Class 10: Light (Refraction) Quiz

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| By Bhudev Singh
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Bhudev Singh
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Quizzes Created: 2 | Total Attempts: 3,433
| Attempts: 1,611
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  • 1/15 Questions

    If ray of light is parallel to principal-axis then, the ray passing through the

    • Cf
    • Centre of lens
    • Focus
    • None
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Class 10: Light (Refraction) Quiz - Quiz

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  • 2. 

    Ratio of the speed of light in vacuum to the speed of light in medium is called

    • Refraction

    • Diffraction

    • Refractive Index

    • Interference

    Correct Answer
    A. Refractive Index
    Explanation
    The ratio of the speed of light in vacuum to the speed of light in a medium is called the refractive index. Refractive index determines how much light is bent when it passes from one medium to another, such as from air to water. It is a measure of how much the speed of light is reduced in a medium compared to its speed in a vacuum.

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  • 3. 

    Unit of Refractive Index:

    • Siemen

    • Rho

    • Ms-1

    • No unit

    Correct Answer
    A. No unit
    Explanation
    The refractive index is a dimensionless quantity that represents the ratio of the speed of light in a vacuum to the speed of light in a given medium. It is a measure of how much the speed of light is reduced when it passes through a material. Since it is a ratio, it does not have any units associated with it. Therefore, the correct answer is "no unit".

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  • 4. 

    Which of the following in diverging lens ?

    • Concave lens

    • Convex lens

    Correct Answer
    A. Concave lens
    Explanation
    A diverging lens is a lens that causes parallel light rays to spread out or diverge. A concave lens is a type of diverging lens because it is thinner at the center and thicker at the edges. When light passes through a concave lens, it is bent away from the principal axis, causing the rays to spread out. On the other hand, a convex lens is thicker at the center and thinner at the edges, causing light rays to converge towards the principal axis. Therefore, the correct answer is concave lens.

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  • 5. 

    Power of convex lens is negative.

    • True

    • False

    Correct Answer
    A. False
    Explanation
    The power of a convex lens is actually positive, not negative. The power of a lens is a measure of its ability to converge or diverge light, and a convex lens is designed to converge light. It is thicker in the middle and thinner at the edges, causing light rays to converge after passing through it. Therefore, the correct answer is false.

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  • 6. 

    An object is placed at a distance of 4 cm from a concave lens of focal length 12 cm, Find the nature. 

    • Real & inverted

    • Virtual & erect

    Correct Answer
    A. Virtual & erect
    Explanation
    When an object is placed at a distance of 4 cm from a concave lens with a focal length of 12 cm, the image formed is virtual and erect. This is because the object is placed within the focal length of the lens, causing the rays of light to diverge after passing through the lens. As a result, the image formed is virtual (cannot be projected onto a screen) and erect (upright).

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  • 7. 

    A lens of short focal length has :

    • More power

    • Less power

    • Moderate power

    • None

    Correct Answer
    A. More power
    Explanation
    A lens with a short focal length has more power because power is inversely proportional to focal length. A shorter focal length means that the lens can bring light rays to a focus over a shorter distance, resulting in a greater bending of the light and a stronger focusing ability. This increased bending of light allows the lens to magnify objects more effectively and produce a larger image. Therefore, a lens with a short focal length has more power compared to lenses with longer focal lengths.

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  • 8. 

    If v/u = -2 and height of object is -15 cm. Find the height of image.

    • -30 cm

    • +30 cm

    • -7.5 cm

    • +7.5 cm

    Correct Answer
    A. +30 cm
    Explanation
    When the height of the object is negative (-15 cm) and the ratio of v/u is negative (-2), it indicates that the image formed is virtual and upright. The negative sign in the object's height indicates that the image is also inverted. Therefore, the height of the image would be positive and the same as the object's height, which is +30 cm.

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  • 9. 

    If focal length of converging lens is 50 cm. Find the power of the lens. 

    • 2 diopters

    • 4 diopters

    • 5 diopters

    • 6 diopters

    Correct Answer
    A. 2 diopters
  • 10. 

    Formula of power of lens :

    • 1/f(in m)

    • 100/f(in cm)

    • 1/1000f (in km)

    • All above

    Correct Answer
    A. All above
    Explanation
    The formula for the power of a lens can be expressed in different units: 1/f in meters, 100/f in centimeters, and 1/1000f in kilometers. Therefore, the correct answer is "all above" as all the given options are valid representations of the formula for the power of a lens.

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  • 11. 

    Unit of power of lens is ________

    Correct Answer
    dioptre
    Explanation
    The unit of power of a lens is dioptre. The power of a lens is a measure of its ability to converge or diverge light. It is defined as the reciprocal of the focal length of the lens in meters. The unit "dioptre" is used to represent this power and is abbreviated as "D". A positive power indicates a converging lens, while a negative power indicates a diverging lens.

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  • 12. 

    How many types of lenses ?

    • 4

    • 3

    • 2

    • 1

    Correct Answer
    A. 2
    Explanation
    There are two main types of lenses: convex and concave. Convex lenses are thicker in the middle and converge light rays, while concave lenses are thinner in the middle and diverge light rays.

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  • 13. 

    A lens of focal length 12 cm forms an erect image three times the size of object. Find distance b/w object and image.

    • 16 cm

    •  32 cm

    • 8 cm

    • 24 cm

    Correct Answer
    A. 16 cm
    Explanation
    The distance between the object and the image can be determined using the lens formula 1/f = 1/v - 1/u, where f is the focal length, v is the distance of the image from the lens, and u is the distance of the object from the lens. In this case, the lens has a focal length of 12 cm and the image is three times the size of the object, indicating that the magnification is 3. By substituting the values into the formula and solving for u, we find that the distance between the object and the image is 16 cm.

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  • 14. 

    The ______ is the imaginary line that is perpendicular to the surface at the point where the light ray strikes.

    Correct Answer
    Normal, normal
    Explanation
    The normal is a line that is perpendicular to a surface at a particular point. It is often used in optics to describe the angle of incidence and reflection of light rays. The angle of incidence is the angle between the incident ray and the normal, while the angle of reflection is the angle between the reflected ray and the normal.

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  • 15. 

    Write the formula of power of combination of lenses,P =________ 

    Correct Answer
    p1 + p2
    Explanation
    The formula for the power of a combination of lenses is obtained by adding the powers of the individual lenses together. In this case, the formula is P = p1 + p2, where p1 represents the power of the first lens and p2 represents the power of the second lens. This formula allows us to calculate the overall power of the combination of lenses when they are used together.

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  • Current Version
  • Nov 07, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Jun 14, 2020
    Quiz Created by
    Bhudev Singh
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