Do you think you know enough about security issues in C code? Can you think with the mind of a hacker?
Test your knowledge with our interactive quiz! Check how much you know, share the results, and help your colleagues learn more about secure coding. Simply click on the "start" button. It's fun and easy - so don't wait!
%n %08x %08x %08x %08x %08x
%08x %08x %08x %08x %08x %s
%s %08x %08x %08x %08x %08x
%100s
%08x %08x %08x %08x %08x %08x
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9
10
11
12
13
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I = 2147483648, j = -2147483649, k = 2147483648, u = 4294967296, v = -1
I = -2147483648, j = 2147483647, k = 2147483648, u = 0, v = 4294967295
I = 0, j = 0, k = 2147483648, u = 0, v = 4294967295
I = -2147483648, j = 2147483647, k = -2147483648, u = 0, v = 4294967295
I = -2147483648, j = 2147483647, k = 0, u = 0, v = 4294967295
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There is no reliable way to protect against format string vulnerabilities.
Injected shellcode can be reliably identified by intrusion detection software.
Proper use of secure integer libraries eliminates integer overflow vulnerabilities.
Using data execution prevention, address space layout randomization and stack smashing protection at the same time provides complete protection against buffer overflow exploits.
Using strncpy and strncat instead of strcpy and strcat guarantees error-free operation.
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00000000000000000000000000000000b6104000
00000000000000000000000000000000004010b6
20202020202020202020202020202020004010b6
2020202020202020202020202020202020b61040
20202020202020202020202020202020b6104000
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A: d1len + d2len
A: d1len
A: (d2len + 2
A: d1len + d2len + 2
A: (d2len
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0x08
0x0A
0x15
0x28
0x2D
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Unicode characters may be used to bypass black-list filtering
In every encoding form, the size of Unicode characters may differ from each other
The length() of a Unicode string may be different from its size()
Unicode strings cannot be printed easily out on the screen
Directional control characters such as U+202E may be exploited
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Char pwd[37], n[ll+1];
#define ll 13
Void s(char *u) {strncpy(n,u,ll-1); printf(n);}
Void s(char *u) {strncpy(n,u,11); printf(“%s”, n);}
Void s(char *u) {strncpy(n,u,ll-1); cout
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