1.
Describe why anabolism and catabolism need to be precisely regulated. Include in your answer what is meant by reciprocal regulation of anabolic and catabolic pathways.
2.
Describe using an equation, how a reaction in a biochemical pathway may occur spontaneously despite the standard free energy for that reaction being positive. Outline the difference between free energy and standard free energy in your answer.
3.
Which is INCORRECT? Energy is required by cells for:
Correct Answer
E. Hydrolysis of a molecule during an exothermic reaction
Explanation
Hydrolysis is a process that requires energy input, not the release of energy. In hydrolysis, a molecule is broken down into smaller components by the addition of water. This process requires energy to break the bonds holding the molecule together. In an exothermic reaction, energy is released, not consumed. Therefore, hydrolysis of a molecule during an exothermic reaction is incorrect.
4.
Which statement about catabolic reactions is true?
Correct Answer
A. Catabolic reactions are degradative and are generally exergonic
Explanation
Catabolic reactions are degradative and generally exergonic because they involve the breakdown of larger molecules into smaller ones, releasing energy in the process. This energy release is due to the breaking of chemical bonds, which results in a decrease in the overall energy of the system. Therefore, catabolic reactions are characterized by the release of energy and the degradation of complex molecules.
5.
Which is NOT a mechanism for regulating metabolic pathways?
Correct Answer
C. Control of cell temperature
Explanation
Control of cell temperature is not a mechanism for regulating metabolic pathways. While temperature can affect the rate of metabolic reactions, it is not a direct regulatory mechanism. The other options listed - control of intracellular substrate concentration, control of allosteric enzymes by inhibitors and activators, control of amount of enzymes, and control of enzymes through signaling substances - all play important roles in regulating metabolic pathways.
6.
Reciprocal regulation refers to:
Correct Answer
E. Activation of one pathway, while suppressing the opposite pathway
Explanation
Reciprocal regulation refers to the activation of one pathway while simultaneously suppressing the opposite pathway. This means that when one pathway is activated, the other pathway is inhibited or suppressed. This type of regulation allows cells to carefully control and balance the activation of anabolic (building up) and catabolic (breaking down) reactions. By activating one pathway and suppressing the opposite pathway, cells can ensure that the energy and resources are allocated appropriately and efficiently based on their current needs.
7.
If the ΔG'° of the reactions A → B is +20kJ/mol, under standard conditions the reaction:
Correct Answer
A. Will proceed spontaneously from right to left
Explanation
The positive value of ΔG° indicates that the reaction is non-spontaneous in the forward direction under standard conditions. Therefore, the reaction will proceed spontaneously in the reverse direction, from right to left, in order to reach equilibrium.
8.
If the ΔG'° of the reaction A → B is -100 kJ/mol, under standard conditions the reaction:
Correct Answer
E. Will proceed spontaneously from left to right
Explanation
The negative value of ΔG° indicates that the reaction is exergonic, meaning it releases energy. This suggests that the reaction will proceed spontaneously in the forward direction (from left to right) under standard conditions.
9.
Which is NOT true about the following reactions?A → B ΔG = +20 kJ/mol = reaction 1C → D ΔG = –30 kJ/mol = reaction 2 A + C → B + D = reaction 3
Correct Answer
D. Reaction 1 will not proceed from left to right unless an enzyme is present
Explanation
The given statement is true because the positive value of ΔG for reaction 1 indicates that it is not spontaneous in the forward direction. In order for the reaction to proceed from left to right, an enzyme is required to lower the activation energy barrier.
10.
Given the following information, calculate the actual free energy of the below reaction. A → B; Keq = 10; concentration in the cell of A = 0.2 M; B = 0.05 M; R = 8.315 J/mol.K; T = 298 K?
Correct Answer
A. -9.1 kJ/mol
Explanation
ΔGo = -RT ln Keq= -8.315 x 298 x ln10 = -5700 J/mol
ΔG = ΔGo + RT ln ([B]/[A])
ΔG = -5700 J/mol + 8.315 x 298 x ln (0.05/0.2)
ΔG = -5700 - 3400
ΔG = -9100 J/mol = -9.1 kJ/mol (answer a)
11.
When a mixture containing an equal concentration of glucose 6-phosphate and fructose 6-phosphate is incubated with the enzyme phosphohexose isomerase, the final mixture contains twice as much glucose 6-phosphate as fructose 6-phosphate. Which one of the following statements is correct, when applied to the reaction below (R = 8.315 J/mol•K and T = 298 K)? Glucose 6-phosphate ↔ fructose 6-phosphate
Correct Answer
A. ΔG'° is +1.7 kJ/mol
Explanation
Keq = [B]/[A] = 1/2
ΔGo = -RT ln Keq
ΔGo = -8.315 x 298x ln (1/2)
ΔGo = +1718 J/mol = +1.7 kJ/mol (answer a)
12.
What is the standard-state free energy (ΔG°) for the hydrolysis of ATP to ADP?
Correct Answer
C. -30.5 kJ/mol
Explanation
The standard-state free energy (∆G°) for the hydrolysis of ATP to ADP is -30.5 kJ/mol.