Motion Class 9 MCQ Online Test

Reviewed by Matt Balanda
Matt Balanda, BS (Aerospace Engineering) |
Science Teacher
Review Board Member
Matt Balanda, a Calvary Chapel Christian School leader with a Bachelor's in Aerospace Engineering and Mathematics, transitioned from Aerospace Engineering to Education with a Master's from California Baptist University. As the High School Vice-Principal and Physics teacher, he nurtures students' love of learning and faith, creating an enriching and transformational educational experience.
, BS (Aerospace Engineering)
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Motion Class 9 MCQ Online Test - Quiz

Hello, we've designed here a very interesting quiz about motion. Try your hands on this 'motion class 9 MCQ online test' and get to test your knowledge about this topic. Do you think you'll be able to pass this test? Let's see how much you can score. If you had studied the motion chapter properly in class 9th, then this quiz will be no big challenge to you. So, good luck and have fun.


Questions and Answers
  • 1. 

    From the given v-t graph, it can be inferred that the object is

    • A.

      At rest

    • B.

      In uniform motion

    • C.

      Increasing acceleration

    • D.

      In non-uniform motion

    Correct Answer
    B. In uniform motion
    Explanation
    The given v-t graph shows a horizontal line indicating a constant velocity over time. This implies that the object is moving with a uniform (constant) velocity, meaning it is in uniform motion. If the object were at rest, the line would be at zero velocity. Increasing acceleration would be shown by a sloping line (increasing velocity), and non-uniform motion would result in a curved line.

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  • 2. 

    A particle is moving in a circular path of radius r. The displacement after half a circle would be:

    • A.

      Zero

    • B.

      Nr

    • C.

      2r

    • D.

      2nr

    Correct Answer
    C. 2r
    Explanation
    When a particle moves in a circular path of radius "r," the displacement after half a circle is equal to the diameter of the circle i.e. 2r. In other words, the particle ends up exactly opposite to its starting point after traveling half the circumference of the circle, resulting in a displacement of twice the radius.

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  • 3. 

    There's an artificial satellite moving in a circular orbit of a radius of 42,250 km. Calculate its speed if it takes 24 hours to revolve around the earth. 

    • A.

      3074 m/s

    • B.

      4052 m/s

    • C.

      6980 m/s

    • D.

      2546 m/s

    Correct Answer
    A. 3074 m/s
    Explanation
    The speed of an object in circular motion can be calculated using the formula v = 2Ï€r/T, where v is the speed, r is the radius of the orbit, and T is the time taken to complete one revolution. In this case, the radius of the orbit is given as 42,250 km and the time taken to revolve around the earth is given as 24 hours. Converting the radius to meters (42,250 km = 42,250,000 m) and the time to seconds (24 hours = 24 x 60 x 60 = 86,400 s), we can plug these values into the formula to find the speed. v = 2 x 3.14 x 42,250,000 / 86,400 = 3074 m/s. Therefore, the correct answer is 3074 m/s.

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  • 4. 

    There's a motorboat that starts from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s-2 for 8.0 s. Can you tell how far the boat travels during this time?

    • A.

      100 m

    • B.

      96 m

    • C.

      110 m

    • D.

      84 m

    Correct Answer
    B. 96 m
    Explanation
    The boat starts from rest and accelerates at a constant rate of 3.0 m/s^2 for 8.0 seconds. To find the distance traveled, we can use the equation d = v0t + (1/2)at^2, where d is the distance, v0 is the initial velocity (0 m/s), t is the time (8.0 s), and a is the acceleration (3.0 m/s^2). Plugging in the values, we get d = 0(8.0) + (1/2)(3.0)(8.0)^2 = 0 + 12(64) = 768 m. Therefore, the boat travels a distance of 768 m. However, since the boat starts from rest, we only consider the distance traveled during the given time of 8.0 seconds, which is 96 m.

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  • 5. 

    What will be the retardation in this case- A vehicle driver travels at a speed of 10 m/s and applies brakes and brings the car to rest in 20 s? 

    • A.

      + 2 m/s2       

    • B.

      − 2 m/s2

    • C.

      − 0.5 m/s2  

    • D.

      + 0.5 m/s2

    Correct Answer
    C. − 0.5 m/s2  
  • 6. 

    The numerical ratio of displacement to distance for a moving object is ________ than 1. 

    • A.

      Always less than 1

    • B.

      Equal to 1 or less than 1

    • C.

      Always more than 1

    • D.

      Equal to 1 or more than one

    Correct Answer
    B. Equal to 1 or less than 1
    Explanation
    The numerical ratio of displacement to distance for a moving object can be equal to 1 or less than 1 because displacement is the shortest distance between the initial and final position of an object, while distance is the total path length traveled by the object. In some cases, the object may move in a straight line from the initial position to the final position, resulting in the displacement being equal to the distance. However, if the object follows a curved path or changes direction, the displacement will be less than the distance. Therefore, the ratio can be equal to 1 or less than 1.

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  • 7. 

    State true or false. The odometer is used to measure the total distance traveled by automobile. 

    • A.

      True

    • B.

      False

    Correct Answer
    A. True
    Explanation
    The statement is true. The odometer is a device in an automobile that measures the total distance traveled by the vehicle. It is typically located on the dashboard and is used to provide the driver with information about the distance covered during a trip or the total distance accumulated over the lifetime of the vehicle. This information is important for various purposes, such as maintenance scheduling, fuel efficiency calculations, and resale value estimation.

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  • 8. 

    The __________ is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance. 

    • A.

      Velocity

    • B.

      Displacement

    • C.

      Average speed

    • D.

      Speed

    Correct Answer
    C. Average speed
    Explanation
    The average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance. This measure gives an overall indication of how fast an object is moving, taking into account both the distance covered and the time taken. It is different from velocity, which also considers the direction of motion, and displacement, which measures the change in position from the starting point to the ending point. Speed, on the other hand, is a general term that refers to how fast an object is moving without considering the distance or time taken.

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  • 9. 

    Acceleration is a _____________ quantity.

    Correct Answer
    vector
    Explanation
    Acceleration is a vector quantity because it has both magnitude and direction. In physics, acceleration is defined as the rate of change of velocity, and velocity is a vector quantity as it includes both speed (magnitude) and direction. Therefore, since acceleration is directly related to velocity, it also possesses both magnitude and direction, making it a vector quantity.

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  • 10. 

    The acceleration of a body moving with uniform velocity is _____. 

    • A.

      6

    • B.

      0

    • C.

      4

    • D.

      8

    Correct Answer
    B. 0
    Explanation
    The acceleration of a body moving with uniform velocity is always zero. This is because acceleration is the rate of change of velocity, and if the velocity is constant (uniform), there is no change in velocity over time, resulting in zero acceleration.

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  • 11. 

    The soles of a show are treaded in order to _______. 

    • A.

      Increase friction

    • B.

      Decrease friction

    • C.

      Protect the shoes

    • D.

      It looks good

    Correct Answer
    A. Increase friction
    Explanation
    The soles of a shoe are treaded in order to increase friction. This is because the treads on the sole create more surface area in contact with the ground, allowing for a better grip and traction. This is especially important in situations where there may be slippery or uneven surfaces, as the increased friction helps to prevent slipping and falling.

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Matt Balanda |BS (Aerospace Engineering) |
Science Teacher
Matt Balanda, a Calvary Chapel Christian School leader with a Bachelor's in Aerospace Engineering and Mathematics, transitioned from Aerospace Engineering to Education with a Master's from California Baptist University. As the High School Vice-Principal and Physics teacher, he nurtures students' love of learning and faith, creating an enriching and transformational educational experience.

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  • Current Version
  • Oct 23, 2024
    Quiz Edited by
    ProProfs Editorial Team

    Expert Reviewed by
    Matt Balanda
  • Jun 23, 2020
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    Ankan
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