells. A wider beam width would allow the signal to spread out more, increasing the chances of interference. Therefore, a horizontal beam width of 65º strikes a balance between focusing the signal and minimizing interference.Rate this question:
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- 28.
A customer asked for an initial estimation of the number of sites needed to cover a large city . What would you do?
- A.
Provide an estimation based on planning tool results, using analytical studies .
- B.
Provide an estimation based on link budget analysis .
- C.
Provide an estimation based on planning tool results, using Monte Carlo simulation.
- D.
Provide an estiamtion based on RF optimization results, using site selection capabilities .
Correct Answer
B. Provide an estimation based on link budget analysis .Explanation
Link budget analysis is a method used to calculate the power budget for a wireless communication system. It takes into account factors such as transmit power, antenna gain, path loss, and receiver sensitivity to determine the maximum distance between sites. By using link budget analysis, an estimation can be provided for the number of sites needed to cover a large city based on the available power and signal strength. This method is commonly used in the telecommunications industry to plan and optimize network coverage.Rate this question:
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- 29.
Which 3 maps types are used as input to propagation prediction tools for use in RF & Monte Carlo Predetion? (choose 3)
- A.
Traffic distribution map
- B.
Elevation map
- C.
Satellite photograph map .
- D.
Noise rise map
- E.
Clutter type (environment) map
Correct Answer(s)
A. Traffic distribution map
B. Elevation map
E. Clutter type (environment) mapExplanation
The three map types used as input to propagation prediction tools for RF & Monte Carlo Prediction are traffic distribution map, elevation map, and clutter type (environment) map. These maps provide important information for predicting the propagation of radio frequency signals and optimizing network coverage. The traffic distribution map helps in understanding the distribution of user traffic and identifying areas with high demand. The elevation map provides data on the terrain, which affects signal propagation. The clutter type map helps in identifying the type of environment, such as urban or rural, which also affects signal propagation.Rate this question:
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- 30.
Which statement describes noise figure(NF) ?
- A.
A parameter in the base station that is used for UL power control .
- B.
The improvement in the SNR caused by active or passive RF system components .
- C.
The UL coverage improvemant when using a tower mounted amplifier.
- D.
The degradation in the signal-To-Noise ratio (SNR) caused by active or passive RF system components .
Correct Answer
D. The degradation in the signal-To-Noise ratio (SNR) caused by active or passive RF system components .Explanation
Noise figure (NF) is a measure of the degradation in the signal-to-noise ratio (SNR) caused by active or passive RF system components. It quantifies how much the noise introduced by these components affects the overall quality of the signal. A lower noise figure indicates better performance and less degradation of the SNR.Rate this question:
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- 31.
Which action should be taken to improve the accuracy of propogation model ?
- A.
Change the antenna height
- B.
Adjust the downlink powers of cells
- C.
Perform a drive test using a scanner .
- D.
Reduce the log normal fading margin .
Correct Answer
C. Perform a drive test using a scanner .Explanation
Performing a drive test using a scanner is the action that should be taken to improve the accuracy of the propagation model. By conducting a drive test, data can be collected on the actual signal strength and quality at different locations, allowing for a more accurate model to be developed. This test helps in identifying any issues or discrepancies in the model and allows for adjustments to be made accordingly.Rate this question:
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- 32.
Which combination of elements are interconnected by the interface S1 in LTE N/W ?
- A.
UE with MME
- B.
ENB with eNb
- C.
ENB with MME
- D.
ENB with UE
Correct Answer
C. ENB with MMEExplanation
The correct answer is "eNB with MME". In an LTE network, the eNB (evolved NodeB) is responsible for managing the radio interface with the User Equipment (UE), while the MME (Mobility Management Entity) is responsible for managing the mobility and authentication of the UE. Therefore, the eNB and MME are interconnected by the interface S1 to facilitate communication and coordination between them.Rate this question:
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- 33.
UMTS Monte Carlo simulation shows that a certain cell is overloaded (DL Load = 100%) with low DL interference . what would you do resolve the problem ?
- A.
Increase the number of scrambling codes .
- B.
Increase power amplifier (PA) output power .
- C.
Increase BW by 1 MHz.
- D.
Disable soft handover (SHO).
Correct Answer
B. Increase power amplifier (PA) output power .Explanation
Increasing the power amplifier (PA) output power would be the best solution to resolve the problem of an overloaded cell with low DL interference. By increasing the PA output power, the signal strength of the cell will be enhanced, allowing it to handle the high DL load more efficiently. This will help in improving the overall performance and capacity of the cell, ensuring a better user experience. Increasing the number of scrambling codes or the bandwidth may not directly address the issue of overload, while disabling soft handover (SHO) may result in degraded network performance.Rate this question:
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- 34.
Which KPI should be used to identify issue in a cell during the call establishment procedure .
- A.
Soft handover success rartio .
- B.
Minutes per drop .
- C.
Call setup Succes Rate (CSSR) .
- D.
Drop Call rate.
Correct Answer
C. Call setup Succes Rate (CSSR) .Explanation
The correct answer is Call setup Success Rate (CSSR). CSSR is a key performance indicator that measures the percentage of successful call setups out of the total attempted call setups. It is used to identify issues in a cell during the call establishment procedure. A low CSSR indicates that there are problems with the cell, such as congestion or poor coverage, which can result in dropped calls or failed call setups. By monitoring CSSR, network operators can identify and address issues to improve the overall call setup success rate.Rate this question:
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- 35.
A base station receiver has a thermal noise floor (kBT) of -108dBm, a noise figure of 2 dB & is not experiencing interference from external sources or other users . An SINR of 10 dB is required to achive the target throughput at the base station . What is the minimum signal level required at the input to the receiver to achieve the target data throughput ?
- A.
(-96) dBm
- B.
(-98) dBm
- C.
(-120) dBm
- D.
(-100) dBm
Correct Answer
D. (-100) dBmExplanation
The minimum signal level required at the input to the receiver to achieve the target data throughput is -100 dBm. This is determined by adding the SINR requirement of 10 dB to the noise figure of 2 dB and subtracting it from the thermal noise floor of -108 dBm. This calculation results in a minimum signal level of -100 dBm.Rate this question:
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- 36.
You want to maximize the sensivity of the overall receive system. Referring to the exhibit, where should you place the amplifire with the noise performance?
- A.
The amplifire should be placed just after the feeder cable (location B)
- B.
The amplifier should be placed just after the antenna (location A)
- C.
The amplifire should be placed just after the base station receiver (Location C)
- D.
If a TMA is used, it does not matter where the amplifier is palced .
Correct Answer
B. The amplifier should be placed just after the antenna (location A)Explanation
Placing the amplifier just after the antenna (location A) maximizes the sensitivity of the overall receive system. By placing the amplifier at this location, any noise introduced by the feeder cable or base station receiver is minimized, allowing for a stronger and cleaner signal to be amplified. This ensures that the system can effectively pick up and process weak signals, improving the overall sensitivity of the receive system.Rate this question:
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- 37.
The exhibit shows a base station to mobile terminal system and a corresponding link budget .What is the path loss(X) so that the link budget is correct ?
- A.
95 dB
- B.
90 dB
- C.
105 dB
- D.
100 dB
Correct Answer
B. 90 dBExplanation
The correct answer is 90 dB. Path loss refers to the reduction in power density (attenuation) of an electromagnetic wave as it propagates through space. The link budget is a calculation of all the gains and losses in a communication system. In order for the link budget to be correct, the path loss must be accurately accounted for. Therefore, the path loss (X) should be 90 dB.Rate this question:
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- 38.
Which 2 duplex technique are used in LTE ? (Choose 2)
- A.
FDD
- B.
TDMA
- C.
OFDMA
- D.
TDD
Correct Answer(s)
A. FDD
D. TDDExplanation
The two duplex techniques used in LTE are FDD (Frequency Division Duplexing) and TDD (Time Division Duplexing). FDD allows for simultaneous transmission and reception on different frequencies, while TDD allows for alternating transmission and reception on the same frequency. Both techniques are used to optimize the use of available spectrum and improve network efficiency in LTE.Rate this question:
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- 39.
Which 2 actions will improve dominance? (choose 2)
- A.
Change antenna tilts
- B.
Add tower mounted amplifire
- C.
Add a new site in the area
- D.
Add another carrier frequency to each site .
Correct Answer(s)
A. Change antenna tilts
C. Add a new site in the areaExplanation
Changing antenna tilts can improve dominance by adjusting the angle and direction of the antenna to optimize signal coverage and reduce interference. Adding a new site in the area can also improve dominance by increasing the number of available cell sites and improving overall coverage and capacity.Rate this question:
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- 40.
What is the correct sequence of task in a WCDMA network design .
- A.
Coverage prediction, radio N/W link budget, Monte Carlo analysis, initial tuning & neighbor planning.
- B.
Radio N/W link budget, Coverage prediction, Monte Carlo analysis, neighbor planning.& initial tuning
- C.
Radio N/W link budget, Coverage prediction, Monte Carlo analysis, initial tuning neighbor planning.
- D.
Radio N/W link budget, Monte Carlo analysis, Coverage prediction, neighbor planning. & initial tuning
Correct Answer
B. Radio N/W link budget, Coverage prediction, Monte Carlo analysis, neighbor planning.& initial tuningExplanation
The correct sequence of tasks in a WCDMA network design is as follows: first, the radio network link budget is calculated to determine the expected signal strength and quality. Then, coverage prediction is performed to estimate the coverage area and identify potential coverage gaps. Next, Monte Carlo analysis is conducted to simulate various scenarios and assess the network's performance under different conditions. After that, initial tuning and neighbor planning are carried out to optimize the network's performance and ensure seamless handovers between cells. Therefore, the correct answer is "radio N/W link budget, Coverage prediction, Monte Carlo analysis, neighbor planning & initial tuning."Rate this question:
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- 41.
Which statement is correct for BSIC ?
- A.
BSIC does not depends on frequency plan.
- B.
BSIC is a combination of NCC & BCC
- C.
BSIC depends directly on the BCCH that is used .
- D.
BSIC depends on the hopping type .
Correct Answer
B. BSIC is a combination of NCC & BCCExplanation
BSIC stands for Base Station Identity Code, and it is used in GSM networks to uniquely identify each base station. The BSIC is a combination of two parts: the Network Color Code (NCC) and the Base Station Color Code (BCC). The NCC represents the network operator, while the BCC represents the specific base station within that network. Therefore, the statement "BSIC is a combination of NCC & BCC" is correct.Rate this question:
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- 42.
What is the purpose of a splitter ?
- A.
To amplify the signal by 3 dB,
- B.
To provide a final element in a transmit chain
- C.
To distribute the signal with equal power distribution ,
- D.
To improve gain
Correct Answer
C. To distribute the signal with equal power distribution ,Explanation
A splitter is used to distribute a signal with equal power distribution to multiple output ports. It takes an input signal and splits it into multiple output signals, ensuring that each output receives the same power level. This is commonly used in various applications such as telecommunications, audio/video distribution, and networking, where the signal needs to be shared among multiple devices or locations. By providing equal power distribution, a splitter allows for efficient and reliable signal transmission to multiple destinations.Rate this question:
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- 43.
Which 2 would effect the path loss predicted by the Okumura-Hata propogation model? (choose 2)
- A.
A change in the distance between tranmitter & receiver
- B.
A change in the transmitted power
- C.
A change in the frequency band
- D.
A change in the antenna tilt.
Correct Answer(s)
A. A change in the distance between tranmitter & receiver
C. A change in the frequency bandExplanation
The path loss predicted by the Okumura-Hata propagation model is affected by a change in the distance between the transmitter and receiver because the path loss increases as the distance between them increases. Additionally, a change in the frequency band also affects the path loss because higher frequency signals experience more attenuation than lower frequency signals.Rate this question:
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- 44.
What is the purpose of tower mounted amplifier ?
- A.
To improve the DL performance of a base station, especially if feeder losses are high
- B.
To overcome inter modulation interference issues in co-sited base station
- C.
To improve the sensivity of a base station receiver system, especially if feeder losses are high
- D.
To assist with DL power control for a base station transreceiver
Correct Answer
C. To improve the sensivity of a base station receiver system, especially if feeder losses are highExplanation
The purpose of a tower mounted amplifier is to improve the sensitivity of a base station receiver system, particularly in cases where there are high feeder losses. This means that the amplifier helps to enhance the ability of the receiver system to detect and receive signals, compensating for any signal loss that may occur due to the feeder. By improving sensitivity, the tower mounted amplifier ensures that the base station can effectively receive and process incoming signals, leading to improved overall performance.Rate this question:
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- 45.
GSM Which 3 inputs are required when making an initial GSM coverage prediction? (choose 3)
- A.
Sector O/P power
- B.
Vector Map
- C.
Terrain elevation map
- D.
BCCH frequency of the setor
- E.
Position of the sectors (latitude/longitude)
Correct Answer(s)
A. Sector O/P power
C. Terrain elevation map
E. Position of the sectors (latitude/longitude)Explanation
When making an initial GSM coverage prediction, three inputs are required. The first input is the sector O/P power, which refers to the power output of the sector. The second input is the terrain elevation map, which provides information about the height and topography of the area. This is important because the elevation can affect the signal propagation. The third input is the position of the sectors, specifically the latitude and longitude coordinates. This information is necessary to accurately determine the location and coverage area of the GSM network.Rate this question:
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- 46.
When using a planning tool for LTE design, what are 2 O/P plots ? (choose 2)
- A.
A signal to interference-plus-noise ratio(SINR) plot
- B.
A soft HO state plot
- C.
A receive signal reference power (RSRP) plot
- D.
A received signal code power (RSCP) plot
Correct Answer(s)
A. A signal to interference-plus-noise ratio(SINR) plot
C. A receive signal reference power (RSRP) plotExplanation
The two output plots in LTE design when using a planning tool are a signal to interference-plus-noise ratio (SINR) plot and a receive signal reference power (RSRP) plot. The SINR plot helps to analyze the quality of the signal by comparing it with the interference and noise levels. The RSRP plot provides information about the power level of the received signal, which is crucial for determining the coverage and strength of the signal.Rate this question:
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- 47.
Which statement would be correct about an antenna with 65 degree horizontal beamwidth and a gain of 15 dBi?
- A.
The gain is approximately 12 dBi at horizontal angles of 30 and -30 degrees from the direction of maximum gain.
- B.
The gain is approximately 9 dBi at horizontal angles of 30 and -30 degrees from the direction of maximum gain.
- C.
The gain is approximately 12 dBi at horizontal angles of 60 and -60 degrees from the direction of maximum gain.
- D.
The gain is approximately 9 dBi at horizontal angles of 60 and -60 degrees from the direction of maximum gain.
Correct Answer
A. The gain is approximately 12 dBi at horizontal angles of 30 and -30 degrees from the direction of maximum gain.Explanation
The given antenna has a horizontal beamwidth of 65 degrees and a gain of 15 dBi. This means that the antenna provides maximum gain in a specific direction, and the gain decreases as the angle from the maximum direction increases. The statement that the gain is approximately 12 dBi at horizontal angles of 30 and -30 degrees from the direction of maximum gain is correct. At these angles, the gain is slightly lower than the maximum gain of 15 dBi, but still relatively high at 12 dBi.Rate this question:
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- 48.
Which 3 frequency Bands are used by WCDMA (UMTS) technology ? (Choose 3)
- A.
900 MHz
- B.
1900 MHz
- C.
700 MHz
- D.
2100 MHz
- E.
5.4 Ghz
Correct Answer(s)
A. 900 MHz
B. 1900 MHz
D. 2100 MHzExplanation
WCDMA (UMTS) technology uses the frequency bands of 900 MHz, 1900 MHz, and 2100 MHz. These frequency bands are used for transmitting and receiving signals in order to provide wireless communication services. The frequency bands determine the range and capacity of the network and are essential for ensuring efficient and reliable communication.Rate this question:
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- 49.
Which 3 elements are used to characterize a mobile radio channel ? (choose 3)
- A.
Slow fading
- B.
Path loss
- C.
Mobile speed
- D.
Mobile category
- E.
Base station power
Correct Answer(s)
A. Slow fading
B. Path loss
C. Mobile speedExplanation
The three elements used to characterize a mobile radio channel are slow fading, path loss, and mobile speed. Slow fading refers to the fluctuation in signal strength over time due to multipath propagation. Path loss is the attenuation of the signal as it travels through the environment. Mobile speed refers to the velocity at which the mobile device is moving, which affects the Doppler shift and the ability to maintain a stable connection.Rate this question:
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- 50.
A base station transmitter has a total output power of 40 W. A pilot channel is set to a level equal to 10% of the total base station transmitter output power. What is the transmitted power of the pilot channel?
- A.
40 dBm
- B.
33 dBm
- C.
36 dBm
- D.
46 dBm
Correct Answer
C. 36 dBmExplanation
The pilot channel is set to a level equal to 10% of the total base station transmitter output power. Therefore, the transmitted power of the pilot channel can be calculated by multiplying the total output power by 10% (0.10). In this case, 40 W * 0.10 = 4 W. Converting this power value to dBm, we use the formula 10 * log10(power in watts) + 30. Thus, 10 * log10(4) + 30 = 36 dBm.Rate this question:
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Mar 21, 2023Quiz Edited by
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Oct 31, 2015Quiz Created by
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