Strength Of Materials! Trivia Questions Quiz

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Naveen
N
Naveen
Community Contributor
Quizzes Created: 1 | Total Attempts: 659
| Attempts: 662
SettingsSettings
Please wait...
  • 1/12 Questions

    As compared to mild steel, high carbon steel has less

    • Ultimate strength
    • Hardness
    • Ductility
    • Hardness and ductility
Please wait...
About This Quiz

This is a strength of materials trivia questions quiz. When it comes to fields such as engineering and construction it is important for one to understand the changes that different materials face when they go through certain processes. If you are looking to test how well you know different materials and how they change based on force applied, this quiz is for you. Give it a shot and see what more you may learn.

Strength Of Materials! Trivia Questions Quiz - Quiz

Quiz Preview

  • 2. 

    In a compression on mild steel

    • Necking does not occur

    • Hooke's law is not valid

    • Hooke's law is valid beyond yield point

    • Strength in compression is much greater than the strength in tension

    Correct Answer
    A. Necking does not occur
    Explanation
    In a compression on mild steel, necking does not occur. Necking is a phenomenon that typically happens in tension, where the material starts to narrow down at a localized point before it eventually fractures. In compression, the material is subjected to forces that push it together, rather than pull it apart, which prevents the occurrence of necking.

    Rate this question:

  • 3. 

    The yield stress of a twisted bar as compared to an ordinary mild steel bar is nearly

    • 50% more

    • 25% more

    • 50% less

    • 25% less

    Correct Answer
    A. 50% more
    Explanation
    The yield stress of a twisted bar is 50% more compared to an ordinary mild steel bar. This means that the twisted bar can withstand 50% more stress before it starts to deform permanently. The twisting process increases the strength and resilience of the bar, making it more resistant to bending or breaking under pressure.

    Rate this question:

  • 4. 

    For carbon steel, the endurance limit is approximately

    • 0.3

    • 0.5

    • 0.75

    • 0.85

    Correct Answer
    A. 0.5
    Explanation
    The endurance limit for carbon steel is approximately 0.5. This means that carbon steel can withstand cyclic loading and stress up to a certain level without experiencing fatigue failure. The endurance limit is the maximum stress that a material can endure for an infinite number of cycles without failure. In the case of carbon steel, this limit is around 0.5, indicating its ability to withstand repeated stress without breaking or wearing out.

    Rate this question:

  • 5. 

    Which of the following statement is false?

    • The stress dependent part of the plastic deformation is referred to as creep, and the time dependent part which is also influenced by the temperature as slip

    • In case of ductile material possessing a well-defined yield point, the proportional limit almost coincides

    • A fatigue failure is of a brittle nature even for materials which are normally ductile

    • The endurance limit for machined and polished specimens is higher than for rolled or forged components

    Correct Answer
    A. The stress dependent part of the plastic deformation is referred to as creep, and the time dependent part which is also influenced by the temperature as slip
    Explanation
    The correct answer is "The stress dependent part of the plastic deformation is referred to as creep, and the time dependent part which is also influenced by the temperature as slip." This statement is false because the stress dependent part of plastic deformation is referred to as slip, and the time dependent part influenced by temperature is referred to as creep.

    Rate this question:

  • 6. 

    For most brittle materials generally ultimate strength in compression is much larger than the ultimate strength in tension, because

    • Of flaws such as microscopic cracks or cavities

    • Compression failure is due to normal stress, and failure in tension due to shear stress

    • Yield point does not occur in compression

    • Of inherent properties of materials

    Correct Answer
    A. Of flaws such as microscopic cracks or cavities
    Explanation
    The correct answer is that the ultimate strength in compression is generally much larger than the ultimate strength in tension because of flaws such as microscopic cracks or cavities. Brittle materials are more prone to failure in tension due to the presence of these flaws, which act as stress concentrators and reduce the material's ability to withstand tensile forces. In compression, these flaws are less likely to propagate and cause failure, resulting in a higher ultimate strength.

    Rate this question:

  • 7. 

    Consider the following statements regarding tensile test diagrams for carbon steels with varying carbon contents. As the carbon content increases 1. the ultimate strength of steel decreases 2. the elongation before fracture increases 3. the ductility of the metal decreases 4. the percentage elongation of steel decreases Of these statements

    • 3 and 4 are correct

    • 1 and 3 are correct

    • 1, 2 and 3 are correct

    • 1 and 2 are correct

    Correct Answer
    A. 3 and 4 are correct
    Explanation
    As the carbon content increases in carbon steels, the ductility of the metal decreases. This means that the ability of the metal to deform without breaking or fracturing decreases. Additionally, the percentage elongation of the steel also decreases, indicating that the steel becomes less capable of stretching or elongating before it fractures. Therefore, statements 3 and 4 are correct.

    Rate this question:

  • 8. 

    Which of the following is primarily responsible for toughness of steel?

    • Iron

    • Carbon

    • Manganese

    • Phosphorous

    Correct Answer
    A. Manganese
    Explanation
    Manganese is primarily responsible for the toughness of steel. Manganese is added to steel as an alloying element to improve its strength, hardness, and toughness. It forms a solid solution with iron, which helps to enhance the grain structure of the steel, making it more resistant to deformation and fracture. Manganese also helps to reduce the formation of brittle phases in the steel, improving its toughness and impact resistance. Therefore, the presence of manganese in steel plays a crucial role in determining its toughness.

    Rate this question:

  • 9. 

    Consider the following statements: A: An isotropic material is always homogeneous R: An isotropic material is one in which all the properties are the same in all the directions at every point. Of these statements

    • Both A and R are true and R is the correct explanation of A

    • Both A and R are true but R is not a correct explanation of A

    • A is true but R is false

    • A is false but R is true

    Correct Answer
    A. A is false but R is true
    Explanation
    An isotropic material is one in which all the properties are the same in all directions at every point. This means that the material has the same mechanical, thermal, and electromagnetic properties regardless of the direction in which they are measured. However, this does not necessarily mean that an isotropic material is always homogeneous. Homogeneous materials have the same composition and structure throughout, while isotropic materials only have the same properties in all directions. Therefore, Statement A is false because isotropic materials can be either homogeneous or non-homogeneous. Statement R is true because it accurately defines what an isotropic material is.

    Rate this question:

  • 10. 

    Consider the following factors: 1. Large number of loading cycles 2. Large variations in stress 3. Large stress concentrations Those associated with fatigue failure include

    • 1 and 2

    • 1 and 3

    • 2 and 3

    • 1, 2 and 3

    Correct Answer
    A. 1 and 3
    Explanation
    Fatigue failure occurs due to repeated loading cycles and large stress concentrations. Large variations in stress can also contribute to fatigue failure, but it is not a necessary factor. Therefore, the factors associated with fatigue failure are 1 and 3.

    Rate this question:

  • 11. 

    Which of the following methods of design would be suitable for metal structures subjected to stress reversals and impact? 1. Simple working stress design 2. Rigid plastic design 3. Semi-rigid design 4. Elastic rigid design Select the correct answer using the codes given below:

    • 1, 2 and 4

    • 1, 3 and 4

    • 1, 2 and 3

    • 2, 3 and 4

    Correct Answer
    A. 1, 3 and 4
    Explanation
    Simple working stress design is suitable for metal structures subjected to stress reversals and impact as it considers the working stress and the material's yield strength. Semi-rigid design is also suitable as it allows for some flexibility and redistribution of stresses. Elastic rigid design is suitable as it considers the structure's elastic behavior under stress. Rigid plastic design, on the other hand, is not suitable as it assumes that the material behaves plastically and does not consider the structure's elastic behavior. Therefore, the correct answer is 1, 3, and 4.

    Rate this question:

  • 12. 

    A deviator state of stress is characterized by

    • A change in volume without distortion

    • A distortion without change in volume

    • A change in volume accompanied by distortion

    • No change in either volume nor distortion

    Correct Answer
    A. A change in volume without distortion
    Explanation
    A deviator state of stress is characterized by a change in volume without distortion. This means that the stress applied to a material causes a change in volume but does not cause any change in the shape or distortion of the material. This can occur, for example, when a material is subjected to hydrostatic pressure, where the stress is uniformly applied in all directions, causing a change in volume but not in shape.

    Rate this question:

Quiz Review Timeline (Updated): Jan 31, 2023 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Jan 31, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Dec 19, 2018
    Quiz Created by
    Naveen
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.