Learn More About Organic Chemistry Quiz

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Akshay_24
A
Akshay_24
Community Contributor
Quizzes Created: 1 | Total Attempts: 609
| Attempts: 609
SettingsSettings
Please wait...
  • 1/11 Questions

    The SN2 reaction of 1-chloro-3-methylbutane with sodium methoxide is relatively slow, but can be accelerated by the addition of a small amount of NaI. How is this catalysis best explained?

    • The NaI changes the mechanism to SN1
    • SN2 reaction of iodide ion converts the alkyl chloride to the more reactive alkyl iodide
    • The iodide anion activates the methoxide nucleophile
    • The sodium cation helps pull off the chloride anion
Please wait...
About This Quiz

Chemistry is made up of mainly elements and compounds as a result of combinations of the elements. Organic chemistry basically involves those elements with carbon atoms. The quiz below gauges your understanding of the topic.

Learn More About Organic Chemistry Quiz - Quiz

Quiz Preview

  • 2. 
    Which reagent(s) would best accomplish the following transformation? - ProProfs

    Which reagent(s) would best accomplish the following transformation?

    • (i) HOBr (ii) Mg in ether

    • (i) B2H6 in ether (ii) H2O2 and base

    • (i) HgSO4 in H2O (ii) NaBH4

    • H3O+ & heat

    Correct Answer
    A. (i) B2H6 in ether (ii) H2O2 and base
    Explanation
    The given transformation involves the addition of a hydroxyl group (-OH) to a double bond. This is a typical reaction of hydroboration-oxidation, where the first step is the addition of borane (B2H6) in ether to the double bond, forming a boron intermediate. In the second step, the boron intermediate is oxidized by H2O2 and base, resulting in the formation of the hydroxyl group. Therefore, the reagents B2H6 in ether and H2O2 with base would best accomplish this transformation.

    Rate this question:

  • 3. 
    Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides.   In each case two isomeric C8H13Br products are obtained.   Which of the following is a common product from both reactions? - ProProfs

    Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides.   In each case two isomeric C8H13Br products are obtained.   Which of the following is a common product from both reactions?

    • B

    • D

    • A

    • C

    Correct Answer
    A. B
    Explanation
    The common product obtained from both reactions is B.

    Rate this question:

  • 4. 
    Which of the following will be the kinetically favored product from the depicted reaction ? - ProProfs

    Which of the following will be the kinetically favored product from the depicted reaction ?

    • B

    • D

    • A

    • C

    Correct Answer
    A. D
  • 5. 
    A C8H12 chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C8H14 compound. Ozonolysis of X (H2O2 workup) gave a chiral C8H12O4 dicarboxylic acid. Which of the following could be X ? - ProProfs

    A C8H12 chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C8H14 compound. Ozonolysis of X (H2O2 workup) gave a chiral C8H12O4 dicarboxylic acid. Which of the following could be X ?

    • A

    • D

    • B

    • C

    Correct Answer
    A. A
  • 6. 

    A C8H14 hydrocarbon (X) is reduced by sodium in liquid ammonia to a single C8H16 product (Y). Both of these compounds undergo hydrogenation (Pt catalyst) to give 2,5-dimethylhexane. Ozonolysis of Y with an oxidative workup produces a single C4H8O2 carboxylic acid. Reaction of Y with perbenzoic acid (C6H5CO3H) gives a chiral C8H14O product, but reaction with bromine gives an achiral C8H14Br2 product What are X and Y?

    • X is 2,5-dimethyl-2,4-hexadiene ; Y is cis-2,5-dimethyl-3-hexene.

    • X is 2.5-dimethyl-1,5-hexadiene ; Y is 2,5-dimethyl-3-hexyne.

    • X is 2,5-dimethyl-3-hexyne ; Y is trans-2,5-dimethyl-3-hexene.

    • X is 2,5-dimethyl-3-hexyne ; Y is cis-2,5-dimethyl-3-hexene.

    Correct Answer
    A. X is 2,5-dimethyl-3-hexyne ; Y is trans-2,5-dimethyl-3-hexene.
    Explanation
    The given information suggests that X is a C8H14 hydrocarbon that undergoes reduction to form Y, a C8H16 hydrocarbon. Y is then subjected to ozonolysis, which produces a single C4H8O2 carboxylic acid. This implies that Y must contain a double bond, which is cleaved during ozonolysis to form the carboxylic acid. Additionally, Y reacts with perbenzoic acid to form a chiral product, indicating the presence of a stereocenter. However, Y reacts with bromine to form an achiral product, suggesting that the bromine addition occurs in a way that does not generate a stereocenter. The only option that satisfies all of these conditions is X being 2,5-dimethyl-3-hexyne and Y being trans-2,5-dimethyl-3-hexene.

    Rate this question:

  • 7. 
    The structures of two 3º-bicyclic chlorides (I and II) are shown below. - ProProfs

    The structures of two 3º-bicyclic chlorides (I and II) are shown below.

    • II is more reactive than I for both substitution and eleimination

    • I is more reactive than II for both substitution and eleimination

    • On treatment with KOH in ethanol, I undergoes substitution and II undergoes eleimination.

    • On treatment with KOH in ethanol, both compounds undergo E2 elimination.

    Correct Answer
    A. II is more reactive than I for both substitution and eleimination
  • 8. 
    Which of the following represents the most stable conformation of all cis-1,2,4-trimethylcyclohexane? - ProProfs

    Which of the following represents the most stable conformation of all cis-1,2,4-trimethylcyclohexane?

    • D

    • B

    • A

    • C

    Correct Answer
    A. A
    Explanation
    The most stable conformation of cis-1,2,4-trimethylcyclohexane is represented by option A. This is because in this conformation, the bulky methyl groups are in equatorial positions, which reduces steric hindrance. The axial positions are occupied by the smaller hydrogen atoms, resulting in a more stable and energetically favorable conformation.

    Rate this question:

  • 9. 
    Which of the following reagents would not effect the following transformation? - ProProfs

    Which of the following reagents would not effect the following transformation?

    • PCl3

    • SOCl2

    • HCl & ZnCl2

    • KCl (5 molar solution)

    Correct Answer
    A. KCl (5 molar solution)
    Explanation
    KCl (5 molar solution) would not affect the given transformation because it is a neutral salt and does not possess any reactive or transforming properties. The other reagents, PCl3, SOCl2, and HCl & ZnCl2, are all known to be reactive and can bring about various chemical transformations. However, KCl (5 molar solution) does not possess any such reactivity and would not cause any change in the given transformation.

    Rate this question:

  • 10. 
    Identify "AC" product in following chart from following answers ? - ProProfs

    Identify "AC" product in following chart from following answers ?

    • A

    • B

    • C

    • D

    Correct Answer
    A. A
    Explanation
    The correct answer is A because it is the only option that matches the given "AC" product in the chart.

    Rate this question:

  • 11. 
    Cyclooctatetraene, C8H8, appears to be a conjugated annulene.   In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below.   Which of these is most likely to be the favored conformation?   note that D is planar. - ProProfs

    Cyclooctatetraene, C8H8, appears to be a conjugated annulene.   In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below.   Which of these is most likely to be the favored conformation?   note that D is planar.

    • A

    • B

    • D

    • C

    Correct Answer
    A. C
    Explanation
    The most likely favored conformation is C. This is because in order to have conjugation in a molecule, it is favorable for the p-orbitals to overlap and align in a planar configuration. The other structures shown are non-planar, which would disrupt the conjugation and make it less stable. Therefore, C, which is also planar, is the most likely favored conformation for cyclooctatetraene.

    Rate this question:

Quiz Review Timeline (Updated): Sep 3, 2024 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Sep 03, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Dec 10, 2011
    Quiz Created by
    Akshay_24
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.