2477 Linear Regression Gradient & Y-intercept Formulae

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| By Anthony Nunan

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Quizzes Created: 132 | Total Attempts: 48,392

| Attempts: 77 | Questions: 24 | Updated: Mar 17, 2025

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1) We are trying to find the y-intercept for the linear regression line.The gradient is given as -2.The mean of the x values is -4 and the mean of the y values is 8The standard deviation of the x values is 7 and the standard deviation of the y values is 12.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

About This Quiz

2477 Linear Regression Gradient & Y-intercept Formulae - Quiz

. The three formulae used in this quiz are : General, y-intercept (a) and gradient (b)

2)

What first name or nickname would you like us to use?

You may optionally provide this to label your report, leaderboard, or certificate.

2) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 6 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

3) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.8The mean of the x values is 6 and the mean of the y values is 8The standard deviation of the x values is 18 and the standard deviation of the y values is 4.What is the y intercept to one decimal place?

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Explanation

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Submit

4) We are trying to find the y-intercept for the linear regression line.The gradient is given as 2.The mean of the x values is 4 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

5) We are trying to find the y-intercept for the linear regression line.The gradient is given as -0.5.The mean of the x values is 10 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

6) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 10 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

7) We are trying to find the y-intercept for the linear regression line.The gradient is given as 1.The mean of the x values is 6 and the mean of the y values is 8The standard deviation of the x values is 5 and the standard deviation of the y values is 3.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

8) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 8 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

9) The explanatory variable is height in cm, and the response variable is weight in kg.Using the generic equation for the linear regression line, y = 150 +17x, match the answers below.

Blue

Red

Purple

Orange

Green

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

10) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.8.The mean of the x values is 12 and the mean of the y values is 30The standard deviation of the x values is 4 and the standard deviation of the y values is 8.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

11) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.8The mean of the x values is 5 and the mean of the y values is 8The standard deviation of the x values is 10 and the standard deviation of the y values is 15.What is the y intercept to one decimal place?

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Explanation

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Submit

12) The data collected from a faulty freezer shows the following linear regression line :freezer temperature in degrees C = -2 + 1.2 x hours from pump failureSlope Statement

Blue

Red

Purple

Orange

Green

Yellow

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

13) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.7.The mean of the x values is 15 and the mean of the y values is 30The standard deviation of the x values is 6 and the standard deviation of the y values is 18.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

14) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.9.The mean of the x values is 18 and the mean of the y values is 34The standard deviation of the x values is 2 and the standard deviation of the y values is 6.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

15) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.9.The mean of the x values is 18 and the mean of the y values is 34The standard deviation of the x values is 4 and the standard deviation of the y values is 8.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

16) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.9.The mean of the x values is 6 and the mean of the y values is 27The standard deviation of the x values is 4 and the standard deviation of the y values is 2.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

17) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.8.The mean of the x values is 6 and the mean of the y values is 27The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

18) We are trying to find the y-intercept for the linear regression line.The gradient is given as 2.The mean of the x values is 4 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

19) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.6.The mean of the x values is 9 and the mean of the y values is 22The standard deviation of the x values is 7 and the standard deviation of the y values is 3.5.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

20) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.9The mean of the x values is 4 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Explanation

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Submit

21) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.9.The mean of the x values is 6 and the mean of the y values is 29The standard deviation of the x values is 2 and the standard deviation of the y values is 8.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

23) The data collected from a weight lifter shows the following linear regression line :weight lifted in kg = 45 + 2.3 x weeks spent in training programmeSlope Statement

Blue

Red

Purple

Orange

Green

Yellow

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

24) The data collected from a faulty freezer shows the following linear regression line :freezer temperature in degrees C = -2 + 1.2 x hours from pump failureY intercept Statement

Blue

Purple

Orange

Green

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

Thank you for your feedback!

All (24)
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Answered ()

We are trying to find the y-intercept for the linear regression...

The explanatory variable is height in cm, and the response variable is...

We are trying to find the gradient of the least squares regression...

We are trying to find the y-intercept for the linear regression...

The data collected from a faulty freezer shows the following linear...

We are trying to find the gradient of the least squares regression...

We are trying to find the y-intercept for the linear regression...

We are trying to find the gradient of the least squares regression...

We are trying to find the y-intercept for the linear regression...

We are trying to find the gradient of the least squares regression...

Type question here. Example: Practice makes you _____

The data collected from a weight lifter shows the following linear...

The data collected from a faulty freezer shows the following linear...

2477 Linear Regression Gradient & Y-intercept Formulae

1) We are trying to find the y-intercept for the linear regression line.The gradient is given as -2.The mean of the x values is -4 and the mean of the y values is 8The standard deviation of the x values is 7 and the standard deviation of the y values is 12.What is the y intercept?

2)

What first name or nickname would you like us to use?

2) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 6 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

4) We are trying to find the y-intercept for the linear regression line.The gradient is given as 2.The mean of the x values is 4 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

5) We are trying to find the y-intercept for the linear regression line.The gradient is given as -0.5.The mean of the x values is 10 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

6) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 10 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

7) We are trying to find the y-intercept for the linear regression line.The gradient is given as 1.The mean of the x values is 6 and the mean of the y values is 8The standard deviation of the x values is 5 and the standard deviation of the y values is 3.What is the y intercept?

8) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 8 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

9) The explanatory variable is height in cm, and the response variable is weight in kg.Using the generic equation for the linear regression line, y = 150 +17x, match the answers below.

10) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.8.The mean of the x values is 12 and the mean of the y values is 30The standard deviation of the x values is 4 and the standard deviation of the y values is 8.What is the gradient?

12) The data collected from a faulty freezer shows the following linear regression line :freezer temperature in degrees C = -2 + 1.2 x hours from pump failureSlope Statement

13) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.7.The mean of the x values is 15 and the mean of the y values is 30The standard deviation of the x values is 6 and the standard deviation of the y values is 18.What is the gradient?

14) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.9.The mean of the x values is 18 and the mean of the y values is 34The standard deviation of the x values is 2 and the standard deviation of the y values is 6.What is the gradient?

15) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.9.The mean of the x values is 18 and the mean of the y values is 34The standard deviation of the x values is 4 and the standard deviation of the y values is 8.What is the gradient?

16) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.9.The mean of the x values is 6 and the mean of the y values is 27The standard deviation of the x values is 4 and the standard deviation of the y values is 2.What is the gradient?

17) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.8.The mean of the x values is 6 and the mean of the y values is 27The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the gradient?

18) We are trying to find the y-intercept for the linear regression line.The gradient is given as 2.The mean of the x values is 4 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

19) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.6.The mean of the x values is 9 and the mean of the y values is 22The standard deviation of the x values is 7 and the standard deviation of the y values is 3.5.What is the gradient?

20) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.9The mean of the x values is 4 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

21) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.9.The mean of the x values is 6 and the mean of the y values is 29The standard deviation of the x values is 2 and the standard deviation of the y values is 8.What is the gradient?

22) Type question here. Example: Practice makes you _____

23) The data collected from a weight lifter shows the following linear regression line :weight lifted in kg = 45 + 2.3 x weeks spent in training programmeSlope Statement

24) The data collected from a faulty freezer shows the following linear regression line :freezer temperature in degrees C = -2 + 1.2 x hours from pump failureY intercept Statement