1.
What is the hexadecimal equivalent of the Ethernet address
01011010 00010001 01010101 00011000 10101010 00001111?
Correct Answer
A. 5A-11-55-18-AA-0F
Explanation
The given answer, 5A-11-55-18-AA-0F, is the correct hexadecimal equivalent of the Ethernet address 01011010 00010001 01010101 00011000 10101010 00001111. Each group of four binary digits (bits) in the Ethernet address corresponds to one hexadecimal digit. The binary digits are converted to their equivalent hexadecimal values, and then combined to form the hexadecimal address. In this case, the conversion results in the hexadecimal digits 5A-11-55-18-AA-0F.
2.
Which of the following device does multi-layer packet forwarding?
Correct Answer
A. Router
Explanation
A router is the correct answer because it is a networking device that operates at the network layer (layer 3) of the OSI model. It uses information from the network layer headers, such as IP addresses, to make decisions on how to forward packets between different networks. Routers have the ability to analyze and make decisions based on multiple layers of the packet, allowing them to efficiently route packets to their intended destinations.
3.
An ARP request is unicast; An ARP reply is broadcast.
Correct Answer
B. False
Explanation
An ARP request is broadcast, not unicast, because it is sent to all devices on the local network to determine the MAC address of a specific IP address. On the other hand, an ARP reply is unicast, as it is sent back only to the device that made the request, providing it with the MAC address it was looking for. Therefore, the correct answer is False.
4.
F the data unit is 111111, the divisor 1010, and the remainder 110, what is the dividend at the receiver?
Correct Answer
A. 111111110
Explanation
The dividend at the receiver can be calculated by adding the remainder to the data unit. In this case, the remainder is 110 and the data unit is 111111. Adding them together gives us 111111110, which is the dividend at the receiver.
5.
In OSPF protocol, What is the main scheme?
Correct Answer
B. All routers have the same link state database.
Explanation
In OSPF protocol, all routers have the same link state database. This means that every router within the OSPF network maintains an identical copy of the link state database, which contains information about the network topology, link states, and routing information. This allows all routers to have a consistent view of the network, enabling them to make informed routing decisions based on the most up-to-date information. By having a shared link state database, OSPF ensures that all routers have a synchronized understanding of the network, promoting efficient and accurate routing.
6.
____________ operates only at the physical and data-link layer
Correct Answer
C. Frame Relay
Explanation
Frame Relay is a wide area network (WAN) technology that operates only at the physical and data-link layer of the OSI model. It provides a connection-oriented service, where data is divided into frames and transmitted over virtual circuits. Frame Relay does not have network layer functionality, which means it does not perform routing or addressing like ICMP or ATM. Stop-and-Wait ARQ is a flow control mechanism used in data communication, but it operates at the data-link layer. Therefore, the correct answer is Frame Relay.
7.
One of the well-known ports used by TCP is:
Correct Answer
A. HTTP
Explanation
HTTP (Hypertext Transfer Protocol) is a well-known port used by TCP (Transmission Control Protocol). It is the protocol used for transmitting and receiving web pages and other resources on the internet. HTTP operates on port 80 and is responsible for establishing a connection between a client (web browser) and a server (web server) to exchange data. It allows for the retrieval and display of web content, making it an essential protocol for browsing the internet.
8.
The number of addresses in class C is smaller than the needs of most organizations.
Correct Answer
A. True
Explanation
The statement is true because class C addresses provide a smaller range of IP addresses compared to class A and class B addresses. Class C addresses have a default subnet mask of 255.255.255.0, which allows for a maximum of 254 usable addresses. This limited number of addresses may not be sufficient for larger organizations that require more IP addresses to accommodate their network infrastructure, devices, and users. Therefore, most organizations with higher needs would require class A or class B addresses, which offer a larger pool of available addresses.
9.
In Stop-and-Wait ARQ:
Correct Answer
D. Numbering frames prevents the retaining of duplicate frames.
Explanation
In Stop-and-Wait ARQ, numbering frames prevents the retaining of duplicate frames. This is because each frame is assigned a unique sequence number by the sender. When the receiver receives a frame, it checks the sequence number to ensure that it is not a duplicate. If a duplicate frame is detected, it is discarded to avoid unnecessary processing and duplication of data. This numbering mechanism helps in maintaining the integrity and reliability of the data transmission.
10.
Class C network: 192.168.9.0
Mask: 255.255.255.224
What is the subnets range for the above network?
Correct Answer
A. 192.168.9.0-224
Explanation
The subnet range for the given Class C network with a mask of 255.255.255.224 is 192.168.9.0-224. This is because the subnet mask of 255.255.255.224 allows for 30 usable host addresses in each subnet. The range starts from the network address 192.168.9.0 and ends at the broadcast address 192.168.9.31, with the usable addresses ranging from 192.168.9.1 to 192.168.9.30.