Physics Quiz: Light And Optics
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The proper name for farsightedness is:
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Hyperopia
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Presbyopia
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Astigmatism
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Glaucoma
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Hello and welcome to this ultimate Physics quiz on Light and Optics that we've created below for you. This quiz will test your knowledge about light and its related concepts. Let's see if you can crack this quiz or not. The questions here are multiple-choice based, and you just have to choose the correct answer to every question.
Immerse yourself See morein the brilliance of optics with our captivating Physics Quiz focusing on Light and Optics. This quiz is crafted for the inquisitive minds fascinated by the mysteries of light. From understanding the fundamentals of reflection and refraction to unraveling the mesmerizing properties of lenses and mirrors, each question serves as a window into the intriguing world of optics.
Dive into topics that range from the behavior of light waves to the formation of images, offering a glimpse into the way we perceive the visual wonders around us. Whether you're a physics enthusiast or a student seeking to grasp the essence of optics, this quiz provides an insightful journey through the science of illumination.
Challenge yourself, broaden your knowledge, and let the quiz shine a light on the captivating physics of optics. Do you think you think you'll be able to pass this test? Let's start the quiz and find out.
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- 2.
A survivor from a shipwreck sees an image of a fish in the water. To catch it with her spear, she must:
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Aim above the image of the fish
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Aim below the image of the fish
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Aim at the image of the fish
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Aim behind the fish
Correct Answer
A. Aim below the image of the fishExplanation
When light travels from one medium to another, it changes direction. This phenomenon is called refraction. When the survivor sees the image of the fish in the water, she is actually seeing a refracted image due to the bending of light. The image appears higher than the actual position of the fish. Therefore, to compensate for this refraction, she needs to aim below the image of the fish in order to spear it accurately.Rate this question:
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- 3.
For a converging lens, a light ray that is traveling parallel to the principal axis refracts:
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Through the principal focus
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Through the secondary focus
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Through the optical center
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Parallel to the principal axis
Correct Answer
A. Through the secondary focusExplanation
For a converging lens, a light ray traveling parallel to the principal axis refracts and converges at the secondary focus (or image focus) on the opposite side of the lens. When light rays parallel to the principal axis pass through a converging lens, they refract and converge at a point called the secondary focus. This is where an image of an object placed at infinity would be formed.Rate this question:
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- 4.
Light travels from medium X into medium Y. Medium Y has a higher index of refraction. Consider each statement below: (i) The light travels faster in X. (ii) The light will bend towards the normal. (iii) The light will speed up. (iv) The light will bend away from the normal.
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(ii)
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(iii) and (iv)
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(i) and (ii)
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(ii), (iii), and (iv)
Correct Answer
A. (i) and (ii)Explanation
When light travels from a medium with a lower index of refraction to a medium with a higher index of refraction, it slows down and bends towards the normal. This is because the speed of light is inversely proportional to the index of refraction of the medium it is traveling in. Therefore, statement (i) is correct because the light travels slower in medium X compared to medium Y. Statement (ii) is also correct because the light will indeed bend towards the normal when it enters medium Y.Rate this question:
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- 5.
The critical angle of zircon is 31°. Which of the following incident angles would result in total internal reflection?
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17°
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34°
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56°
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B and C
Correct Answer
A. B and CExplanation
The critical angle is the angle of incidence at which light passing from a denser medium to a less dense medium is refracted at an angle of 90 degrees. Any incident angle greater than the critical angle will result in total internal reflection. In this case, the critical angle of zircon is 31 degrees. Therefore, incident angles of 34 degrees and 56 degrees (options B and C) would result in total internal reflection.Rate this question:
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- 6.
The proper name for the inability to focus in different planes is:
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Hyperopia
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Presbyopia
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Astigmatism
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Myopia
Correct Answer
A. AstigmatismExplanation
Astigmatism is the proper name for the inability to focus in different planes. It is a common eye condition where the cornea or lens is irregularly shaped, causing blurry or distorted vision at all distances. This irregularity prevents light from properly focusing on the retina, resulting in difficulties in focusing on objects both near and far. Hyperopia refers to farsightedness, presbyopia is the loss of near vision with age, and myopia is nearsightedness.Rate this question:
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- 7.
The focal length of a converging lens is 15 cm. An object is placed 45 cm away from the lens. The image will be:
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Smaller and real
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Larger and real
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The same size and real
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Smaller and virtual
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Larger and virtual
Correct Answer
A. Smaller and realExplanation
When an object is placed beyond the focal point of a converging lens, a real and smaller image is formed on the opposite side of the lens. This is because the light rays converge after passing through the lens, creating a smaller image. Therefore, the given answer "smaller and real" is correct.Rate this question:
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- 8.
A light ray has an angle of incidence of 34º. The reflected ray will make what angle with the reflecting surface?
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0º
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34º
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66º
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74º
Correct Answer
A. 34ºExplanation
When a light ray is incident on a reflecting surface, the angle of incidence is equal to the angle of reflection. In this case, the angle of incidence is 34°, so the reflected ray will also make an angle of 34° with the reflecting surface.Rate this question:
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- 9.
The critical angle for diamond (n = 2.42) submerged in water (n = 1.33) is:
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33.34°
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49°
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24°
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17°
Correct Answer
A. 33.34°Explanation
The critical angle for diamond submerged in water can be calculated using the formula: critical angle = sin^(-1)(n2/n1), where n2 is the refractive index of the medium diamond submerged in (water), and n1 is the refractive index of diamond. Plugging in the values, we get critical angle = sin^(-1)(1.33/2.42) = 33.34°. Therefore, the correct answer is 33.34°.Rate this question:
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- 10.
A object is placed between f and 2f for a diverging lens. The image will be located:
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Between f and 2f
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Between the lens and f
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Farther than 2f
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A or B
Correct Answer
A. Between the lens and fExplanation
When an object is placed between the focal point (f) and twice the focal point (2f) for a diverging lens, the image formed will be located between the lens and the focal point (f). This is because a diverging lens always forms virtual and upright images that are located on the same side as the object. Since the object is placed between f and 2f, the image will be formed on the same side of the lens, between the lens and f.Rate this question:
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- 11.
Calculate the index of refraction for an object in which light travels at 1.97 x 108 m/s.
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1.97 m/s
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1.52 m/s
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1.95
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1.52
Correct Answer
A. 1.52Explanation
The index of refraction is a measure of how much light slows down when it passes through a medium compared to its speed in a vacuum. In this question, the given speed of light in the object is 1.97 x 10^8 m/s. To calculate the index of refraction, we need to divide the speed of light in a vacuum (3 x 10^8 m/s) by the speed of light in the object. Therefore, the index of refraction is 3 x 10^8 m/s divided by 1.97 x 10^8 m/s, which equals approximately 1.52.Rate this question:
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- 12.
Light that travels into the eye passes through several parts to get to the retina. The correct order is:
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Cornea, vitreous humor, lens, pupil
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Cornea, lens, pupil, vitreous humor
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Pupil, cornea, lens, vitreous humor
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Cornea, pupil, lens, vitreous humor
Correct Answer
A. Cornea, pupil, lens, vitreous humorExplanation
Light enters the eye through the cornea, which is the clear, outermost layer of the eye. It then passes through the pupil, which is the opening in the center of the iris that regulates the amount of light entering the eye. After passing through the pupil, the light reaches the lens, which focuses the light onto the retina at the back of the eye. Finally, the light passes through the vitreous humor, a gel-like substance that fills the space between the lens and the retina, before reaching the retina, where it is converted into electrical signals for the brain to process.Rate this question:
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- 13.
The focal length of a diverging lens is 12 cm. An object is placed 5.0 cm away from the lens. The image will be:
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Smaller and real
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Larger and real
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The same size and real
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Smaller and virtual
Correct Answer
A. Smaller and virtualExplanation
When an object is placed 5.0 cm away from a diverging lens with a focal length of 12 cm, the image formed will be smaller and virtual. This is because a diverging lens always forms virtual images that are smaller than the object. The negative focal length indicates that the lens is diverging, causing the light rays to spread out. As a result, the image is formed on the same side as the object and cannot be projected onto a screen, making it virtual. Additionally, the image is smaller than the object due to the diverging nature of the lens.Rate this question:
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- 14.
A block of glass is pushed into the path of the light, as shown below. The point where the light rays cross will:
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Stay in the same place
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Move to the left
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Move to the right
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Shift up
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Shift down
Correct Answer
A. Move to the rightExplanation
When a block of glass is pushed into the path of light, it causes the light rays to change direction due to refraction. Refraction occurs because the speed of light changes when it passes from one medium (air) to another (glass). In this case, the block of glass is denser than air, so the light rays bend towards the normal (a line perpendicular to the surface of the glass). As a result, the point where the light rays cross will appear to move to the right.Rate this question:
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- 15.
When a light ray traveling in glass is incident on an air surface:
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It will refract away from the normal
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Some of the light may be reflected
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All of the light may be reflected
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All of A, B, and C
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Two of A, B, and C
Correct Answer
A. All of A, B, and CExplanation
When a light ray traveling in glass is incident on an air surface, it can undergo multiple phenomena. Firstly, it will refract away from the normal, meaning it will change direction as it passes from a denser medium (glass) to a less dense medium (air). Additionally, some of the light may be reflected at the air surface, causing a partial reflection. Lastly, under certain conditions, all of the light may be reflected, resulting in total internal reflection. Therefore, all of the options A, B, and C are correct, as they describe different possibilities that can occur when a light ray travels from glass to air.Rate this question:
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Current Version
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Mar 26, 2024Quiz Edited by
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Expert Reviewed by
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Nov 08, 2009Quiz Created by
Junho Song
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