Aircraft Metals Technology Journeyman

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By A1cspyder
A
A1cspyder
Community Contributor
Quizzes Created: 1 | Total Attempts: 96
| Attempts: 96
SettingsSettings
Please wait...
  • 1/98 Questions

    What must be done to molten metal to form a cast product?

    • Pour it into a mold
    • Solution treat it
    • Cold work it
    • Anneal it
Please wait...
About This Quiz

This quiz tests knowledge on metal properties, including physical and mechanical properties, and metal composition in the context of metallurgy.

Aircraft Metals Technology Journeyman - Quiz

Quiz Preview

  • 2. 

    When a Rockwell tester is used for hardness testing, lack of surface uniformity results in

    • Soft spots

    • Hard spots

    • Errouneous readings

    • Errouneous minor load settings

    Correct Answer
    A. Errouneous readings
    Explanation
    When a Rockwell tester is used for hardness testing and there is a lack of surface uniformity, it can result in erroneous readings. This means that the hardness measurements obtained from the tester may not accurately reflect the true hardness of the material being tested. The lack of surface uniformity can cause variations in the depth of indentation made by the indenter, leading to inconsistent readings.

    Rate this question:

  • 3. 

    The terms of a fraction are the

    • Numerator and denominator

    • Denominator and multiple

    • Numerator and multiple

    • Divisor and multiple

    Correct Answer
    A. Numerator and denominator
    Explanation
    The terms of a fraction refer to the numerator and denominator. The numerator represents the number of equal parts being considered, while the denominator represents the total number of equal parts in the whole. These terms are essential in understanding and representing fractions accurately.

    Rate this question:

  • 4. 

    What is the least common denominator of 1/8, 5/16, and 3/4.

    • 12

    • 14

    • 16

    • 18

    Correct Answer
    A. 16
    Explanation
    The least common denominator is the smallest number that all the denominators can evenly divide into. In this case, the denominators are 8, 16, and 4. The smallest number that all three denominators can divide into is 16. Therefore, 16 is the least common denominator.

    Rate this question:

  • 5. 

    If you notice that the Brale penetrator is chipped, you should

    • File it

    • Hone it

    • Burnish it

    • Replace it

    Correct Answer
    A. Replace it
    Explanation
    If the Brale penetrator is chipped, it is necessary to replace it. A chipped penetrator can affect the accuracy and reliability of measurements taken with it. Using a chipped penetrator can lead to inaccurate results and potentially damage the surface being tested. Therefore, it is important to replace the chipped penetrator to ensure accurate and reliable measurements.

    Rate this question:

  • 6. 

    What is required to achieve hardness in ferrous metals?

    • Soaking time must be based on the alloying element

    • The material must contain sufficeint carbon content

    • The material must be heated to slightly below Ac1

    • All elements must go into solid austenitic solution

    Correct Answer
    A. The material must contain sufficeint carbon content
    Explanation
    To achieve hardness in ferrous metals, it is necessary for the material to have sufficient carbon content. Carbon is a key element in the formation of different phases in steel, such as martensite, which contributes to hardness. The presence of carbon allows for the transformation of the material's microstructure during heat treatment, resulting in increased hardness. Without sufficient carbon content, the material will not be able to achieve the desired level of hardness.

    Rate this question:

  • 7. 

    If a metal has a composition of 15% Cr, 1% C, 0.21% Fe and 20% Ni, what type of metal is it?

    • Ferrous

    • Nonferrous

    • Titanium alloy

    • Aluminum alloy

    Correct Answer
    A. Nonferrous
    Explanation
    The metal in question has a composition that includes chromium (Cr), carbon (C), iron (Fe), and nickel (Ni), but does not contain any significant amount of iron. Ferrous metals are those that contain iron, while nonferrous metals are those that do not. Therefore, based on the given composition, the metal in question is nonferrous.

    Rate this question:

  • 8. 

    Bringing a number to its root means finding the number of

    • Equal factors into which it can be added

    • Equal factors into which it can be divided

    • Odd factors into which it can be multiplied

    • Odd factors into which it can be subtracted

    Correct Answer
    A. Equal factors into which it can be divided
    Explanation
    To bring a number to its root means finding the number of equal factors into which it can be divided. This is because finding the root of a number involves finding a number that, when multiplied by itself, equals the original number. Therefore, the root of a number can be found by dividing the number into equal factors.

    Rate this question:

  • 9. 

    Which furnace component protects the heating elements from damamge and serves as the floor to the furnace?

    • Baffles

    • Grid rack

    • Insulation

    • Hearth plate

    Correct Answer
    A. Hearth plate
    Explanation
    The hearth plate is the correct answer because it serves as the floor to the furnace and protects the heating elements from damage. It acts as a barrier between the heating elements and the rest of the furnace, preventing any direct contact and potential damage. The hearth plate also helps to distribute heat evenly throughout the furnace, ensuring efficient heating.

    Rate this question:

  • 10. 

    The process of pulling heated metal through a series of dies to produce a desired shape is known as

    • Rolling

    • Forging

    • Piercing

    • Drawing

    Correct Answer
    A. Drawing
    Explanation
    Drawing is the correct answer because it refers to the process of pulling heated metal through a series of dies to produce a desired shape. This process is commonly used in the manufacturing industry to create long, thin objects such as wires or tubes. Rolling involves passing metal between two rollers to reduce its thickness, forging involves shaping metal by applying force, and piercing involves creating holes in metal by removing material.

    Rate this question:

  • 11. 

    What is an adverse effect of hardening steels?

    • Lowered corrosion resistance

    • Excessive grain growth

    • Malleabliity increases

    • Brittleness increases

    Correct Answer
    A. Brittleness increases
    Explanation
    Hardening steels can lead to an increase in brittleness. This occurs because the hardening process involves heating the steel to high temperatures and then rapidly cooling it, which can cause the formation of hard but brittle martensite. This increase in brittleness makes the steel more prone to fractures and less able to withstand impacts or deformations without breaking.

    Rate this question:

  • 12. 

    Raising 6 to the 3 power equals

    • 172

    • 202

    • 216

    • 236

    Correct Answer
    A. 216
    Explanation
    Raising 6 to the power of 3 means multiplying 6 by itself three times. So, 6^3 is equal to 6 * 6 * 6, which equals 216.

    Rate this question:

  • 13. 

    An oxidized thermocouple results in

    • Contaminated oven atmospheres

    • Incorrect temperature readings

    • Excessive heat loss

    • Stress on the leads

    Correct Answer
    A. Incorrect temperature readings
    Explanation
    When a thermocouple is oxidized, it means that its surface has reacted with oxygen in the air, forming a layer of oxide. This oxide layer can interfere with the accurate measurement of temperature, causing incorrect temperature readings. The oxide layer acts as an insulator, reducing the thermocouple's ability to accurately sense and transmit temperature changes. Therefore, an oxidized thermocouple can lead to inaccurate temperature readings.

    Rate this question:

  • 14. 

    To maintain an atmosphere around the thermocouple equal tot hatt of theair at room temperature, heat-treating furnaces require

    • Pyrometers

    • Extension leads

    • Protective tubes

    • Inert atmospheres

    Correct Answer
    A. Protective tubes
    Explanation
    Heat-treating furnaces require protective tubes to maintain an atmosphere around the thermocouple equal to that of the air at room temperature. Protective tubes act as a barrier, preventing the thermocouple from coming into direct contact with the high temperatures and corrosive gases inside the furnace. This helps to protect the thermocouple from damage and ensures accurate temperature measurements. Without protective tubes, the thermocouple would be exposed to the harsh conditions inside the furnace, leading to inaccurate readings and potential failure of the thermocouple.

    Rate this question:

  • 15. 

    To prevent cracking when cold working metal

    • Slightly stress relieve or partially anneal it

    • Ensureit is at maximum depth hardness

    • Remove impurities from the grains

    • Temper it to remove strain

    Correct Answer
    A. Slightly stress relieve or partially anneal it
    Explanation
    To prevent cracking when cold working metal, it is necessary to slightly stress relieve or partially anneal it. This process helps to reduce the internal stresses that build up during cold working, which can lead to cracking or failure of the metal. By applying controlled heat treatment, the metal is allowed to relax and redistribute the internal stresses, making it less prone to cracking and improving its overall strength and ductility.

    Rate this question:

  • 16. 

    When a steel part of unequal cross section is heat treated, the soaking period is determined by the

    • Mechanical properties of the part

    • Physical properties of the part

    • Heaviest cross section

    • Lightest cross section

    Correct Answer
    A. Heaviest cross section
    Explanation
    The soaking period during heat treatment of a steel part of unequal cross section is determined by the heaviest cross section. This is because the heaviest cross section takes the longest time to reach the desired temperature throughout its entire thickness. Soaking is necessary to ensure that the entire part reaches a uniform temperature, allowing for proper transformation and achieving the desired mechanical properties.

    Rate this question:

  • 17. 

    When heat treating a part of uneven cross section, what is the quenching procedure?

    • Immerse both sections simultaneously.

    • Immerse heavier section first

    • Immerse lighter section first

    • There is no set procedure

    Correct Answer
    A. Immerse heavier section first
    Explanation
    When heat treating a part of uneven cross section, it is important to immerse the heavier section first during the quenching procedure. This is because the heavier section will retain heat for a longer period of time, and by immersing it first, it ensures that both sections cool down at a similar rate. If the lighter section is immersed first, it may cool down too quickly, causing uneven cooling and potentially leading to distortion or other issues in the part. By immersing the heavier section first, it allows for more uniform cooling and helps to prevent any potential problems.

    Rate this question:

  • 18. 

    Reduce the fraction 12/28 to its lowest terms

    • 6/14

    • 4/12

    • 3/7

    • 1/2

    Correct Answer
    A. 3/7
    Explanation
    To reduce a fraction to its lowest terms, we need to find the greatest common divisor (GCD) of the numerator and denominator and then divide both by this GCD. In this case, the GCD of 12 and 28 is 4. Dividing both numerator and denominator by 4 gives us 3/7, which is the lowest term of the fraction 12/28.

    Rate this question:

  • 19. 

    If a metal has a composition of 43% Fe, 1 % C, and 0.2% Ni, what type of metal is it?

    • Ferrous

    • Nonferrous

    • Nickel alloy

    • Titanium alloy

    Correct Answer
    A. Ferrous
    Explanation
    The metal with a composition of 43% Fe, 1% C, and 0.2% Ni is considered ferrous. This is because "ferrous" refers to metals that contain iron (Fe), and in this case, the metal has a significant amount of iron in its composition (43%). The presence of carbon (C) and nickel (Ni) does not change the fact that it is a ferrous metal.

    Rate this question:

  • 20. 

    The purpose of case hardening is to produce

    • A hard case over a tough core

    • A tough case over a hard core

    • Maximum toughness

    • Maximum hardness

    Correct Answer
    A. A hard case over a tough core
    Explanation
    Case hardening is a heat treatment process used to increase the hardness of the surface of a material while maintaining toughness in the core. This is achieved by adding carbon to the surface of the material and then heating it to a high temperature, followed by rapid cooling. The result is a hard outer layer, or "case," that provides resistance to wear and abrasion, while the core remains tough and durable. This combination of a hard case over a tough core is desirable in applications where the material needs to withstand both high impact and wear.

    Rate this question:

  • 21. 

    The T designator for aluminum alloys indicates the

    • Treatment process

    • Amount of hardness

    • Amount of cold working

    • Amount of modifications

    Correct Answer
    A. Treatment process
    Explanation
    The T designator for aluminum alloys indicates the treatment process. This means that the T designator is used to identify the specific heat treatment process that has been applied to the aluminum alloy. Heat treatment processes can include processes such as solution heat treatment, precipitation hardening, or annealing, among others. The T designator helps to classify and specify the properties and characteristics of the aluminum alloy based on the specific treatment process that has been used.

    Rate this question:

  • 22. 

    Metal that is worked after casting is considered

    • Machined

    • Wrought

    • Molded

    • Welded

    Correct Answer
    A. Wrought
    Explanation
    The term "wrought" refers to metal that has been shaped or formed by hammering, rolling, or other mechanical processes after it has been cast. This process of working the metal after casting helps to improve its strength, durability, and overall quality. Therefore, "wrought" is the correct term to describe metal that has been worked after casting.

    Rate this question:

  • 23. 

    When three atoms of iron and one atom of carbon chemically unite, the resulting compound is known as

    • Fe3C

    • FeE3

    • Fe3

    • FC3

    Correct Answer
    A. Fe3C
    Explanation
    When three atoms of iron and one atom of carbon chemically unite, they form a compound known as Fe3C. This compound is also called iron carbide or cementite. It is a hard and brittle compound that is commonly found in steel alloys. The Fe3C compound has a crystal structure that consists of iron atoms surrounded by carbon atoms. It is an important component in the microstructure of steel and contributes to its strength and hardness.

    Rate this question:

  • 24. 

    A metal's resistance to a high number of cyclic loads is known as

    • Compressive strength

    • Tensile strength

    • Fatigued strength

    • Shear strength

    Correct Answer
    A. Fatigued strength
    Explanation
    Fatigued strength refers to a metal's ability to withstand repeated cyclic loads without failure. It is a measure of the material's resistance to fatigue, which occurs when a metal is subjected to alternating stress over time. Fatigue failure can lead to cracks or fractures in the metal, making it important for materials to have a high fatigued strength to ensure durability and reliability under cyclic loading conditions. Compressive strength, tensile strength, and shear strength, on the other hand, refer to a metal's ability to withstand specific types of loads, but not necessarily cyclic ones.

    Rate this question:

  • 25. 

    What is the weight of the minor load when testing for hardness using a Rockwell tester?

    • 5 kg.

    • 10 kg.

    • 60 kg.

    • 150 kg.

    Correct Answer
    A. 10 kg.
    Explanation
    The weight of the minor load when testing for hardness using a Rockwell tester is 10 kg. This weight is used to initially penetrate the surface of the material being tested.

    Rate this question:

  • 26. 

    What scale is used on a Rockwell hardness tester for testing metals of unknown hardness?

    • A.

    • B.

    • C.

    • E.

    Correct Answer
    A. C.
    Explanation
    The Rockwell hardness tester uses the C scale to test metals of unknown hardness. This scale is commonly used for softer metals such as aluminum, copper, and brass. The C scale measures the depth of penetration of a diamond cone or steel ball into the material, providing a hardness value that can be compared to a standard scale. This allows for accurate and consistent testing of metals to determine their hardness properties.

    Rate this question:

  • 27. 

    An additional advantage to nitrided parts is that they have increased

    • Corrosion resistance

    • Machinability

    • Weldability

    • Malleability

    Correct Answer
    A. Corrosion resistance
    Explanation
    Nitrided parts have an additional advantage of increased corrosion resistance. This means that the parts are less likely to undergo corrosion or rust when exposed to moisture or other corrosive substances. This increased resistance to corrosion can prolong the lifespan of the parts and ensure their functionality over a longer period of time.

    Rate this question:

  • 28. 

    After descaling martensitic stainless steels by acid pickling, baking helps

    • Remove the effects of cold working

    • Remove hydroge embrittlement

    • Minimize warpage

    • Temper the metal

    Correct Answer
    A. Remove hydroge embrittlement
    Explanation
    After descaling martensitic stainless steels by acid pickling, baking helps to remove hydrogen embrittlement. Hydrogen embrittlement is a phenomenon where hydrogen atoms diffuse into the metal lattice, causing it to become brittle and prone to cracking. Baking the metal after pickling helps to drive out the trapped hydrogen, reducing the risk of embrittlement and ensuring the structural integrity of the steel.

    Rate this question:

  • 29. 

    An 18-inch gear meshes with a 6 inch gear. If the large gear has 72 teeth, how many teeth does the small gear have?

    • 12

    • 24

    • 36

    • 48

    Correct Answer
    A. 24
    Explanation
    The ratio of the number of teeth on two gears is equal to the ratio of their diameters. In this case, the large gear has a diameter of 18 inches and 72 teeth, while the small gear has a diameter of 6 inches and an unknown number of teeth. By setting up a proportion, we can solve for the number of teeth on the small gear. The proportion would be 18/6 = 72/x, where x represents the number of teeth on the small gear. Cross-multiplying and solving for x gives us x = 24. Therefore, the small gear has 24 teeth.

    Rate this question:

  • 30. 

    What metal identifictaion system uses a letter designator to seperate metals into 18 different family groupings?

    • AISI

    • JAN specifications

    • Federal specification numerics code

    • UNS

    Correct Answer
    A. UNS
    Explanation
    UNS (Unified Numbering System) is a metal identification system that uses a letter designator to separate metals into 18 different family groupings. It provides a standardized method for identifying and classifying various types of metals based on their chemical composition and properties. This system is widely used in the metal industry to ensure consistency and accuracy in metal identification and classification.

    Rate this question:

  • 31. 

    When a metal registers Rc53 on the Rockwell scale, it is at

    • Maximum hardness

    • Maximum toughness

    • Minimum yield point

    • Minimum malleability

    Correct Answer
    A. Maximum hardness
    Explanation
    When a metal registers Rc53 on the Rockwell scale, it indicates that the metal has reached its maximum hardness. The Rockwell scale is used to measure the hardness of materials, with higher values indicating greater hardness. Therefore, Rc53 signifies that the metal is extremely hard and resistant to deformation.

    Rate this question:

  • 32. 

    When heat treating clad aluminum, oversoaking results in

    • Lossof strength

    • Gain of strength

    • Loss of corrosion resistance

    • Improvement in conductivity

    Correct Answer
    A. Loss of corrosion resistance
    Explanation
    When heat treating clad aluminum, oversoaking refers to exposing the material to high temperatures for an extended period. This can lead to the diffusion of alloying elements from the core to the cladding, resulting in a depletion of these elements in the cladding layer. As a result, the cladding becomes more susceptible to corrosion, leading to a loss of corrosion resistance.

    Rate this question:

  • 33. 

    The amount of hardness or softness you can achieve for carbon and low alloy steels is dictated by the

    • Soaking time

    • Carbon content

    • Quench medium

    • Treatment process

    Correct Answer
    A. Carbon content
    Explanation
    The amount of hardness or softness that can be achieved for carbon and low alloy steels is determined by the carbon content. Carbon is the main alloying element in these steels and it influences their mechanical properties, including hardness. Higher carbon content generally leads to higher hardness, while lower carbon content results in lower hardness. Therefore, the carbon content plays a crucial role in determining the hardness or softness of these steels.

    Rate this question:

  • 34. 

    Reduce the fraction 8/6 to a mixed number.

    • 1 1/3

    • 1 1/2

    • 2 1/3

    • 2 1/2

    Correct Answer
    A. 1 1/3
    Explanation
    To reduce the fraction 8/6 to a mixed number, we divide the numerator (8) by the denominator (6). The quotient is 1 and the remainder is 2. This means that the mixed number is 1 2/6, which can be simplified to 1 1/3 by dividing both the numerator and denominator by their greatest common divisor, which is 2. Therefore, the correct answer is 1 1/3.

    Rate this question:

  • 35. 

    The mechanical properties of a metal are determined by the

    • Grain structure

    • Alloying elements

    • Chemical analysis

    • Chemical compound

    Correct Answer
    A. Grain structure
    Explanation
    The mechanical properties of a metal are determined by its grain structure. The grain structure refers to the arrangement of individual grains or crystals within the metal. The size, shape, and orientation of these grains can affect various mechanical properties such as strength, ductility, and toughness. For example, metals with a finer grain structure tend to be stronger and more resistant to deformation, while those with a larger grain structure may exhibit lower strength and increased susceptibility to fracture. Therefore, understanding and controlling the grain structure is crucial in designing and manufacturing metals with desired mechanical properties.

    Rate this question:

  • 36. 

    What type of penetrator may you have if you get consistantly low readings with the Rockwell tester?

    • Flattened Brale

    • Chipped Brale

    • Flattened ball

    • Chipped ball

    Correct Answer
    A. Chipped Brale
    Explanation
    If you consistently get low readings with the Rockwell tester, it suggests that the penetrator being used is not sharp enough to properly indent the material being tested. A chipped Brale penetrator would have a damaged tip, resulting in a less effective indentation and therefore lower readings.

    Rate this question:

  • 37. 

    Would you use a nitrogen atmosphere for hardening stainless steel? why?

    • Yes, aids in chemical properties

    • Yes, to case-harden high carbon steels

    • No, may result in surface blistering

    • No, produces undesirable properties in metals

    Correct Answer
    A. No, produces undesirable properties in metals
    Explanation
    Using a nitrogen atmosphere for hardening stainless steel would not be recommended because it produces undesirable properties in metals. Nitrogen can cause surface blistering, which is not desirable in the hardening process. Additionally, nitrogen may introduce impurities or alter the chemical composition of the steel, leading to negative effects on its overall properties. Therefore, it is best to avoid using a nitrogen atmosphere for hardening stainless steel.

    Rate this question:

  • 38. 

    When heat treating, using a reactive atmosphere results in chemical

    • Inertness

    • Blending

    • Reduction

    • Movement

    Correct Answer
    A. Blending
    Explanation
    When heat treating, using a reactive atmosphere can result in blending. This means that the reactive atmosphere combines with the material being treated, causing a chemical reaction. This blending process can lead to desired changes in the material's properties, such as improved hardness or increased strength. Reactive atmospheres are often used in heat treatment processes to achieve specific outcomes by altering the chemical composition of the material.

    Rate this question:

  • 39. 

    Physical properties in metals are the properties that are

    • Changed by either heat treatment or cold working

    • Not changed by heat treatment or cold working

    • Changed by cold working only

    • Changed by heat treating only

    Correct Answer
    A. Not changed by heat treatment or cold working
    Explanation
    Physical properties in metals are not changed by heat treatment or cold working. Heat treatment involves heating and cooling the metal to alter its microstructure and improve its mechanical properties, such as hardness and strength. Cold working, on the other hand, involves deforming the metal at room temperature to increase its strength and hardness. However, these processes do not change the inherent physical properties of the metal, such as its density, melting point, electrical conductivity, and thermal conductivity. These properties remain constant regardless of heat treatment or cold working.

    Rate this question:

  • 40. 

    Austenitic stainless steels are hardened by

    • Annealing

    • Hot rolling

    • Cold working

    • Low drawing

    Correct Answer
    A. Cold working
    Explanation
    Austenitic stainless steels are hardened by cold working. Cold working involves subjecting the material to mechanical deformation at temperatures below its recrystallization temperature. This process increases the strength and hardness of the steel while maintaining its corrosion resistance. Cold working induces dislocations and strain in the crystal structure, leading to a denser and stronger material. Annealing, hot rolling, and low drawing are not methods used for hardening austenitic stainless steels.

    Rate this question:

  • 41. 

    For hardness and strength, the most important element in aluminum alloys is

    • Copper

    • Carbon

    • Magnesium

    • Columbium

    Correct Answer
    A. Copper
    Explanation
    Copper is the most important element in aluminum alloys for hardness and strength. When added to aluminum, copper forms a solid solution, strengthening the alloy by creating a fine dispersion of copper atoms within the aluminum matrix. This results in improved mechanical properties such as increased hardness and strength. Additionally, copper also enhances the alloy's resistance to corrosion and improves its thermal conductivity.

    Rate this question:

  • 42. 

    Overage of aluminum alloys results in

    • Higher corrosion resistance

    • Lower formability

    • Higher strength

    • Lower strength

    Correct Answer
    A. Lower strength
    Explanation
    An overage of aluminum alloys refers to the process of aging the alloy beyond its peak strength. This causes the alloy to become overaged and results in lower strength. Aging is a heat treatment process that improves the strength of aluminum alloys by allowing the formation of fine precipitates. However, if the aging process is prolonged, the precipitates become coarser, leading to a decrease in strength. Therefore, an overage of aluminum alloys leads to lower strength.

    Rate this question:

  • 43. 

    What property makes aluminum bronzes valuablein a hazardous environment?

    • High tensile strength

    • Corrosion resistance

    • Spark resistance

    • Wear resistance

    Correct Answer
    A. Spark resistance
    Explanation
    Aluminum bronzes are valuable in a hazardous environment due to their spark resistance. This property means that they do not produce sparks when struck against a hard surface, making them ideal for use in environments where sparks could potentially ignite flammable substances or cause explosions. This makes aluminum bronzes a safer choice in industries such as mining, oil and gas, and chemical processing where the risk of fire or explosion is high.

    Rate this question:

  • 44. 

    If you suspect that the beryllium copper alloy has been incorrectly solution treated, you should

    • Age it

    • Heat it

    • Anneal it

    • Temper it

    Correct Answer
    A. Anneal it
    Explanation
    If you suspect that the beryllium copper alloy has been incorrectly solution treated, the best course of action would be to anneal it. Annealing involves heating the material to a specific temperature and then slowly cooling it, which helps to relieve any internal stresses and restore the alloy to its original state. This process can help to correct any issues that may have occurred during the solution treatment, ensuring the alloy's desired properties are achieved.

    Rate this question:

  • 45. 

    What is the result when the fraction 1/8 is subtracted from the sum of the fractions 3/4 and 5/32?

    • 29/64

    • 25/32

    • 12/16

    • 11/16

    Correct Answer
    A. 25/32
    Explanation
    To find the result when subtracting 1/8 from the sum of 3/4 and 5/32, we first need to find the sum of 3/4 and 5/32. We can convert 3/4 to have a common denominator with 5/32, which is 32. So, 3/4 becomes 24/32. Adding 24/32 and 5/32 gives us a total of 29/32. Then, we subtract 1/8 from 29/32. To have a common denominator, we convert 1/8 to 4/32. Subtracting 4/32 from 29/32 gives us 25/32. Therefore, the result is 25/32.

    Rate this question:

  • 46. 

    An example of a cube root symbol is

    • \/

    • 1\/

    • 2\/

    • 3\/

    Correct Answer
    A. 3\/
    Explanation
    The given symbol \/ represents the cube root. In this case, the number 3 is inside the symbol, indicating that it is the cube root of a number. Therefore, the correct answer is 3\/.

    Rate this question:

  • 47. 

    The main difference between the SAE and AISI coding system is

    • AISI prefix identifies the chemical composition only

    • SAE prefix identifies the physical composition only

    • AISI prefix indicates the manufacturing process

    • SAE prefix indicates the manufacturing process

    Correct Answer
    A. AISI prefix indicates the manufacturing process
    Explanation
    The given answer is incorrect. The main difference between the SAE (Society of Automotive Engineers) and AISI (American Iron and Steel Institute) coding systems is that the AISI prefix identifies the chemical composition of the material, while the SAE prefix identifies the physical composition or properties of the material. The AISI coding system is primarily used for steel and iron alloys, while the SAE coding system is used for a wider range of materials including metals, plastics, and rubber.

    Rate this question:

  • 48. 

    To prevent the formation of pearlite when hardening carbon steel, cool it below 1000 degrees F in less than

    • 1/4 second

    • 1/2 second

    • 1 second

    • 2 seconds

    Correct Answer
    A. 1 second
    Explanation
    To prevent the formation of pearlite when hardening carbon steel, it is necessary to cool it rapidly. Cooling the steel below 1000 degrees F in less than 1 second ensures that there is not enough time for the pearlite structure to form. Pearlite is a mixture of ferrite and cementite that forms during slow cooling, and it can reduce the hardness and strength of the steel. By cooling the steel rapidly, the formation of pearlite is avoided, resulting in a harder and stronger material.

    Rate this question:

  • 49. 

    When quenching a heat-treated part in a liquid medium, stirring ahould be

    • Induced to prevent warpage

    • Minimized to prevent warpage

    • Induced to create steam pockets

    • Minimized to create steam pockets

    Correct Answer
    A. Minimized to prevent warpage
    Explanation
    When quenching a heat-treated part in a liquid medium, minimizing stirring is necessary to prevent warpage. Stirring can cause uneven cooling, leading to internal stresses and distortion in the part. By minimizing stirring, the heat is evenly distributed, reducing the risk of warpage and ensuring the part maintains its desired shape and dimensions.

    Rate this question:

Quiz Review Timeline (Updated): Nov 9, 2023 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Nov 09, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Mar 02, 2009
    Quiz Created by
    A1cspyder
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.