What are the percent composition for SF2?

45.76% Sulfur and 54.39 % Fluorine

49.2 % Sulfur and 50.8 % Fluorine

What is the percent composition of Ethyne? C2H2?

92.31% Carbon and 7.76% Hydrogen

82.7% Carbon and 17.3 % Hydrogen

Percent Composition Of Chemical Compounds MCQ Quiz

1.

What are the percent composition for SF₂?
- A.
  
  55 % Sulfur and 45% Fluorine
- B.
  
  45.76% Sulfur and 54.39 % Fluorine
- C.
  
  33% Sulfur and 67% Fluorine
- D.
  
  49.2 % Sulfur and 50.8 % Fluorine
Correct Answer
B. 45.76% Sulfur and 54.39 % Fluorine

Explanation
First find molar mass: Sulfur 32.06 + Fluorine 2 (19) = 70.06 g Sulfur percentage: (32.06 divided by the molar mass 70.06) x 100% = 45.76% Fluorine percentage (38 divided by 70.06) x 100 % = 54.39%

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2.

What is the percent composition of Ethyne? C₂H₂?
- A.
  
  92.31% Carbon and 7.76% Hydrogen
- B.
  
  82% Carbon and 18% Hydrogen
- C.
  
  82.7% Carbon and 17.3 % Hydrogen
- D.
  
  90% Carbon and 14 % Hydrogen
Correct Answer
A. 92.31% Carbon and 7.76% Hydrogen

Explanation
The percent composition of a compound refers to the percentage by mass of each element in the compound. In the case of ethyne (C2H2), there are 2 carbon atoms and 2 hydrogen atoms. To calculate the percent composition, we need to determine the molar mass of each element and divide it by the molar mass of the entire compound, then multiply by 100.

The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. The molar mass of ethyne (C2H2) is therefore (2 x 12.01) + (2 x 1.01) = 26.04 g/mol.

To calculate the percent composition of carbon, we divide the molar mass of carbon (24.02 g/mol) by the molar mass of ethyne (26.04 g/mol) and multiply by 100: (24.02 g/mol / 26.04 g/mol) x 100 = 92.31%.

To calculate the percent composition of hydrogen, we divide the molar mass of hydrogen (2.02 g/mol) by the molar mass of ethyne (26.04 g/mol) and multiply by 100: (2.02 g/mol / 26.04 g/mol) x 100 = 7.76%.

Therefore, the correct answer is 92.31% Carbon and 7.76% Hydrogen.

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3.

What is the percentage of Sulfur in SF₂?
- A.
  
  32.06 % Sulfur
- B.
  
  25% Sulfur
- C.
  
  45.7 % Sulfur
- D.
  
  62.67 % Sulfur
Correct Answer
C. 45.7 % Sulfur

Explanation
The correct answer is 70.06% Sulfur. This is because SF2 is a compound made up of one sulfur atom and two fluorine atoms. To calculate the percentage of sulfur in SF2, we need to find the molar mass of sulfur and divide it by the molar mass of SF2, then multiply by 100. The molar mass of sulfur is 32.06 g/mol, and the molar mass of SF2 is 70.06 g/mol. So, (32.06 g/mol / 70.06 g/mol) * 100 = 45.7%.

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4.

. What is the empirical formula for a compound that contains 1.67 mole Carbon and 5.01 Moles of Hydrogen
- A.
  
  CH
- B.
  
  CH2
- C.
  
  C2H3
- D.
  
  CH3
Correct Answer
D. CH3

Explanation
Empirical formula will always be whole numbers. Divide each moles of Carbon and Hydrogen by 1.6 = Carbon 1 and Hydrogen 3.

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5.

What is the empirical formula for a compound that contains 5.28 moles Oxygen, 1.32 moles Sulfur and 2.64 moles Hydrogen
- A.
  
  HSO
- B.
  
  H2SO2
- C.
  
  H2SO4
- D.
  
  HSO2
Correct Answer
C. H2SO4

Explanation
Empirical formula for a compound will always be in whole numbers. Divide each moles of S, H, and O by 1.32 .
Hydrogen: 2 Sulfur: 1 Oxygen: 4

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6.

What is the empirical formula for a compound that contains 22.00 % N and 78.0 % O
- A.
  
  N2O5
- B.
  
  NO3
- C.
  
  N2O3
- D.
  
  N2
Correct Answer
B. NO3

Explanation
Percent can be change to grams. N: 22.0 g, Oxygen 78 grams. All empirical formulas is the simplest whole-number ratio. Divide each by the lowest number of molar mass to get moles. N= 22.0/14.01 = 1.57 moles O = 78.00/16.00 = 4.87moles Divide each by 1.57 : N 1 and O 3.1 (experimental and rounding error) = NO3

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7.

What is the empirical formula for a compound that contains 37.69% Na and 62.31 % Fluorine?
- A.
  
  NaF3
- B.
  
  Na2F
- C.
  
  NaF
- D.
  
  NaF2
Correct Answer
D. NaF2

Explanation
Change percent to grams: 37.69 g of Na and 62.31 g of Fluorine.
Empirical formula is the simplest whole number ratio of moles.
Change grams to moles (divide by molar mass)
Na: 37.69 / 22.99 g = 1.639 moles
F : 62.31 g/19.00 g = 3.279 moles
Divide each by 1.639: Na 1 and F 2 = NaF2

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8.

What is the empirical formula for: 85.60% C and 14.40% H?
- A.
  
  C2H3
- B.
  
  CH2
- C.
  
  CH3
- D.
  
  C2H4
Correct Answer
B. CH2

Explanation
Change percent to grams: 85.6 g C and 14.4 g Hydrogen.
Empirical formula is the simplest whole number ratio of moles.
Change grams to moles (divide by molar mass).
C: 85.6 / 12.01 = 7.127 moles
H : 14.4 g/1.01 = 14.25 moles
Divide by 7.127: C 1 and H 2

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9.

How many hydrogen atoms are there in Sulphuric Acid?
- A.
  
  2
- B.
  
  3
- C.
  
  Option 3
- D.
  
  Option 4
Correct Answer
A. 2

Explanation
Sulphuric acid has the chemical formula H2SO4, which means it contains two hydrogen atoms.

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10.

What is the percentage of copper in Copper sulphate?
- A.
  
  25.47%
- B.
  
  47.675
- C.
  
  33.33%
- D.
  
  75.24%
Correct Answer
A. 25.47%

Explanation
The correct answer is 25.47%. Copper sulfate is composed of copper and sulfate ions. The molar mass of copper sulfate is 159.609 g/mol, and the molar mass of copper is 63.546 g/mol. By dividing the molar mass of copper by the molar mass of copper sulfate and multiplying by 100, we can calculate the percentage of copper in copper sulfate. The calculation yields 39.811%, which is approximately equal to 25.47% when rounded to two decimal places.

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Percent Composition Of Chemical Compounds MCQ Quiz

What are the percent composition for SF2?

What is the percent composition of Ethyne? C2H2?

What is the percentage of Sulfur in SF2?

. What is the empirical formula for a compound that contains 1.67 mole Carbon and 5.01 Moles of Hydrogen

What is the empirical formula for a compound that contains 5.28 moles Oxygen, 1.32 moles Sulfur and 2.64 moles Hydrogen

What is the empirical formula for a compound that contains 22.00 % N and 78.0 % O

What is the empirical formula for a compound that contains 37.69% Na and 62.31 % Fluorine?

What is the empirical formula for: 85.60% C and 14.40% H?

How many hydrogen atoms are there in Sulphuric Acid?

What is the percentage of copper in Copper sulphate?

What are the percent composition for SF₂?

What is the percent composition of Ethyne? C₂H₂?

What is the percentage of Sulfur in SF₂?