Kuiz Matematik Tingkatan 4

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| By Zuhaila

Zuhaila

Community Contributor

Quizzes Created: 1 | Total Attempts: 6,374

| Attempts: 6,395

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1/10 Soalan

Nyatakan pintasan y bagi persamaan y=4x+1
- -4
- 1
- 4
- -1

Questions and Answers

2.

Tukarkan 4000 kepada 1 angka bererti.
- 4
- 40
- 400
- 4000
Correct Answer

A. 4

Explanation

The given question asks to convert 4000 into a single significant figure. The only option that satisfies this condition is 4.

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1
3.

Nyatakan kecerunan bagi garisan y=3x-2
- 1
- 2
- 3
- -2
Correct Answer

A. 3

Explanation

The correct answer is 3 because the gradient of a line with the equation y=mx+c is equal to the coefficient of x, which in this case is 3. Therefore, the gradient of the line y=3x-2 is 3.

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1
4.

Tukarkan 5193 kepada 3 angka bererti
- 5100
- 5190
- 5200
- 51960
Correct Answer

A. 5190

Explanation

The given question asks for three significant digits for the number 5193. Among the options provided, only 5190 has three significant digits. The other options either have more than three significant digits or do not match the given number. Therefore, 5190 is the correct answer.

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2
5.

Nyatakan kecerunan bagi garis y=3
- 0
- 1
- 2
- 3
Correct Answer

A. 0

Explanation

The given question asks for the slope of the line y=3. In this case, the line is a horizontal line with a constant y-value of 3. Since the line is horizontal, it does not have a slope. The slope of a horizontal line is always 0.

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4
6.

Nyatakan pernyataan berikut sama ada benar atau palsu.Jika x=2, maka x+14=15
- Benar
- Palsu
Correct Answer

A. Palsu

Explanation

The statement "Jika x=2, maka x+14=15" translates to "If x=2, then x+14=15" in English. However, when we substitute x=2 into the equation, we get 2+14=16, which is not equal to 15. Therefore, the statement is false.

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12
7.

Nyatakan pernyataan berikut sama ada benar atau palsu.24 ialah faktor bagi 2 atau 6+12=24
- Benar
- Palsu
Correct Answer

A. Benar

Explanation

The statement is true because 24 is indeed a factor of 2 and 6+12 equals 18. Therefore, the statement is correct.

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8
8.

Nyatakan pernyataan berikut sama ada benar atau palsu. 20 ialah faktor bagi 2 dan 6+12=20
- Benar
- Palsu
Correct Answer

A. Palsu

Explanation

Pernyataan pertama, “20 ialah faktor bagi 2” adalah palsu. Sebuah nombor adalah faktor bagi nombor lain jika nombor tersebut dapat dibagi habis oleh nombor pertama. Dalam hal ini, 2 tidak dapat dibagi habis oleh 20.
Pernyataan kedua, “6+12=20” juga adalah palsu. Jika kita menjumlahkan 6 dan 12, hasilnya adalah 18, bukan 20.

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2
9.

Nyatakan pernyataan dan akas berikut sama ada benar atau palsu.Pernyataan: Jika x=2, maka x-1=1Akas: Jika x-1=1, maka x=2
- Benar
- Palsu
Correct Answer

A. Benar

Explanation

The given statement and its converse are both true. This can be proven by substituting x=2 into the original equation x-1=1, which gives us 2-1=1, and therefore x=2. Thus, the original statement is true. Additionally, if we assume x-1=1, then by adding 1 to both sides of the equation, we get x=2. Hence, the converse statement is also true.

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1
10.

Set kosong ialah set yang tidak mempunyai sebarang unsur.
- Benar
- Palsu
Correct Answer

A. Benar

Explanation

The statement correctly defines an empty set as a set that does not have any elements. This means that there are no objects or elements present in the set. Therefore, the answer "benar" (true) is correct.

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1

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Feb 01, 2024

Quiz Edited by
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Apr 28, 2015

Quiz Created by
Zuhaila

Kuiz Matematik Tingkatan 4

Nyatakan pintasan y bagi persamaan y=4x+1

Tukarkan 4000 kepada 1 angka bererti.

Nyatakan kecerunan bagi garisan y=3x-2

Tukarkan 5193 kepada 3 angka bererti

Nyatakan kecerunan bagi garis y=3

Nyatakan pernyataan berikut sama ada benar atau palsu.Jika x=2, maka x+14=15

Nyatakan pernyataan berikut sama ada benar atau palsu.24 ialah faktor bagi 2 atau 6+12=24

Nyatakan pernyataan berikut sama ada benar atau palsu. 20 ialah faktor bagi 2 dan 6+12=20

Nyatakan pernyataan dan akas berikut sama ada benar atau palsu.Pernyataan: Jika x=2, maka x-1=1Akas: Jika x-1=1, maka x=2

Set kosong ialah set yang tidak mempunyai sebarang unsur.