Equation Lesson - Parts, Types, and Examples

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Lesson Overview



An equation is a mathematical statement showing that two things are equal. It has an equal sign (=) between two expressions.

Example: 

2x +3=7

This means that when you solve for x, the equation is balanced.

Parts of an Equation

Key Components of Algebraic Expressions

TermDefinitionExample
VariableA symbol, like y, that represent an unknown value.In 2y+9+15, y is the variable.
CofficientThe number in font of a variable.In 2y+9=15, 9 and 15 are constants
ConstantA number without a variable.
In 2y+9=15, 2 is the Coefficients
OperatorSymbols like+,-,x,* used to perform operations.In 2y+9=15, + and = are Operations.



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Types of Equations

Type of EquationDefinitionExample
Linear EquationThe highest power of the variable is 1.2x + 3 = 7
Quadratic EquationThe variable is raised to the power of 2.x² - 4x + 4 = 0
Cubic EquationThe variable is raised to the power of 3.x³ - 3x² + 2x - 1 = 0
Polynomial EquationVariables have powers greater than 2.x³ + 2x² + x = 0




Solving Different Types of Equations

  1. Linear Equations
  • Combine like terms.
  • Isolate the variable.

Example: Solve 2x + 5 = 15

Step 1: 2x = 10 (Subtract 5 from both sides).

Step 2:  x = 5 (Divide both sides by 2).





2. Quadratic Equations

  • Factorize or use the quadratic formula: x = (-b ± √(b² - 4ac)) / 2a

Example: Solve x² - 5x + 6 = 0

Step 1: (x - 2)(x - 3) = 0 (Factorize).

Step 2: x = 2 or x = 3.

3. Cubic Equations

  • Factor or use synthetic division to simplify the cubic equation.

Example: Solve x³ - 6x² + 11x - 6 = 0

Step 1: Check for possible rational roots using the Rational Root Theorem. Try x = 1.

Step 2: Divide the cubic equation by (x - 1) using synthetic or long division.
This gives you: x² - 5x + 6 = 0.

Step 3: Factor the quadratic equation: (x - 2)(x - 3) = 0.

Step 4: Solve for x: x = 1, 2, or 3.

4. Polynomial Equations

  • Factor the polynomial and solve using the Zero-Product Property.

    Example: Solve x⁴ - 5x² + 4 = 0

    Step 1: Let y = x². The equation becomes y² - 5y + 4 = 0.

    Step 2: Factor the quadratic equation: (y - 1)(y - 4) = 0.

    Step 3: Solve for y: y = 1 or y = 4.

    Step 4: Substitute back x² for y: x² = 1 or x² = 4.

    Step 5: Solve for x: x = ±1 or x = ±2.


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Equation vs Expression

FeatureEquationExpression
DefinitionA mathematical statement showing equality using an "=" sign.A mathematical phrase without an "=" sign.
ContainsVariables, constants, operators, and an equal sign.Variables, constants, and operators.
Example2x + 5 = 102x + 5
PurposeShows a relationship between two expressions.Represents a value or calculation.

Note:

Equations can be solved to find the value of variables.

Expressions cannot be solved but can be simplified.


How to Graph an Equation

Graphing a linear equation involves solving it and plotting the solutions on a coordinate plane. Follow these steps:

  • Convert to slope-intercept form

Rewrite the equation as y = mx + b, where m is the slope and b is the y-intercept.

  • Generate points

Find at least three (x, y) pairs that satisfy the equation using trial and error.

  • Find intercepts
  • Y-Intercept: Set x = 0 and solve for y.
  • X-Intercept: Set y = 0 and solve for x.

These give the points (0, b) and (a, 0).

  • Create a table

Organize the x and y values in a table for reference.

  • Plot the points

Mark the points, including the intercepts, on the graph.

  • Draw the line

Connect the points to form a straight line representing the equation

Example: Draw a graph of the linear equation x+3y=9.

Step 1: Rewrite the Equation in Slope-Intercept Form

The slope-intercept form is y=mx+c, where:

  • m is the slope.
  • c is the y-intercept.

Rearrange x+3y=9 to solve for y:

3y=−x+9(subtract x from both sides)

y=−1/3​x+3(divide by 3)

Now, the equation is y=−1/3​x+3.

Step 2: Identify Key Features

From the slope-intercept form y=−1/3​x+3:

  • The slope (m) is −1/3​, which means the line decreases by 1 unit vertically for every 3 units it moves to the right.
  • The y-intercept (c) is 3, meaning the line crosses the y-axis at y=3.

Step 3: Find Two or More Points

Choose values for x to find corresponding values for y:

Point 1: x=0 (y-intercept)y=−1/3​(0)+3=3

Point: (0,3).

Point 2: x=3y=−1/3​(3)+3=−1+3=2

Point: (3,2).

Point 3: x=6y=−1/3​(6)+3=−2+3=1

Point: (6,1).

Step 4: Plot the Points

On a graph:

  • Plot (0,3) (y-intercept).
  • Plot (3,2).
  • Plot (6,1).

Step 5: Draw the Line

Use a ruler to connect the points, extending the line in both directions. This represents the equation x+3y=9.

Step 6: Verify

Optionally, test another point to confirm it lies on the line. For example:

  • Let x=−3:

y=−1/3​(−3)+3=1+3=4

Point: (−3,4).

Plot (−3,4) and confirm it aligns with the line.

Graph Characteristics

  • The line decreases due to the negative slope.
  • The y-intercept is at (0,3).
  • The x-intercept can be calculated by setting y=0 in the original equation:

x+3(0)=9⇒x=9

Thus, the x-intercept is (9,0).

By combining these insights, you have a complete graph of the equation x+3y=9.

See the values of x and y in the following table.

x036

y321

Fig: Graph representing the linear equation x+3y=9



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Common Mistakes and Tips for Solving Equations


MistakeExampleTipCorrected Example
Not balancing both sides2x+3=7, subtracting 3 only on one sideApply the same operation on both sides.2x+3−3=7−3→2x=4
Combining terms incorrectly2x+3y=7, adding as 5xyCombine only like terms.2x+3y stays as is.
Ignoring negative signs−x+5=10, solving as 𝑥+5=10Watch for negative signs.−x+5=10→x=−5
Misplacing fractions/powersx/2=3, solving as 𝑥=3+2Simplify carefully.x/2=3→x=3×2→x=6

Example of Equations

Example 1:

Solve for the variable in the given equations:

(a) 4y + 3 = 19

(b) 2x - 5 = 11

(c) z/4 = 3

(d) a + 7 = 15

Solution:

(a) 4y + 3 = 19

4y = 19 - 3

4y = 16

y = 16 / 4

y = 4

The variable is "y," and the solution is y = 4.

(b) 2x - 5 = 11

2x = 11 + 5

2x = 16

x = 16 / 2

x = 8

The variable is "x," and the solution is x = 8.

(c) z/4 = 3

z = 3 × 4

z = 12

The variable is "z," and the solution is z = 12.

(d) a + 7 = 15

a = 15 - 7

a = 8

The variable is "a," and the solution is a = 8.

Example 2:

Emily buys two books and a bag. The total cost is $50. If the cost of the bag is $30 and each book costs the same, represent this situation as an equation and find the cost of each book.

Solution:

Let the cost of one book = $x.

The cost of the bag = $30.

The total cost = $50.

The equation is:

2x + 30 = 50

Solving:

2x = 50 - 30

2x = 20

x = 20 / 2

x = 10

The cost of each book is $10.

Example 3:

A rectangle's length is 3 times its width. The perimeter of the rectangle is 48 units. Represent this as an equation and calculate the dimensions.

Solution:

Let the width = w units and the length = 3w units.

Perimeter = 2(length + width)

The equation is:

2(3w + w) = 48

Simplifying:

2(4w) = 48

8w = 48

w = 48 / 8

w = 6

Width = 6 units, Length = 3 × 6 = 18 units.



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