Gibilisco - The Bipolar Transistor
A bipolar transistor is a semiconductor device commonly used for amplification. The device can amplify analog or digital signals. Test out your understanding on this devise by taking up the quick quiz below and note down what you need to read more on. Give it a try and all the best!
- 1.
In a PNP circuit, the collector
- A.
Has an arrow pointing inward.
- B.
Is positive with respect to the emitter.
- C.
Is biased at a small fraction of the base bias.
- D.
Is negative with respect to the emitter.
Correct Answer
D. Is negative with respect to the emitter.Explanation
In a PNP circuit, the collector is negative with respect to the emitter. This is because in a PNP transistor, the base-emitter junction is forward biased, allowing current to flow from the emitter to the base. As a result, the collector-emitter junction is reverse biased, causing the collector to be negative with respect to the emitter.Rate this question:
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- 2.
In many cases, a PNP transistor can be replaced with an NPN device and the circuit will dothe same thing, provided that
- A.
The power supply or battery polarity is reversed.
- B.
The collector and emitter leads are interchanged.
- C.
The arrow is pointing inward.
- D.
Forget it! A PNP transistor can never be replaced with an NPN transistor.
Correct Answer
A. The power supply or battery polarity is reversed.Explanation
When a PNP transistor is replaced with an NPN transistor, the circuit will still function the same way as long as the power supply or battery polarity is reversed. This is because the PNP and NPN transistors have opposite polarities, so reversing the polarity of the power supply or battery compensates for the difference in transistor types. The collector and emitter leads being interchanged or the arrow pointing inward are not relevant factors in determining whether the circuit will still work.Rate this question:
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- 3.
A bipolar transistor has
- A.
Three P-N junctions.
- B.
Three semiconductor layers.
- C.
Two N-type layers around a P-type layer.
- D.
A low avalanche voltage.
Correct Answer
B. Three semiconductor layers.Explanation
A bipolar transistor consists of three semiconductor layers, namely the emitter, base, and collector. These layers are typically made of different materials, such as N-type and P-type semiconductors, which form two P-N junctions. The three layers allow for the transistor's operation by controlling the flow of current. The emitter is heavily doped to emit majority carriers, while the base is lightly doped to control the current flow. The collector collects the majority carriers, completing the transistor's functionality. The statement about the low avalanche voltage is not applicable to the description of a bipolar transistor.Rate this question:
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- 4.
In the dual-diode model of an NPN transistor, the emitter corresponds to
- A.
The point where the cathodes are connected together.
- B.
The point where the cathode of one diode is connected to the anode of the other.
- C.
The point where the anodes are connected together.
- D.
Either of the diode cathodes.
Correct Answer
D. Either of the diode cathodes.Explanation
In the dual-diode model of an NPN transistor, the emitter corresponds to either of the diode cathodes. This is because in an NPN transistor, the emitter is the terminal through which the majority charge carriers (electrons) flow out of the transistor. In the dual-diode model, the emitter is represented by one of the diode cathodes, as it is the point from which the majority carriers are emitted. Therefore, the emitter can be connected to either of the diode cathodes.Rate this question:
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- 5.
The current through a transistor depends on
- A.
EC.
- B.
EB relative to EC.
- C.
IB.
- D.
More than one of the above.
Correct Answer
D. More than one of the above.Explanation
The current through a transistor depends on more than one of the above factors. The current can be influenced by the collector-emitter voltage (EC), the base-emitter voltage relative to the collector-emitter voltage (EB relative to EC), and the base current (IB). All three factors play a role in determining the current flowing through the transistor.Rate this question:
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- 6.
With no signal input, a bipolar transistor would have the least IC when
- A.
The emitter is grounded.
- B.
The E-B junction is forward-biased.
- C.
The E-B junction is reverse-biased.
- D.
The E-B current is high.
Correct Answer
C. The E-B junction is reverse-biased.Explanation
When the E-B junction of a bipolar transistor is reverse-biased, it creates a depletion region that prevents the flow of current. This means that there will be minimal or no current flowing through the transistor, resulting in the least IC (collector current) when there is no signal input.Rate this question:
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- 7.
When a transistor is conducting as much as it can, it is said to be
- A.
In a state of cutoff.
- B.
In a state of saturation.
- C.
In a state of reverse bias.
- D.
In a state of avalanche breakdown.
Correct Answer
B. In a state of saturation.Explanation
When a transistor is conducting as much as it can, it is said to be in a state of saturation. In this state, the transistor is fully turned on and allows maximum current flow between its collector and emitter terminals. The transistor operates in its active region and acts as a closed switch, allowing the passage of current with minimal resistance. This state is opposite to the cutoff state where the transistor is fully turned off and does not allow any current flow. Reverse bias and avalanche breakdown are unrelated to the transistor's conduction state.Rate this question:
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- 8.
In a common emitter circuit, the gain bandwidth product is
- A.
The frequency at which the gain is 1.
- B.
The frequency at which the gain is 0.707 times its value at 1 MHz.
- C.
The frequency at which the gain is greatest.
- D.
The difference between the frequency at which the gain is greatest, and the frequency at which the gain is 1.
Correct Answer
A. The frequency at which the gain is 1.Explanation
The gain bandwidth product is defined as the product of the gain of a device and the bandwidth over which that gain is maintained. In a common emitter circuit, the gain bandwidth product is the frequency at which the gain is 1. This means that at this frequency, the gain of the circuit drops to unity or 0 dB. This frequency is important because it represents the upper limit of the frequency range over which the circuit can amplify signals effectively.Rate this question:
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- 9.
The bipolar-transistor configuration most often used for matching a high input impedance toa low output impedance puts signal ground at
- A.
The emitter.
- B.
The base.
- C.
The collector.
- D.
Any point; it doesn’t matter.
Correct Answer
C. The collector.Explanation
In a bipolar-transistor configuration, the collector is often used to match a high input impedance to a low output impedance. This is because the collector is typically connected to the load, which requires a low output impedance to effectively transfer the signal. By placing signal ground at the collector, the input impedance can be matched to the load impedance, resulting in efficient signal transfer.Rate this question:
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- 10.
The output is in phase with the input in
- A.
A common emitter circuit.
- B.
A common base circuit.
- C.
A common collector circuit.
- D.
More than one of the above.
Correct Answer
D. More than one of the above.Explanation
The output being in phase with the input means that the output signal follows the same pattern as the input signal, without any phase shift or inversion. In a common emitter circuit, the output voltage is in phase with the input voltage. Similarly, in a common base circuit, the output voltage is also in phase with the input voltage. In a common collector circuit, the output voltage is in phase with the input voltage as well. Therefore, the correct answer is "more than one of the above" because all three circuit configurations can have an output that is in phase with the input.Rate this question:
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- 11.
The greatest possible amplification is obtained in
- A.
A common emitter circuit.
- B.
A common base circuit.
- C.
A common collector circuit.
- D.
More than one of the above.
Correct Answer
A. A common emitter circuit.Explanation
A common emitter circuit provides the greatest possible amplification because it has a high voltage gain and a high current gain. In this configuration, the input signal is applied to the base-emitter junction, while the output is taken from the collector-emitter junction. This allows for a large voltage swing and a significant increase in signal amplitude. Additionally, the common emitter circuit offers a relatively high input impedance and a low output impedance, making it suitable for driving loads and interfacing with other circuits.Rate this question:
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- 12.
The input is applied to the collector in
- A.
A common emitter circuit.
- B.
A common base circuit.
- C.
A common collector circuit.
- D.
None of the above.
Correct Answer
D. None of the above.Explanation
The correct answer is "none of the above" because the question is asking about the input applied to the collector in a circuit, and none of the given options accurately describe this. The input is typically applied to the base of the transistor in a common emitter circuit, the emitter in a common base circuit, and the emitter in a common collector circuit. Therefore, none of the given options correctly describe the input applied to the collector.Rate this question:
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- 13.
The configuration noted for its stability in RF power amplifiers is the
- A.
Common emitter circuit.
- B.
Common base circuit.
- C.
Common collector circuit.
- D.
Emitter follower circuit.
Correct Answer
B. Common base circuit.Explanation
The common base circuit is known for its stability in RF power amplifiers. In this configuration, the input signal is applied to the emitter terminal, while the output is taken from the collector terminal. This arrangement provides a high voltage gain and low input impedance, making it suitable for impedance matching and minimizing signal distortion. Additionally, the common base circuit exhibits good high-frequency response and low noise, making it ideal for RF applications where stability is crucial.Rate this question:
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- 14.
In a common base circuit, the output is taken from
- A.
The emitter.
- B.
The base.
- C.
The collector.
- D.
More than one of the above.
Correct Answer
C. The collector.Explanation
In a common base circuit, the output is taken from the collector. This is because in a common base configuration, the input is applied to the emitter and the output is taken from the collector. The emitter current controls the collector current, and the collector current is the output current of the circuit. Therefore, the correct answer is the collector.Rate this question:
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- 15.
Suppose that the input signal to a transistor amplifier results in saturation during part of thecycle. This produces
- A.
The greatest possible amplification.
- B.
Reduced efficiency.
- C.
Avalanche effect.
- D.
Nonlinear output impedance.
Correct Answer
B. Reduced efficiency.Explanation
When the input signal to a transistor amplifier results in saturation during part of the cycle, it means that the transistor is being overdriven and cannot amplify the signal accurately. This leads to distortion in the output signal and reduced efficiency of the amplifier. Saturation occurs when the transistor is unable to accurately reproduce the input signal due to limitations in its operating range. As a result, the amplifier's performance is compromised, leading to reduced efficiency in amplifying the signal.Rate this question:
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- 16.
Suppose that the gain of a transistor in a common emitter circuit is 100 at a frequency of1 kHz, and the gain is 70.7 at 335 kHz. The gain drops to 1 at 210 MHz. The alpha cutofffrequency is
- A.
1 kHz.
- B.
335 kHz.
- C.
210 MHz.
- D.
Impossible to define based on this data.
Correct Answer
B. 335 kHz.Explanation
The alpha cutoff frequency is the frequency at which the gain of a transistor drops to 1/α times its low-frequency value. In this case, the gain drops to 1 at 210 MHz, which means α = 1/100. Therefore, the alpha cutoff frequency is 1/α times the low-frequency value, which is 1 kHz. Since α = 1/100, the alpha cutoff frequency is 1 kHz * 100 = 100 kHz. However, the gain is given to be 70.7 at 335 kHz, which is closer to the alpha cutoff frequency. Therefore, the correct answer is 335 kHz.Rate this question:
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Current Version
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Sep 04, 2023Quiz Edited by
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Dec 09, 2010Quiz Created by
BATANGMAGALING
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