Trivia Quiz On Measurement And Calibration!
Let's face it: Unless your measurement instruments get regular calibration, the measurements they make will become meaningless. Calibration keeps your equipment running within tolerance. Test your knowledge on this.
- 1.
What is the term used to specify the difference between higher and lower calibration values in a measuring system?
- A.
Span
- B.
Drift
- C.
Range
- D.
Threshold
Correct Answer
A. SpanExplanation
The term used to specify the difference between higher and lower calibration values in a measuring system is called "Span". It refers to the range between the upper and lower limits of a measurement device.Rate this question:
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- 2.
The voltage that a Josephson Junction produces is proportional to...
- A.
Frequency
- B.
Light intensity
- C.
Current
- D.
Temperature
Correct Answer
A. FrequencyExplanation
The voltage produced by a Josephson Junction is proportional to the frequency of the applied microwave signal. This is known as the Josephson effect, where the voltage across the junction is directly related to the frequency of the electromagnetic wave. The Josephson effect is a quantum mechanical phenomenon that occurs in superconducting materials, and it is used in various applications such as high-precision voltage standards and superconducting quantum computers.Rate this question:
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- 3.
A DC voltmeter with a sensitivity of 500ohm/V. What will be the current through voltmeter for a full-scale reading in 100V range?
- A.
300mA
- B.
250mA
- C.
500mA
- D.
200mA
Correct Answer
D. 200mAExplanation
The sensitivity of the voltmeter is given as 500ohm/V. This means that for every volt of input, the voltmeter will draw a current of 500mA. Since the full-scale reading is 100V, the current through the voltmeter can be calculated by multiplying the sensitivity by the full-scale reading: 500ohm/V * 100V = 50,000mA = 50A. However, the question asks for the current in the 100V range, so we need to divide the current by 100 to get the current for a full-scale reading in the 100V range: 50A / 100 = 500mA. Therefore, the correct answer is 500mA.Rate this question:
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- 4.
Calibration is a term that is quite common. But a lot of times, people misuse it. What does it mean?
- A.
Altering a measuring device so it will read correctly
- B.
Comparing a measuring device to a standard of known accuracy
- C.
Rebuilding a measurement device to correct a malfunction
- D.
Using a measuring device to make a measurement
Correct Answer
B. Comparing a measuring device to a standard of known accuracyExplanation
Calibration refers to the process of comparing a measuring device to a standard of known accuracy. This is done to ensure that the measuring device is providing accurate and reliable measurements. By comparing the device to a known standard, any discrepancies or errors in the measurements can be identified and corrected if necessary. Calibration is essential in various industries and fields where precise measurements are required, such as scientific research, manufacturing, and quality control.Rate this question:
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- 5.
Calibration techs have to know a little about all sorts of subjects. Which of the following are involved in calibration?
- A.
Physics
- B.
Chemistry
- C.
Mathematics
- D.
All of the above
Correct Answer
D. All of the aboveExplanation
Calibration technicians need to have knowledge in various subjects because calibration involves measuring and adjusting instruments to ensure accuracy and precision. Physics is essential for understanding the principles of measurement and the behavior of instruments. Chemistry is important for calibrating instruments used in chemical analysis or processes. Mathematics is required for performing calculations and data analysis during calibration. Therefore, all of the above subjects are involved in calibration.Rate this question:
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- 6.
For a meter movement of 0 to 50mA meter movement, what is the sensitivity?
- A.
50ohm/V
- B.
20ohm/V
- C.
25ohm/V
- D.
5ohm/V
Correct Answer
B. 20ohm/VExplanation
The sensitivity of a meter movement is a measure of how much the meter deflects for a given input. In this case, the sensitivity is given as 20ohm/V. This means that for every volt of input, the meter will deflect by 20 ohms.Rate this question:
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- 7.
What is the term used to specify the closeness of two or more measurements?
- A.
Accuracy
- B.
Precision
- C.
Threshold
- D.
Fidelity
Correct Answer
B. PrecisionExplanation
Precision is the term used to specify the closeness of two or more measurements. It refers to the level of consistency and exactness in the measurements taken. A high level of precision means that the measurements are close to each other and have a low level of variability. Precision is important in scientific experiments and measurements as it indicates the reliability and reproducibility of the results.Rate this question:
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- 8.
A torque wrench measures the rotational force required to tighten a threaded fastener. Torque settings are often given in ft-lbs or in Nm. What parameters are involved in measuring torque?
- A.
Vacuum and current
- B.
Length and force
- C.
Pressure and voltage
- D.
Luminance and pH
Correct Answer
B. Length and forceExplanation
To measure torque, two parameters are involved: length and force. Length refers to the distance from the axis of rotation to the point where the force is applied, while force represents the amount of rotational force being applied to the fastener. By multiplying these two parameters, torque can be calculated. Vacuum and current, pressure and voltage, and luminance and pH are not relevant parameters for measuring torque.Rate this question:
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- 9.
What is the relative error of measurement when using a voltmeter whose measured value is 24.3V and true value 24V?
- A.
1.25%
- B.
0.013
- C.
0.014
- D.
0.012
Correct Answer
A. 1.25%Explanation
The relative error of measurement can be calculated by taking the absolute difference between the measured value and the true value, dividing it by the true value, and then multiplying by 100 to express it as a percentage. In this case, the absolute difference is 0.3V (24.3V - 24V), the true value is 24V, and the relative error is (0.3V / 24V) * 100 = 1.25%.Rate this question:
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- 10.
One step in a calibration procedure requires you to "tare" a balance (scale). What does this mean?
- A.
Put the largest weight you have on the balance
- B.
Remove the draft shield from the balance
- C.
Remove the pan from the balance
- D.
Make the balance read zero, even if something is on it
Correct Answer
D. Make the balance read zero, even if something is on itExplanation
Taring a balance means to reset the balance to zero, even if there is something already placed on it. This is done to ensure accurate measurements by subtracting the weight of the container or any other objects placed on the balance, allowing only the weight of the desired substance to be measured.Rate this question:
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Current Version
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Mar 21, 2023Quiz Edited by
ProProfs Editorial Team -
Jul 06, 2019Quiz Created by
AdewumiKoju
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