Organic Chemistry Conditions And Reagents
All of the conditions and reagents required for haloalkanes, alkenes and Alcohols, for the AQA AS Chemistry Syllabus. By Kafeel :)
- 1.
What is the reagent used in the production of butan-1-ol from 1-Chlorobutane?
- A.
KOH (Aq) or NaOH(aq)
- B.
KOH (aq)
- C.
KOH (Ethanolic)
- D.
NaOH (aq)
- E.
NaOH (Ethanolic)
Correct Answer
A. KOH (Aq) or NaOH(aq)Explanation
If you got this question wrong your a idiot.Rate this question:
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- 2.
What are the conditions in the production of butan-1-ol from 1-Chlorobutane?
- A.
Boil
- B.
Warm
- C.
Warm Under Reflux
- D.
Boil Under Reflux
- E.
Ice cold water from Atlantic Ocean
Correct Answer
C. Warm Under RefluxExplanation
The conditions in the production of butan-1-ol from 1-Chlorobutane require warming the reaction mixture under reflux. Refluxing involves heating the reaction mixture while continuously condensing and returning any volatile components that evaporate back into the reaction vessel. This allows for a more efficient and controlled reaction, ensuring that the reactants are heated and mixed thoroughly. Boiling alone may not be sufficient to achieve the desired conversion, and ice cold water from the Atlantic Ocean is irrelevant to the production process.Rate this question:
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- 3.
What are the reagents used in the production of ethanenitrile from Bromoethane?
- A.
Air
- B.
NaOH
- C.
KBR
- D.
KOH
- E.
KCN
Correct Answer
E. KCNExplanation
To produce ethanenitrile from bromoethane, KCN (potassium cyanide) is used as the reagent. KCN reacts with bromoethane through a substitution reaction, where the bromine atom is replaced by a cyano group (CN). This reaction is known as nucleophilic substitution, and KCN acts as a source of the nucleophile (CN-). The other reagents listed (air, NaOH, KBr, KOH) do not play a role in this specific reaction and are therefore not used for the production of ethanenitrile from bromoethane.Rate this question:
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- 4.
What are the conditions used in the production of ethanenitrile from Bromoethane?
- A.
Warm Under Reflux
- B.
Cool Under Reflux
- C.
Boil under Reflux
- D.
Boil
- E.
Warm
Correct Answer
C. Boil under RefluxExplanation
Boiling under reflux is the correct condition for the production of ethanenitrile from Bromoethane. Reflux involves heating a reaction mixture and continuously condensing the vapors that are formed back into the reaction flask. This allows for a more efficient reaction as any volatile components are not lost to evaporation. In the case of producing ethanenitrile from Bromoethane, boiling under reflux ensures that the reaction proceeds at a controlled temperature, allowing for the formation of the desired product.Rate this question:
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- 5.
What is the reagent used in the production of Propylamine from Chloropropane?
- A.
Ammonium Ions (NH4+)
- B.
Ammonia (NH3)
- C.
Ammoniacal Silver Nitrate
- D.
Ammonium Chloride
- E.
Amine Ions
Correct Answer
B. Ammonia (NH3)Explanation
Ammonia (NH3) is used as the reagent in the production of Propylamine from Chloropropane. Ammonia acts as a nucleophile and reacts with Chloropropane through a nucleophilic substitution reaction, where the chlorine atom is replaced by an amino group (-NH2). This reaction is known as the Hofmann rearrangement. Ammonia is a common reagent in organic synthesis and is often used to introduce amino groups into organic compounds.Rate this question:
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- 6.
What are the conditions used in the production of Propylamine from Chloropropane?
- A.
Heat
- B.
Boil Under Reflux
- C.
Heat under Reflux
- D.
Cool
- E.
Distillation
Correct Answer
A. HeatExplanation
Heat is used in the production of Propylamine from Chloropropane because it is necessary to provide the energy required for the reaction to occur. Heating the mixture of Chloropropane allows for the breaking of the chemical bonds and the formation of Propylamine. This process is commonly used in organic chemistry reactions where heat is used as a catalyst to facilitate the conversion of one compound into another.Rate this question:
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- 7.
What is the reagent used in the production of hex-2-ene from 3-Bromohexane?
- A.
NaOH (Ethanolic)
- B.
KOH (aqueous)
- C.
KOH (Ethanolic)
- D.
NaOH or KOH (aq)
- E.
NaCl
Correct Answer
C. KOH (Ethanolic)Explanation
KOH (Ethanolic) is the reagent used in the production of hex-2-ene from 3-Bromohexane. The reaction is an elimination reaction known as the E2 mechanism. In this reaction, the ethanolic KOH acts as a strong base and abstracts a proton from the beta carbon of 3-Bromohexane, creating a carbanion. The carbanion then eliminates a bromide ion, resulting in the formation of hex-2-ene. The ethanolic solvent helps to dissolve KOH and facilitate the reaction.Rate this question:
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- 8.
What are the conditions used in the production of polyethene from ethene?
- A.
High temperature
- B.
High Concentration of Ethene
- C.
High pressure
- D.
Low Temperature
- E.
Low Pressure
Correct Answer
C. High pressureExplanation
High pressure is used in the production of polyethene from ethene because it helps to increase the reaction rate and promote the formation of polymer chains. This is because high pressure forces the ethene molecules closer together, increasing the chances of successful collisions and polymerization reactions. Additionally, high pressure helps to maintain the stability of the reaction and prevent the formation of unwanted by-products. Therefore, high pressure is a crucial condition in the production of polyethene from ethene.Rate this question:
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- 9.
What are the conditions used in the production of 3,3-DiIodopentane from pentene?
- A.
Boil under Reflux
- B.
High pressure
- C.
Distillation
- D.
Cool
- E.
Room Temperature
Correct Answer
E. Room TemperatureExplanation
The production of 3,3-DiIodopentane from pentene does not require any specific conditions such as boiling under reflux, high pressure, or distillation. Instead, it can be produced at room temperature, indicating that the reaction does not require any additional heat or pressure to proceed.Rate this question:
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- 10.
What is the reagent used in the production of 3,3DiIodopentane from pentene?
- A.
HBR
- B.
HI
- C.
Cl2
- D.
I2
- E.
KBR
Correct Answer
D. I2Explanation
I2, or iodine, is the reagent used in the production of 3,3-DiIodopentane from pentene. Iodine reacts with the double bond in pentene to form the corresponding diiodoalkane.Rate this question:
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- 11.
What is the reagent and condition used in the production of ethyl hydrogensulphate from ethene?
- A.
Sulphuric Acid (Cold)
- B.
Concentrated Sulphuric Acid (Cold)
- C.
Dilute Sulphuric Acid (warm)
- D.
Copper Sulphate (ice cold)
- E.
Sulphate ions (Ice)
Correct Answer
B. Concentrated SulpHuric Acid (Cold)Explanation
Concentrated sulphuric acid (cold) is the reagent and condition used in the production of ethyl hydrogensulphate from ethene. This reaction involves the addition of sulphuric acid to ethene, resulting in the formation of ethyl hydrogensulphate. The use of concentrated sulphuric acid ensures a high concentration of the acid, which promotes the reaction. The cold temperature helps to control the reaction rate and prevent unwanted side reactions.Rate this question:
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- 12.
What is the catalyst used in the production of an Alcohol from an Alkene?
- A.
H2SO4
- B.
Potassium Dichromate
- C.
H3PO4
- D.
Coke
- E.
Nickel
Correct Answer
C. H3PO4Explanation
H3PO4, also known as phosphoric acid, is the catalyst used in the production of alcohol from an alkene. It acts as a proton donor, facilitating the addition of water to the alkene molecule, resulting in the formation of an alcohol. Phosphoric acid is commonly used in industrial processes for the production of various alcohols, such as ethanol.Rate this question:
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- 13.
What are the conditions used in the production of an Alcohol from an Alkene?
- A.
Electrolysis
- B.
Soil
- C.
100°C and 55 atmospheres under water
- D.
300°C and 60 atmospheres under steam
- E.
Boil under reflux
Correct Answer
D. 300°C and 60 atmospHeres under steamExplanation
In the production of alcohol from an alkene, the conditions of 300°C and 60 atmospheres under steam are used. This high temperature and pressure help in the process of hydration, where water is added to the alkene to form an alcohol. The steam acts as a source of water, and the conditions of high temperature and pressure facilitate the reaction to occur at a faster rate. This process is commonly known as the steam hydration of alkenes.Rate this question:
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- 14.
How would I make butanal from Butan-1-ol?
- A.
Use potassium dichromate, Concentrated H2SO4 then Cool and Reflux.
- B.
Use potassium dichromate, Concentrated H2SO4 then Warm and Distill.
- C.
Use potassium dichromate, Dilute H2SO4 then Warm and Distill.
- D.
Use potassium dichromate, Dilute H2SO4 then Cool and Reflux.
- E.
I dont know.
Correct Answer
C. Use potassium dichromate, Dilute H2SO4 then Warm and Distill.Explanation
The correct answer is to use potassium dichromate, dilute H2SO4, then warm and distill. This is because the reaction requires an oxidizing agent like potassium dichromate to convert the alcohol (butan-1-ol) into the corresponding aldehyde (butanal). Dilute H2SO4 is used as a catalyst to speed up the reaction. Warm and distill is the appropriate method to separate the desired product from the reaction mixture.Rate this question:
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- 15.
How would i make Propanone from Propan-2-ol?
- A.
Use potassium dichromate, Dilute H2SO4 then Heat and Distill.
- B.
Use potassium dichromate, Concentrated H2SO4 then Warm and Distill.
- C.
Use potassium dichromate, Dilute H2SO4 then Cool and Reflux.
- D.
Use potassium dichromate, Concentrated H2SO4 then Cool and Reflux.
- E.
What is this and Where am i?
Correct Answer
A. Use potassium dichromate, Dilute H2SO4 then Heat and Distill.Explanation
The correct answer is "Use potassium dichromate, Dilute H2SO4 then Heat and Distill." This method is commonly used to convert Propan-2-ol (an alcohol) into Propanone (a ketone). Potassium dichromate and dilute H2SO4 act as oxidizing agents, causing the alcohol to lose two hydrogen atoms and form a ketone. Heating and distilling the mixture helps in the separation and purification of the desired product.Rate this question:
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- 16.
How would i make pentanoic Acid from pentanal?
- A.
I still dont know.
- B.
Use potassium dichromate, Dilute H2SO4 then Heat and Distill.
- C.
Use potassium dichromate, Concentrated H2SO4 then Cool and Reflux.
- D.
Use potassium dichromate, Concentrated H2SO4 then Warm and Distill.
- E.
Use potassium dichromate, dilute H2SO4 then Heat and Reflux.
Correct Answer
E. Use potassium dichromate, dilute H2SO4 then Heat and Reflux.Explanation
The correct answer suggests using potassium dichromate and dilute H2SO4 to convert pentanal into pentanoic acid. Heating and refluxing the mixture allows for the reaction to occur, resulting in the formation of the desired product.Rate this question:
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- 17.
How do i make ethene from Ethanol?
- A.
Concentrated H2SO4 and Heat
- B.
Dilute H2SO4 and Heat
- C.
Concentrated H2SO4 and high pressure
- D.
H3PO4 catalyst
- E.
High temperature alone
Correct Answer
A. Concentrated H2SO4 and HeatExplanation
Concentrated H2SO4 and heat can be used to make ethene from ethanol through a process called dehydration. In this process, the concentrated sulfuric acid acts as a catalyst and removes a water molecule from the ethanol molecule, resulting in the formation of ethene. The heat provides the necessary energy for the reaction to occur.Rate this question:
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Mar 20, 2023Quiz Edited by
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May 14, 2011Quiz Created by
Kafeelmirza
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