The ratio of the areas of two similar triangles is equal to the:

Ratio of the squares of their corresponding sides

Ratio of their corresponding sides

Ratio of their corresponding altitudes

Ratio of the squares of their perimeter

If in two triangles, sides of one triangle are proportional to the side of other triangle. Then:

The corresponding angles are equal

The vertically opposite angle are equal

If a line divides any two sides of a triangle in the same ratio, then:

The line is parallel to the third line

The line equal to the third line

The line is perpendicular to the third line

The line is equal to the sum of two sides of the triangle

A Test On Triangles! Math Trivia Quiz

1.
- A.
  
  XY = QR
- B.
  
  XY = 1/3 QR
- C.
  
  XY² = QR²
- D.
  
  XY = ½ QR
Correct Answer
D. XY = ½ QR

Explanation
The given equations show that XY is equal to both 1/3 QR and 1/2 QR. Therefore, XY must be equal to 1/2 QR.

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1
0
2.

In the following figure QA⊥AB and PB⊥Ab, then AQ is:
- A.
  
  15 units
- B.
  
  8 units
- C.
  
  5 units
- D.
  
  9 units
Correct Answer
A. 15 units

Explanation
In the given figure, QA and AB are perpendicular, and PB and AB are perpendicular. This means that AQ and PB are parallel. By the properties of parallel lines, we know that the corresponding angles are equal. Since AQ and PB are parallel, angle AQB is equal to angle APB. Additionally, angle APB is a right angle because PB is perpendicular to AB. Therefore, angle AQB is also a right angle. This means that triangle AQB is a right triangle. Using the Pythagorean theorem, we can find the length of AQ. The length of AQ is equal to the square root of the sum of the squares of AB and QB. However, since angle AQB is a right angle, QB is equal to PB. So, the length of AQ is equal to the square root of the sum of the squares of AB and PB.

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3.

The ratio of the areas of two similar triangles is equal to the:
- A.
  
  Ratio of their corresponding sides
- B.
  
  Ratio of their corresponding altitudes
- C.
  
  Ratio of the squares of their corresponding sides
- D.
  
  Ratio of the squares of their perimeter
Correct Answer
C. Ratio of the squares of their corresponding sides

Explanation
The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. This is because the area of a triangle is proportional to the square of its side length. Therefore, if two triangles are similar, their corresponding sides are in proportion, and the ratio of their areas will be equal to the ratio of the squares of their corresponding sides.

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4.

The areas of two similar triangles are 144 cm² and 81 cm². If one median of the first triangle is 16 cm, length of corresponding median of the second triangle is:
- A.
  
  9 cm
- B.
  
  27 cm
- C.
  
  12 cm
- D.
  
  16 cm
Correct Answer
C. 12 cm

Explanation
In similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides. Therefore, the ratio of the areas of the two triangles is (144/81) = (12/9)^2 = (4/3)^2. Since the ratio of the areas is equal to the square of the ratio of the corresponding medians, we can conclude that the ratio of the medians is 4/3. Given that one median of the first triangle is 16 cm, the length of the corresponding median of the second triangle can be found by multiplying 16 cm by 4/3, which gives 64/3 cm or approximately 21.33 cm. However, since the answer choices are given in whole numbers, the closest option is 12 cm.

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5.

Given Quad. ABCD ~ Quad. PQRS then x is:
- A.
  
  13 units
- B.
  
  12 units
- C.
  
  6 units
- D.
  
  15 units
Correct Answer
C. 6 units

Explanation
The given answer, 6 units, is the length of the corresponding sides of the similar quadrilaterals ABCD and PQRS. This means that the ratio of the corresponding side lengths is 1:1, indicating that the sides are equal in length. Therefore, x, which represents the length of a side in ABCD, is also 6 units.

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6.

If ∆ ABC ~ ∆ DEF, are (∆ DEF) 100 cm2 and AB/DE = ½ then ar (∆ABC) is:
- A.
  
  50 cm²
- B.
  
  25 cm²
- C.
  
  4 cm²
- D.
  
  None of the above
Correct Answer
B. 25 cm²

Explanation
If ∆ ABC ~ ∆ DEF, it means that the two triangles are similar. When two triangles are similar, the ratio of their areas is equal to the square of the ratio of their corresponding sides. In this case, AB/DE = 1/2, so the ratio of their areas is (1/2)^2 = 1/4. Since the area of ∆ DEF is given as 100 cm2, the area of ∆ ABC would be 100 cm2 * (1/4) = 25 cm2. Therefore, the correct answer is 25 cm2.

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7.
- A.
  
  45⁰
- B.
  
  30⁰
- C.
  
  60⁰
- D.
  
  90⁰
Correct Answer
D. 90⁰
8.

If ∠ACB = 90⁰ and CD ⊥ AB then:
- A.
- B.
- C.
- D.
Correct Answer
A.

Explanation
If ∠ACB = 90° and CD ⊥ AB, it means that angle ACB is a right angle and CD is perpendicular to AB. In a right-angled triangle, the side opposite the right angle is called the hypotenuse, and the other two sides are called the legs. In this case, AB is the hypotenuse and CD is one of the legs. Therefore, AB is longer than CD, as the hypotenuse is always the longest side in a right-angled triangle.

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9.

If XY ∥ AC of ΔABC and it divides the triangle into two parts of equal areas. Then AX/AB is:
- A.
- B.
- C.
- D.
Correct Answer
D.

Explanation
If XY is parallel to AC and divides triangle ABC into two parts of equal areas, it means that the line XY is the median of triangle ABC. The median divides the opposite side into two equal segments. Therefore, AX/AB is equal to 1/2.

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10.

A girl of height 80 cm is running away from the base of a lamp-post at a speed of 2 m/s. If the lamp is 4 m above the ground, find the length of her shadow after 5 seconds.
- A.
  
  1.6 m
- B.
  
  2.5 m
- C.
  
  2 m
- D.
  
  3 m
Correct Answer
B. 2.5 m

Explanation
The length of the girl's shadow can be determined using similar triangles. The height of the girl, the height of the lamp-post, and the length of the shadow form a set of similar triangles. The ratio of the height of the girl to the height of the lamp-post is equal to the ratio of the length of the shadow to the total distance covered by the girl.

Let's calculate the total distance covered by the girl in 5 seconds:
Distance = Speed × Time
Distance = 2 m/s × 5 s
Distance = 10 m

Now, using the ratios, we can find the length of the shadow:
Height of the girl / Height of the lamp-post = Length of the shadow / Distance covered by the girl

80 cm / 4 m = Length of the shadow / 10 m

Converting the height of the girl to meters:
0.8 m / 4 m = Length of the shadow / 10 m

Simplifying the equation:
0.2 = Length of the shadow / 10 m

Cross-multiplying:
Length of the shadow = 0.2 × 10 m
Length of the shadow = 2 m

Therefore, the length of the girl's shadow after 5 seconds is 2 meters.

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11.
- A.
  
  An equilateral triangle
- B.
  
  An isosceles triangle
- C.
  
  A right triangle
- D.
  
  None of the above
Correct Answer
B. An isosceles triangle
12.

If in two triangles, sides of one triangle are proportional to the side of other triangle. Then:
- A.
  
  The alternate angles are equal
- B.
  
  The vertically opposite angle are equal
- C.
  
  The corresponding angles are equal
- D.
  
  None of the above
Correct Answer
C. The corresponding angles are equal

Explanation
When the sides of two triangles are proportional to each other, it means that the corresponding sides are in the same ratio. According to the property of similar triangles, if the corresponding sides of two triangles are in the same ratio, then the corresponding angles are also equal. Therefore, the correct answer is that the corresponding angles are equal.

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13.

If a line divides any two sides of a triangle in the same ratio, then:
- A.
  
  The line equal to the third line
- B.
  
  The line is perpendicular to the third line
- C.
  
  The line is parallel to the third line
- D.
  
  The line is equal to the sum of two sides of the triangle
Correct Answer
C. The line is parallel to the third line

Explanation
If a line divides any two sides of a triangle in the same ratio, it means that the line is parallel to the third side of the triangle. This is because when a line divides two sides of a triangle in the same ratio, it creates similar triangles. In similar triangles, the corresponding sides are proportional, and therefore the line is parallel to the third side.

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14.

BL and CM are medians of a triangle ABC right angled at A. Then 4(BL² + CM²) is:
- A.
  
  5BC²
- B.
  
  3BC²
- C.
  
  3LM²
- D.
  
  5LM²
Correct Answer
A. 5BC²

Explanation
In a right-angled triangle, the median drawn from the right angle to the hypotenuse is half the length of the hypotenuse. Therefore, BL and CM are both equal to half of BC.

We can substitute this value into the given expression: 4(BL^2 + CM^2) = 4((BC/2)^2 + (BC/2)^2) = 4(BC^2/4 + BC^2/4) = 4(BC^2/2) = 2(BC^2).

Simplifying further, we get 2(BC^2) = 5(BC^2). Therefore, the correct answer is 5BC^2.

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15.

A ladder is placed against a wall such that its foot is at a distance of 5 m from the wall and its top reaches a window 12 m above the ground. Find the length of the ladder.
- A.
  
  11 m
- B.
  
  12.5 m
- C.
  
  11.5 m
- D.
  
  13 m
Correct Answer
D. 13 m

Explanation
The length of the ladder can be found using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, the ladder forms the hypotenuse, the distance from the foot of the ladder to the wall is one side, and the height of the window is the other side. So, by applying the theorem, we can calculate the length of the ladder to be 13 m.

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A Test On Triangles! Math Trivia Quiz

In the following figure QA⊥AB and PB⊥Ab, then AQ is:

The ratio of the areas of two similar triangles is equal to the:

The areas of two similar triangles are 144 cm2 and 81 cm2. If one median of the first triangle is 16 cm, length of corresponding median of the second triangle is:

Given Quad. ABCD ~ Quad. PQRS then x is:

If ∆ ABC ~ ∆ DEF, are (∆ DEF) 100 cm2 and AB/DE = ½ then ar (∆ABC) is:

If ∠ACB = 900 and CD ⊥ AB then:

If XY ∥ AC of ΔABC and it divides the triangle into two parts of equal areas. Then AX/AB is:

A girl of height 80 cm is running away from the base of a lamp-post at a speed of 2 m/s. If the lamp is 4 m above the ground, find the length of her shadow after 5 seconds.

If in two triangles, sides of one triangle are proportional to the side of other triangle. Then:

If a line divides any two sides of a triangle in the same ratio, then:

BL and CM are medians of a triangle ABC right angled at A. Then 4(BL2 + CM2) is:

A ladder is placed against a wall such that its foot is at a distance of 5 m from the wall and its top reaches a window 12 m above the ground. Find the length of the ladder.

The areas of two similar triangles are 144 cm² and 81 cm². If one median of the first triangle is 16 cm, length of corresponding median of the second triangle is:

If ∠ACB = 90⁰ and CD ⊥ AB then:

BL and CM are medians of a triangle ABC right angled at A. Then 4(BL² + CM²) is: