2.2.12 Conservation Of Linear Momentum / Newton's 3rd Law

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| By Gboulton
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Quizzes Created: 18 | Total Attempts: 10,840
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  • 1/6 Questions

    Why does a gangstah (note new spelling) not actually fly back through a glass window when he "takes" a bullet

    • The bullet is travelling too fast
    • He might will be wearing a bullet proof vest
    • The total momentum before he is it is too small to make a significant change in his velocity
    • The bullet gives all the momentum to the person that fired the bullet.
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About This Quiz

Explore the principles of conservation of momentum and Newton's 3rd Law through practical scenarios. Understand momentum in collisions, effects of external forces, and action-reaction pairs. Essential for students mastering physics fundamentals.

2.2.12 Conservation Of Linear Momentum / Newtons 3rd Law - Quiz

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  • 2. 

    According to newton's 3rd Law, If I push a car forward,

    • The car will accelerate slowly

    • The car will move at constant velocity

    • The car will not move at all

    • The car will push me back

    • I have been taking too many high energy drinks.

    Correct Answer
    A. The car will push me back
    Explanation
    According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When you push a car forward, you are applying a force on the car. As a result, the car will push back on you with an equal and opposite force. This is why the correct answer is "the car will push me back." The acceleration or movement of the car is not mentioned in the question, so it is not relevant to the answer. The reference to high energy drinks is unrelated and does not affect the outcome described by Newton's third law.

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  • 3. 

    If the gangstah stands on the pavement, which are newton's third law pair of forces

    • The gansta pushes down on the ground, and the ground pushes up on the gansta (reaction)

    • The earth pulls down on the gangster, and the pavement pushes up on the ganster

    • The ganster's mass pulls up on the earth, and the ground pushes up on the gangster.

    Correct Answer
    A. The gansta pushes down on the ground, and the ground pushes up on the gansta (reaction)
    Explanation
    When the gangsta stands on the pavement, the force exerted by the gangsta pushing down on the ground is the action force. According to Newton's third law, there is always an equal and opposite reaction force. In this case, the reaction force is the ground pushing up on the gangsta. This pair of forces follows Newton's third law, where the action and reaction forces are equal in magnitude and opposite in direction.

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  • 4. 

    Which is the best wording to describe the conservation of momentum

    • Momentum before a collision is the same as the momentum after the collision

    • Momentum before a collision is the same as the momentum after the collision if there are no external forces

    • The total momentum before a collision is equal to the total momentum after a collision

    • The total momentum before a collision is equal to the total momentum after the collision if the total external forces acting upon the system is zero.

    Correct Answer
    A. The total momentum before a collision is equal to the total momentum after the collision if the total external forces acting upon the system is zero.
    Explanation
    The best wording to describe the conservation of momentum is that the total momentum before a collision is equal to the total momentum after the collision if the total external forces acting upon the system is zero. This means that in a closed system where no external forces are acting, the total momentum of the system remains constant before and after a collision.

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  • 5. 

    In explosion type collision, two static trolleys of masses 2Kg and 3Kg start to move apart (pushed by a spring between them),  What is the velocity of the first trolley if the 3Kg trolley moves with velocity 4m/s?

    • 3m/s

    • -3 m/s

    • 4 m/s

    • -4 m/s

    • 6 m/s

    • -6 m/s

    Correct Answer
    A. -6 m/s
    Explanation
    In an explosion type collision, the two trolleys move apart from each other after being pushed by a spring. The momentum of the system is conserved, which means that the total momentum before the collision is equal to the total momentum after the collision. Since the 3Kg trolley moves with a velocity of 4m/s, the momentum of the system after the collision is (3Kg * 4m/s) + (2Kg * v), where v is the velocity of the 2Kg trolley. Since the total momentum before the collision is zero (since the trolleys are initially static), the total momentum after the collision must also be zero. Solving the equation (3Kg * 4m/s) + (2Kg * v) = 0, we find that v = -6m/s.

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  • 6. 

    Are there any parts of the conservation of momentum and Newton's 3rd Law that needs to be reviewed next lesson?  Can you formulate a question

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  • Current Version
  • May 28, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Oct 18, 2012
    Quiz Created by
    Gboulton
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