Molarity Practice Quiz

Reviewed by Zohra Sattar Waxali

Zohra Sattar Waxali, PhD (Chemistry) |

Chemistry

Review Board Member

Dr. Zohra Sattar Waxali earned her doctorate in chemistry and biochemistry from Northwestern University, specializing in the metallomes of cardiac cells and stem cells, and their impact on biological function. Her research encompasses the development of arsenoplatin chemotherapeutics, stapled peptide estrogen receptor inhibitors, and antimicrobial natural products.

, PhD (Chemistry)

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Quizzes Created: 18 | Total Attempts: 57,284

Questions: 10 | Attempts: 17,385 | Updated: Feb 12, 2024

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Are you ready to take this molarity practice quiz that we have here for you? If so, take the quiz then! The concentration of a solution can be calculated even before it is formed by the use of the number of moles they have. Do you have an upcoming chemistry exam where you need to study morality? This quiz will help you practice molarities calculations. Give it a try, and all the best! Let's go for it!

Questions and Answers

1.

Sea water contains roughly 28.0 g of NaCl per liter. What is the molarity of sodium chloride in seawater?
- A.
  
  0.479M
- B.
  
  0.488M
- C.
  
  0.499M
- D.
  
  0.610M
Correct Answer
A. 0.479M

Explanation
The molarity of a solution is defined as the number of moles of solute per liter of solution. In this case, the solute is sodium chloride (NaCl) and the solution is seawater. To calculate the molarity, we need to convert the mass of NaCl to moles and then divide by the volume of the solution in liters. Given that seawater contains 28.0 g of NaCl per liter, we can convert this to moles using the molar mass of NaCl (58.44 g/mol). Dividing the moles of NaCl by the volume of the solution in liters gives us the molarity. Calculating this value, we find that the molarity of sodium chloride in seawater is 0.479M.

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0
2.

What is the molarity of 5.30 g of Na₂CO₃ dissolved in 400.0 mL solution?
- A.
  
  0.105M
- B.
  
  0.125M
- C.
  
  0.25M
- D.
  
  0.225M
Correct Answer
B. 0.125M

Explanation
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution in liters. In this case, we need to first convert the mass of Na2CO3 to moles by using its molar mass. Then, we divide the moles by the volume of the solution in liters. The molarity is calculated to be 0.125M.

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19
8
3.

What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?
- A.
  
  0.15M
- B.
  
  0.167M
- C.
  
  0.172M
- D.
  
  0.184M
Correct Answer
B. 0.167M

Explanation
To find the molarity of a solution, we need to calculate the number of moles of solute (NaOH) and divide it by the volume of the solution in liters.

First, we need to convert the mass of NaOH from grams to moles. The molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol. So, 5.00 g of NaOH is equal to 5.00 g / 40.00 g/mol = 0.125 mol.

Next, we need to convert the volume of the solution from milliliters to liters. 750.0 mL is equal to 750.0 mL / 1000 mL/L = 0.750 L.

Finally, we divide the number of moles (0.125 mol) by the volume of the solution in liters (0.750 L) to get the molarity. 0.125 mol / 0.750 L = 0.1667 M, which rounds to 0.167 M.

Therefore, the molarity of the solution is 0.167M.

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13
3
4.

The molarity of 10.00 g of NaOH in 1900.0 mL of solution is
- A.
  
  0.152M
- B.
  
  0.178M
- C.
  
  0.252M
- D.
  
  None of these
Correct Answer
D. None of these

Explanation
Molarity is defined as the moles of solute divided by the liters of solution. The molar mass of NaOH is 40 g/mol, so this solution contains 10.00 g NaOH/ 40 g/mol = 0.25 moles of NaOH. 1900.0 mL is 1.9 L. As such, the molarity of the solution is 0.25 mol / 1.9 L = 0.13 M, which is not one of the answer choices given.

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3
0
5.

What is the molarity of a solution made by dissolving 20.0 g of H₃PO₄ in 50.0 mL of solution?
- A.
  
  3.08M
- B.
  
  4.08M
- C.
  
  5.08M
- D.
  
  6.08M
Correct Answer
B. 4.08M

Explanation
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution in liters. In this case, we need to first calculate the moles of H3PO4. The molar mass of H3PO4 is 97.99 g/mol. By dividing the given mass of H3PO4 (20.0 g) by its molar mass, we find that there are 0.204 moles of H3PO4. Next, we convert the given volume of the solution (50.0 mL) to liters by dividing it by 1000. The volume of the solution is 0.050 L. Finally, we divide the moles of H3PO4 by the volume of the solution to find the molarity: 0.204 moles / 0.050 L = 4.08 M.

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10
0
6.

0.450 moles of NaCl are dissolved in 95.0 mL of water. Calculate the molarity of the NaCl solution.
- A.
  
  4.7M
- B.
  
  4.8M
- C.
  
  4.9M
- D.
  
  5.0M
Correct Answer
A. 4.7M

Explanation
To calculate the molarity of a solution, we need to divide the number of moles of solute by the volume of the solution in liters. In this case, we have 0.450 moles of NaCl dissolved in 95.0 mL of water. To convert the volume to liters, we divide by 1000, giving us 0.095 L. Dividing the moles by the volume in liters, we get a molarity of 4.737 M. Rounded to the nearest tenth, the molarity of the NaCl solution is 4.7M.

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0
7.

15 g of NaCl occupy a volume of 75 mL. What is the molarity of the solution?
- A.
  
  3.4M
- B.
  
  3.6M
- C.
  
  3.8M
- D.
  
  4.0M
Correct Answer
A. 3.4M

Explanation
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution in liters. In this case, we are given the mass of NaCl (15g) and the volume of the solution (75 mL). We need to convert the volume from milliliters to liters by dividing it by 1000. Then, we can calculate the moles of NaCl by dividing the mass by its molar mass. Finally, we divide the moles by the volume in liters to find the molarity. The correct answer is 3.4M.

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7
2
8.

45.0 g of Ca(NO₃)₂ was used to create a 1.3 M solution. What is the volume of the solution?
- A.
  
  115ml
- B.
  
  190ml
- C.
  
  210ml
- D.
  
  250ml
Correct Answer
C. 210ml

Explanation
To find the volume of the solution, we can use the formula:

Molarity (M) = moles of solute / volume of solution (L)

Given that the molarity is 1.3 M and the moles of solute is 45.0 g of Ca(NO3)2, we need to find the volume of the solution.

First, we need to convert the mass of Ca(NO3)2 to moles. The molar mass of Ca(NO3)2 is 164 g/mol, so:

moles of Ca(NO3)2 = mass / molar mass
moles of Ca(NO3)2 = 45.0 g / 164 g/mol
moles of Ca(NO3)2 = 0.2744 mol

Now, we can rearrange the formula to solve for the volume of the solution:

volume of solution = moles of solute / Molarity
volume of solution = 0.2744 mol / 1.3 mol/L
volume of solution ≈ 0.211 L

Since the volume is given in milliliters, we convert it to mL:

volume of solution = 0.211 L * 1000 mL/L
volume of solution ≈ 211 mL

Therefore, the volume of the solution is 210 mL.

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0
9.

What is the molarity of sodium chloride in river water?
- A.
  
  0.455M
- B.
  
  0.488M
- C.
  
  0.510M
- D.
  
  None of these
Correct Answer
D. None of these

Explanation
Waters can have varying salinities, so there is not enough information to calculate an answer to this question. Additionally, rivers are freshwater sources and likely have low concentrations of sodium chloride.

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10.

How many moles of Ca(NO₃)₂ are there in 75 mL of 0.25 M solution?.
- A.
  
  0.0188mol
- B.
  
  0.02mol
- C.
  
  0.0321mol
- D.
  
  0.044mol
Correct Answer
A. 0.0188mol

Explanation
The number of moles of a substance can be calculated using the formula: moles = concentration (M) × volume (L). In this case, the concentration is given as 0.25 M and the volume is given as 75 mL. However, the volume needs to be converted to liters by dividing it by 1000 (since 1 L = 1000 mL). Therefore, the volume is 75 mL ÷ 1000 = 0.075 L. Plugging these values into the formula, we get moles = 0.25 M × 0.075 L = 0.0188 mol.

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9
2

Zohra Sattar Waxali |PhD (Chemistry) |

Chemistry

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Mar 06, 2016

Quiz Created by
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Molarity Practice Quiz

Sea water contains roughly 28.0 g of NaCl per liter. What is the molarity of sodium chloride in seawater?

What is the molarity of 5.30 g of Na2CO3 dissolved in 400.0 mL solution?

What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?

The molarity of 10.00 g of NaOH in 1900.0 mL of solution is

What is the molarity of a solution made by dissolving 20.0 g of H3PO4 in 50.0 mL of solution?

0.450 moles of NaCl are dissolved in 95.0 mL of water. Calculate the molarity of the NaCl solution.

15 g of NaCl occupy a volume of 75 mL. What is the molarity of the solution?

45.0 g of Ca(NO3)2 was used to create a 1.3 M solution. What is the volume of the solution?

What is the molarity of sodium chloride in river water?

How many moles of Ca(NO3)2 are there in 75 mL of 0.25 M solution?.

What is the molarity of 5.30 g of Na₂CO₃ dissolved in 400.0 mL solution?

What is the molarity of a solution made by dissolving 20.0 g of H₃PO₄ in 50.0 mL of solution?

45.0 g of Ca(NO₃)₂ was used to create a 1.3 M solution. What is the volume of the solution?

How many moles of Ca(NO₃)₂ are there in 75 mL of 0.25 M solution?.