Simulasi Online Ujian Nasional Fisika 2016/2017

Explanation
The correct answer is 10,00 mm because the image shows a micrometer screw, which is a tool used to measure small distances with high precision. The measurement scale on the micrometer screw indicates that the diameter of the wheel spoke is exactly 10 mm.

Explanation
The magnitude of the resultant vector can be determined by using the Pythagorean theorem. In this case, the vectors a and b are perpendicular to each other, forming a right triangle. The magnitude of the resultant vector is equal to the square root of the sum of the squares of the magnitudes of vectors a and b. Since the magnitude of vector a is 8 satuan and the magnitude of vector b is 6 satuan, the magnitude of the resultant vector is sqrt(8^2 + 6^2) = sqrt(64 + 36) = sqrt(100) = 10 satuan.

Explanation
Diagram (5) represents D = A + B + C because it shows three separate circles, each representing A, B, and C, with an overlapping section in the middle representing the sum of A, B, and C, which is D.

Explanation
The correct answer is (1), (2), dan (3).


(1) Frekuensi putarannya 4/π Hz: Frekuensi putaran dapat dihitung dengan rumus f = v / (2πr), dimana v adalah kecepatan dan r adalah jari-jari lingkaran. Dalam kasus ini, kecepatan adalah 4 m/s dan jari-jari adalah 0,5 meter. Menggantikan nilai ke dalam rumus, f = 4 / (2π * 0,5) = 4/π Hz.

(2) Percepatan sentripetalnya 32 m/s2: Percepatan sentripetal dapat dihitung dengan rumus a = v^2 / r, dimana v adalah kecepatan dan r adalah jari-jari lingkaran. Dalam kasus ini, kecepatan adalah 4 m/s dan jari-jari adalah 0,5 meter. Menggantikan nilai ke dalam rumus, a = (4^2) / 0,5 = 32 m/s^2.

(3) Gaya sentripetalnya 320 N: Gaya sentripetal dapat dihitung dengan rumus F = m * a, dimana m adalah massa dan a adalah percepatan sentripetal. Dalam kasus ini, massa adalah 10 kg dan percepatan sentripetal adalah 32 m/s^2. Menggantikan nilai ke dalam rumus, F = 10 * 32 = 320 N.

Therefore, statements (1), (2), and (3) are correct explanations.

Explanation
When the stone is thrown upwards, it will experience a decrease in velocity due to the force of gravity pulling it downwards. The stone will reach its highest point when its velocity becomes zero. As it starts to descend, its velocity will become negative because it is moving in the opposite direction of the initial throw. When the stone lands on the board, its velocity will still be negative, indicating that it is moving downwards. Therefore, the correct answer is -3 m/s.

Explanation
The correct answer is 330 N because to find the force required to move the system to the left with an acceleration of 2 m/s^2, we need to consider the frictional force between block A and the table. The frictional force can be calculated using the formula F_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force. The normal force is equal to the weight of the block, which is given by the formula N = m * g, where m is the mass of the block and g is the acceleration due to gravity. By substituting the given values into the formulas and solving, we find that the frictional force is 33 N. Since the system is moving to the left, we need to apply a force in the opposite direction, which is equal in magnitude but opposite in direction to the frictional force. Therefore, the force required to move the system to the left with an acceleration of 2 m/s^2 is 330 N.

Explanation
The density of the star is directly proportional to its mass, and the mass is directly proportional to the cube of the radius. Therefore, if the density increases by a factor of 0.75, the mass will also decrease by a factor of 0.75. Since the radius increases by a factor of 1.25, the acceleration due to gravity at the surface will decrease by a factor of (0.75/1.25)^2 = 0.45. Therefore, the new acceleration due to gravity at the surface is 0.45 times the original acceleration, which is equivalent to (15/16) g.