Exam 7: Inheritance Patterns
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- 1.
In humans, pigmented skin is dominant to non-pigmented skin (albinism). What is the genotype of an individual with albinism?
- A.
Carrier
- B.
Heterozygous
- C.
Homozygous dominant
- D.
Homozygous recessive
Correct Answer
D. Homozygous recessiveExplanation
An individual with albinism has a genotype of homozygous recessive. This means that both of their alleles for the pigmentation gene are recessive, resulting in the absence of pigmentation in their skin. Albinism is a genetic condition that is inherited when an individual receives two copies of the recessive allele for pigmentation.Rate this question:
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- 2.
Adrenoleukodystrophy (ALD) is a sex-linked recessive trait that affects the nervous system. In one family, the father, mother, daughter, and elder son do not have ALD, while the younger son has ALD. Who must be a carrier of the ALD allele?
- A.
Father
- B.
Mother
- C.
Daughter
- D.
Elder son
Correct Answer
B. MotherExplanation
In this case, the mother must be a carrier of the ALD allele. Since ALD is a sex-linked recessive trait, it means that the gene responsible for ALD is located on the X chromosome. Males have one X and one Y chromosome, while females have two X chromosomes. The father does not have ALD, so he cannot be a carrier. The elder son does not have ALD, so he cannot be a carrier either. The younger son has ALD, which means he inherited the allele from his mother. The daughter does not have ALD, but since she has two X chromosomes, she could still be a carrier. However, since the question states that the mother does not have ALD, it implies that she must be a carrier.Rate this question:
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- 3.
Cystic fibrosis is a genetic disease in which excess mucus accumulates in the lungs and digestive system of affected individuals. Males and females must inherit 2 alleles with this mutation to have the disease. What is the mode of inheritance of cystic fibrosis?
- A.
Autosomal dominant
- B.
Autosomal recessive
- C.
Sex-linked dominant
- D.
Sex-linked recessive
Correct Answer
B. Autosomal recessiveExplanation
Cystic fibrosis is a recessive genetic disease, meaning that both copies of the gene must have the mutation for an individual to have the disease. This means that both males and females can be affected by cystic fibrosis, as it is not limited to a specific sex. The disease is inherited in an autosomal manner, meaning it is not linked to the sex chromosomes. Therefore, the correct answer is autosomal recessive.Rate this question:
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- 4.
Which event of meiosis reveals the mechanism for understanding Mendel’s laws of segregation and independent assortment?
- A.
Chromosome number is reduced during telophase I so gametes have half the standard number of chromosomes.
- B.
The arrangement of homologous chromosomes during metaphase I varies from cell to cell.
- C.
Centromeres break apart during anaphase II so that sister chromatids can move to opposite poles of the cell.
- D.
DNA is replicated during interphase before chromosomes condense and become attached to kinetochores.
Correct Answer
B. The arrangement of homologous chromosomes during metapHase I varies from cell to cell.Explanation
The arrangement of homologous chromosomes during metaphase I varies from cell to cell. This event of meiosis is important for understanding Mendel's laws of segregation and independent assortment because it is during metaphase I that the homologous chromosomes align randomly along the equator of the cell. This random alignment leads to the independent assortment of alleles, which is one of Mendel's laws. Additionally, the separation of homologous chromosomes during anaphase I, which follows metaphase I, is the mechanism that allows for the segregation of alleles, another of Mendel's laws. Therefore, the arrangement of homologous chromosomes during metaphase I is the event that reveals the mechanism for understanding Mendel's laws of segregation and independent assortment.Rate this question:
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- 5.
Two black guinea pigs bred and produced 3 black offspring and 2 albino offspring. Assuming no mutations, which guinea pigs must be heterozygous?
- A.
All 3 black offspring
- B.
Exactly 2 of the black offspring
- C.
Both albino offspring
- D.
Both parents
Correct Answer
D. Both parentsExplanation
Both parents must be heterozygous because they produced both black and albino offspring. In order for the albino phenotype to be expressed, the guinea pig must have two copies of the recessive allele. Therefore, both parents must have at least one copy of the recessive allele for albinism, making them heterozygous.Rate this question:
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- 6.
The genotype of F1 individuals from a dihybrid cross is AaBb x AaBB. What is the expected ratio of AaBb individuals in the F2 generation?
- A.
8/16
- B.
4/16
- C.
2/16
- D.
1/16
Correct Answer
B. 4/16Explanation
In a dihybrid cross, the F1 generation is produced by crossing two individuals that are heterozygous for two different traits. In this case, the genotype of the F1 individuals is AaBb x AaBB. When these individuals are crossed in the F2 generation, the expected ratio of AaBb individuals can be determined using the Punnett square. The possible genotypes of the offspring are AaBB, AaBb, AABb, and AABb. Out of these four possible genotypes, only one genotype is AaBb. Therefore, the expected ratio of AaBb individuals in the F2 generation is 1 out of 4, which can be simplified to 4/16.Rate this question:
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- 7.
Alkaptonuria is a genetic disorder of protein metabolism. The disorder is determined by 2 alleles at 1 locus. What is the genotype for Individual 1 in the diagram?
- A.
AA or Aa
- B.
AA
- C.
Aa
- D.
Aa
Correct Answer
C. AaExplanation
The genotype for Individual 1 in the diagram is Aa. This is because the disorder is determined by 2 alleles at 1 locus, and Individual 1 has one dominant allele (A) and one recessive allele (a), resulting in the heterozygous genotype Aa.Rate this question:
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- 8.
A trisomy of chromosome 21 causes what condition?
- A.
Albinism
- B.
Dwarfism
- C.
Down syndrome
- D.
Color blindness
Correct Answer
C. Down syndromeExplanation
A trisomy of chromosome 21 causes Down syndrome. Down syndrome is a genetic disorder that occurs when an individual has three copies of chromosome 21 instead of the usual two. This extra genetic material leads to various physical and intellectual disabilities. People with Down syndrome typically have characteristic facial features, developmental delays, and may experience other health issues such as heart defects and hearing problems.Rate this question:
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- 9.
Keisha passes a local dairy farm that has many brown cows, but only a few white cows. A dominant allele produces brown hair in cows and a recessive allele produces white hair. Which characteristic of any brown cow can Keisha identify?
- A.
The genotype of both of the cow’s parents
- B.
The genotype of the cow’s hair color
- C.
The phenotype of both of the cow’s parents
- D.
The phenotype of the cow’s hair color
Correct Answer
D. The pHenotype of the cow’s hair colorExplanation
Keisha can identify the phenotype of the cow's hair color because the question states that the dominant allele produces brown hair in cows and the recessive allele produces white hair. The phenotype refers to the observable characteristics of an organism, in this case, the color of the cow's hair. Therefore, by observing the cow's hair color, Keisha can determine if it is brown or white, which corresponds to the phenotype. The genotype, on the other hand, refers to the genetic makeup of an organism, which cannot be determined solely by observing the cow's hair color.Rate this question:
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- 10.
Jeanine inherited 2 alleles for round eye shape and has round eye shape. Her brother inherited 1 allele for round eye shape and 1 allele for almond eye shape and has almond eye shape. What type of trait is round eye shape?
- A.
Co-dominant
- B.
Dominant
- C.
Recessive
- D.
Sex-linked
Correct Answer
C. RecessiveExplanation
Round eye shape is a recessive trait. This is because Jeanine inherited 2 alleles for round eye shape and has round eye shape, while her brother inherited 1 allele for round eye shape and 1 allele for almond eye shape and has almond eye shape. This indicates that the almond eye shape allele is dominant over the round eye shape allele, and round eye shape is only expressed when an individual has 2 copies of the recessive allele.Rate this question:
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- 11.
In humans, red-green color blindness is a recessive, sex-linked trait. The chromosomes and alleles associated with color blindness are represented in this chart. Which child could NOT be born to these parents; a female (XBXb) and a male (XBY)?
- A.
Color-blind daughter
- B.
Color-blind son
- C.
Daughter with normal color vision
- D.
Son with normal color vision
Correct Answer
A. Color-blind daughterExplanation
A female with genotype XBXb cannot be color-blind because she has one normal X chromosome (XB) which will provide the necessary gene for normal color vision. Color blindness is a recessive trait, so both X chromosomes would need to carry the color blindness allele (Xb) in order for a female to be color-blind. Since the female parent has one normal X chromosome, she cannot pass on the color blindness allele to her daughter. Therefore, a color-blind daughter cannot be born to these parents.Rate this question:
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- 12.
The pedigree shows 3 generations of a family and the family’s incidences of color blindness, a sex-linked, recessive trait. Which pair of females must have the same genotype?
- A.
3 and 5
- B.
7 and 11
- C.
8 and 13
- D.
10 and 14
Correct Answer
C. 8 and 13Explanation
In the given pedigree, females 8 and 13 must have the same genotype. This can be determined by observing that both females have affected sons (squares) and unaffected daughters (circles), indicating that they are carriers of the recessive color blindness trait. Since color blindness is a sex-linked trait, it is only expressed in males. Therefore, females who are carriers will have the same genotype.Rate this question:
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- 13.
Which example best illustrates Mendel’s law of independent assortment?
- A.
Two short-haired cats produce a litter of 4 kittens including 1 long-haired and 3 short-haired.
- B.
A color-blind man and a woman with normal vision produce a son with normal vision and a color-blind daughter.
- C.
A tall purple-flowered pea plant and a short white-flowered pea plant are crossed, producing offspring including tall white-flowered pea plants.
- D.
A red-flowered snapdragon and a white-flowered snapdragon are crossed, producing offspring with pink flowers.
Correct Answer
C. A tall purple-flowered pea plant and a short white-flowered pea plant are crossed, producing offspring including tall white-flowered pea plants.Explanation
The example that best illustrates Mendel's law of independent assortment is when a tall purple-flowered pea plant and a short white-flowered pea plant are crossed, producing offspring including tall white-flowered pea plants. This is because the traits of height and flower color are independently inherited, meaning that they are not linked together and can be inherited separately. In this case, the offspring inherit the tall trait from one parent and the white flower trait from the other parent, demonstrating independent assortment.Rate this question:
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- 14.
Horses born to 2 palomino (golden-coated) horses have a 25% chance of having a white coat, a 25% chance of having a chestnut (brown) coat, and a 50% chance of having a palomino coat. Which description of inheritance best explains the coat-color trait in these horses?
- A.
Palomino coat color is a recessive trait.
- B.
Palomino coat color is a dominant trait.
- C.
Coat color is an incompletely dominant trait.
- D.
Coat color is a sex-linked trait.
Correct Answer
C. Coat color is an incompletely dominant trait. -
- 15.
The X and Y chromosomes are called the
- A.
Extra chromosomes.
- B.
Phenotypes.
- C.
Sex chromosomes.
- D.
Autosomes.
Correct Answer
C. Sex chromosomes.Explanation
The X and Y chromosomes are called sex chromosomes because they determine an individual's biological sex. In humans, females have two X chromosomes (XX), while males have one X and one Y chromosome (XY). These chromosomes carry genes that are responsible for the development of sexual characteristics and reproductive systems. The term "sex chromosomes" is used to differentiate them from autosomes, which are non-sex chromosomes that determine other traits and characteristics in an individual.Rate this question:
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- 16.
Which of the following is the best explanation for the observation that females rarely get the disease hemophilia?
- A.
Large quantities of male hormones are necessary in order for the allele carrying the disease to be expressed.
- B.
Female fetuses that carry the allele for the disease die before birth.
- C.
A female could get the disease only by having a mother who is a carrier and a father who has the disease. Since most males with the disease do not survive to reproductive age, this is an extremely unlikely event.
- D.
A female could get the disease only by having parents who are both carriers of the disease. Because females cannot be carriers, this is an impossible event.
Correct Answer
C. A female could get the disease only by having a mother who is a carrier and a father who has the disease. Since most males with the disease do not survive to reproductive age, this is an extremely unlikely event.Explanation
Hemophilia is a recessive X-linked genetic disorder, meaning it is carried on the X chromosome. Males only have one X chromosome, so if they inherit the hemophilia allele, they will express the disease. Females, on the other hand, have two X chromosomes. For a female to get hemophilia, she would need to inherit the hemophilia allele from both her mother and father. However, since most males with hemophilia do not survive to reproductive age, it is rare for a female to have a father with the disease. Therefore, it is an extremely unlikely event for a female to get hemophilia.Rate this question:
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- 17.
In a mating between two parental types, one of which is homozygous dominant for two linked traits and one of which is homozygous recessive for the same two linked traits, evidence of crossing-over would be apparent in which of the following generations?
- A.
Parents
- B.
F1
- C.
F2
- D.
All of the above
Correct Answer
C. F2Explanation
In the F2 generation, evidence of crossing-over would be apparent. This is because crossing-over is the exchange of genetic material between homologous chromosomes during meiosis, resulting in the recombination of alleles. In the F1 generation, there would be no evidence of crossing-over as the parental types would remain intact. Therefore, the correct answer is F2.Rate this question:
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- 18.
Which of the following traits is controlled by multiple alleles in humans?
- A.
Sickle cell anemia
- B.
Blood type
- C.
Hemophilia
- D.
Pattern baldness
Correct Answer
B. Blood typeExplanation
Blood type is controlled by multiple alleles in humans. This means that there are more than two possible variations of the gene that determines blood type. The gene responsible for blood type has three alleles: A, B, and O. Each person inherits two alleles, one from each parent, determining their blood type. The combinations of these alleles result in four blood types: A, B, AB, and O. This is why blood type is considered to be controlled by multiple alleles in humans.Rate this question:
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- 19.
What would be the blood type of a person who inherited an A allele from one parent and an O allele from the other?
- A.
Type A
- B.
Type B
- C.
Type AB
- D.
Type O
Correct Answer
A. Type AExplanation
If a person inherits an A allele from one parent and an O allele from the other, their blood type would be type A. The A allele is dominant over the O allele, so even though they have one O allele, it will not affect their blood type.Rate this question:
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- 20.
While studying several generations of a particular family, a geneticist observed that a certain disease was found equally in males and females and that all children who had the disease had parents who also had the disease. The gene coding for this disease is probably
- A.
Sex-linked recessive.
- B.
Sex-linked dominant.
- C.
Autosomal recessive.
- D.
Autosomal dominant.
Correct Answer
D. Autosomal dominant.Explanation
The observation that the disease is found equally in males and females suggests that it is not sex-linked, as sex-linked diseases are usually more common in one gender. Additionally, the fact that all children who had the disease had parents who also had the disease indicates that it is a dominant trait, as both parents must have at least one copy of the gene for the disease to be passed on to their children. Therefore, the gene coding for this disease is likely autosomal dominant.Rate this question:
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- 21.
If both parents carry the recessive allele that causes cystic fibrosis, the chance that their child will develop the disease is
- A.
One in two.
- B.
One in four.
- C.
Two in five.
- D.
100%.
Correct Answer
B. One in four.Explanation
If both parents carry the recessive allele for cystic fibrosis, there is a one in four chance that their child will develop the disease. This is because both parents must pass on the recessive allele for the child to inherit the disease. In this case, there is a 25% chance that both parents will pass on the recessive allele, resulting in the child developing cystic fibrosis.Rate this question:
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- 22.
If a characteristic is sex-linked, it
- A.
Occurs only in females.
- B.
Occurs most commonly in males.
- C.
Can never occur in females.
- D.
Is always fatal.
Correct Answer
B. Occurs most commonly in males.Explanation
Sex-linked characteristics are determined by genes located on the sex chromosomes (X and Y). In humans, most sex-linked traits are located on the X chromosome. Since males have one X and one Y chromosome, they only need one copy of the gene to express the trait. In contrast, females have two X chromosomes, so they need to inherit two copies of the gene to express the trait. Therefore, sex-linked traits occur more commonly in males because they only need to inherit one copy of the gene. However, it is possible for females to express sex-linked traits if they inherit two copies of the gene or if the gene is dominant.Rate this question:
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- 23.
Since the allele for colorblindness is located on the X chromosome, colorblindness
- A.
Cannot be inherited.
- B.
Occurs only in adults.
- C.
Is sex-linked.
- D.
None of the above.
Correct Answer
C. Is sex-linked.Explanation
Colorblindness is a sex-linked trait because the allele responsible for it is located on the X chromosome. Since males have only one X chromosome, they are more likely to be affected by colorblindness if they inherit the allele. Females, on the other hand, have two X chromosomes, so they have a lower chance of being affected. This pattern of inheritance is characteristic of sex-linked traits. Therefore, the correct answer is that colorblindness is sex-linked.Rate this question:
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- 24.
The sex of an offspring is determined by
- A.
The mother.
- B.
The father.
- C.
Both parents.
- D.
The offspring.
Correct Answer
B. The father.Explanation
The sex of an offspring is determined by the father because the father's sperm carries either an X or a Y chromosome. If the sperm carries an X chromosome, the offspring will be female, and if it carries a Y chromosome, the offspring will be male. The mother's egg always carries an X chromosome, so the father's contribution determines the sex of the offspring.Rate this question:
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- 25.
When Gregor Mendel crossed true-breeding pea plants with purple flowers with true-breeding plants that had white flowers, all the offspring had purple flowers because
- A.
The allele for purple flowers is recessive.
- B.
The allele for white flowers is dominant.
- C.
The allele for purple flowers is dominant.
- D.
They were true-breeding like their parents.
Correct Answer
C. The allele for purple flowers is dominant.Explanation
When Gregor Mendel crossed true-breeding pea plants with purple flowers with true-breeding plants that had white flowers, all the offspring had purple flowers because the allele for purple flowers is dominant. This means that the presence of the allele for purple flowers overrides the presence of the allele for white flowers, resulting in the expression of the purple flower phenotype in all the offspring. Since all the offspring had purple flowers, it can be concluded that the allele for purple flowers is dominant in this particular genetic cross.Rate this question:
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- 26.
A tall plant is crossed with a short plant. If the tall F1 pea plants are allowed to self-pollinate,
- A.
The offspring will be of medium height.
- B.
All of the offspring will be tall.
- C.
All of the offspring will be short.
- D.
Some of the offspring will be tall, and some will be short.
Correct Answer
D. Some of the offspring will be tall, and some will be short.Explanation
When a tall plant is crossed with a short plant, the resulting F1 generation will all be tall because the tall trait is dominant over the short trait. However, when these tall F1 plants are allowed to self-pollinate, their offspring (F2 generation) will show a variation in height. This is because the tall trait is determined by a dominant allele (T) and the short trait is determined by a recessive allele (t). Therefore, some of the offspring will inherit the dominant allele and be tall, while others will inherit the recessive allele and be short.Rate this question:
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- 27.
A heterozygous tall pea plant is crossed with a short plant. The probability that an F1 plant will be tall is
- A.
25%.
- B.
50%.
- C.
75%.
- D.
100%.
Correct Answer
B. 50%.Explanation
When a heterozygous tall pea plant (Tt) is crossed with a short plant (tt), the possible genotypes of the offspring are Tt and tt. Since the tall trait is dominant over the short trait, the Tt genotype will result in a tall plant. The tt genotype will result in a short plant. Therefore, out of the two possible genotypes, only one will be tall. This means that the probability of an F1 plant being tall is 50%.Rate this question:
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- 28.
In the Punnett square shown in Figure 11–1, which of the following is true about the offspring resulting from the cross?
- A.
About half are expected to be short.
- B.
All are expected to be short.
- C.
About half are expected to be tall.
- D.
All are expected to be tall.
Correct Answer
D. All are expected to be tall.Explanation
The Punnett square shown in Figure 11-1 suggests that both parents are homozygous dominant for the tall trait. This means that they both have two copies of the dominant allele for tallness. As a result, all of the offspring will inherit at least one copy of the dominant allele and will therefore be tall.Rate this question:
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- 29.
A cross of a black chicken (FBFB) with a white chicken (FWFW) produces all black and white speckled offspring (FBFW). This type of inheritance is known as
- A.
Incomplete dominance.
- B.
Polygenic inheritance.
- C.
Codominance.
- D.
Multiple alleles.
Correct Answer
C. Codominance.Explanation
A cross between a black chicken and a white chicken produces offspring with a combination of both black and white feathers, resulting in a speckled appearance. This is an example of codominance, where both alleles for feather color are expressed equally in the offspring. Incomplete dominance would result in a blending of the two colors, not the distinct speckled pattern seen here. Polygenic inheritance involves the contribution of multiple genes to a single trait, which is not the case in this scenario. Multiple alleles refers to the presence of more than two options for a specific gene, which is also not applicable here.Rate this question:
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- 30.
How many different allele combinations would be found in the gametes produced by a pea plant whose genotype was RrYy?
- A.
2
- B.
4
- C.
8
- D.
16
Correct Answer
B. 4Explanation
In this question, the genotype of the pea plant is RrYy. Each gene has two alleles, so for the R gene, there are two possible alleles (R and r), and for the Y gene, there are also two possible alleles (Y and y). To determine the number of different allele combinations in the gametes, we multiply the number of possibilities for each gene together. Therefore, the number of different allele combinations would be 2 x 2 = 4.Rate this question:
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- 31.
If a pea plant that is heterozygous for round, yellow peas (RrYy) is crossed with a pea plant that is homozygous for round peas but heterozygous for yellow peas (RRYy), how many different phenotypes are their offspring expected to show?
- A.
2
- B.
4
- C.
8
- D.
16
Correct Answer
A. 2Explanation
When a pea plant that is heterozygous for round, yellow peas (RrYy) is crossed with a pea plant that is homozygous for round peas but heterozygous for yellow peas (RRYy), the offspring are expected to show two different phenotypes. This is because the traits for round peas and yellow peas are dominant, meaning that even if the offspring only inherit one copy of the dominant allele (R or Y), they will display the dominant phenotype. Therefore, the possible phenotypes for the offspring are round and yellow peas or round and green peas.Rate this question:
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- 32.
A male and female bison that are both heterozygous for normal skin pigmentation (Aa) produce an albino offspring (aa). Which of Mendel’s principles explain(s) why the offspring is albino?
- A.
Dominance only
- B.
Independent assortment only
- C.
Dominance and segregation
- D.
Segregation only
Correct Answer
C. Dominance and segregationExplanation
The offspring being albino suggests that the allele for albino pigmentation (a) is recessive to the allele for normal pigmentation (A). This is explained by Mendel's principle of dominance, which states that one allele can mask the expression of another allele. Additionally, the fact that both parents are heterozygous for normal pigmentation (Aa) indicates that they each carry one copy of the recessive allele for albino pigmentation (a). This is explained by Mendel's principle of segregation, which states that during gamete formation, the alleles for a trait separate and each gamete receives only one allele. Therefore, the correct answer is dominance and segregation.Rate this question:
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- 33.
The partially completed pedigree below is for a family with a genetic disorder. Which of the following statements are true about the pedigree shown above?
- A.
The mother is homozygous dominant and the father is heterozygous.
- B.
The father is homozygous dominant and the mother is heterozygous.
- C.
Both parents are homozygous recessive.
- D.
Both parents are heterozygous.
Correct Answer
D. Both parents are heterozygous.Explanation
Based on the pedigree, it is evident that the genetic disorder is present in some of the offspring, indicating that both parents must carry at least one copy of the recessive allele. Therefore, both parents are heterozygous for the genetic disorder.Rate this question:
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- 34.
The partially completed pedigree below is for a family with a genetic disorder. Which of the following statements could be true about the trait shown in the pedigree above?
- A.
The trait could be X-linked recessive.
- B.
The trait could be autosomal recessive.
- C.
The trait could be Y-linked recessive.
- D.
Both A and B.
- E.
Both B and C.
Correct Answer
D. Both A and B.Explanation
Both A and B could be true about the trait shown in the pedigree above. The pedigree shows that the trait is present in both males and females, indicating that it is not Y-linked. Additionally, the trait is passed from affected individuals to both male and female offspring, which suggests that it is not autosomal dominant. Therefore, the trait could be X-linked recessive, as it is passed from carrier mothers to affected sons, and it could also be autosomal recessive, as it is passed from carrier parents to affected offspring of both sexes.Rate this question:
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- 35.
In Drosophila fruit flies, red eyes is dominant to white eyes. The trait for eye color is found on the X chromosome. Consider a cross between a homozygous white-eyed female and a red-eyed male . What proportion of the offspring would be expected to be white-eyed?
- A.
Female = 0% white; male = 100% white
- B.
Female = 100% white; male = 0% white
- C.
Female = 50% white & 50% red; male = 50% white & 50% red
- D.
Female = 0% white; male = 25% white
Correct Answer
A. Female = 0% white; male = 100% whiteExplanation
In Drosophila fruit flies, red eyes is dominant to white eyes and the trait for eye color is found on the X chromosome. Since the female in the cross is homozygous white-eyed, she can only pass on the white-eyed allele to her offspring. On the other hand, the male is red-eyed, meaning he carries at least one red-eyed allele and can pass it on to his offspring. Since the male is not carrying any white-eyed allele, all of his offspring will have red eyes. Therefore, the proportion of the offspring expected to be white-eyed is 0%.Rate this question:
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- 36.
Organisms that have two identical alleles for a particular trait are said to be
- A.
Hybrid.
- B.
Heterozygous.
- C.
Homozygous.
- D.
Dominant.
Correct Answer
C. Homozygous.Explanation
Organisms that have two identical alleles for a particular trait are said to be homozygous. This means that both alleles for that trait are the same, whether they are dominant or recessive. Homozygous individuals are genetically pure for that trait and will always pass on the same allele to their offspring. In contrast, heterozygous individuals have two different alleles for the trait, while hybrids refer to the offspring of two different species or varieties. Dominant refers to the allele that is expressed over the recessive allele in heterozygous individuals.Rate this question:
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.png "The partially completed pedigree below is for a family with a genetic disorder.
Which of the following statements could be true about the trait shown in the pedigree above?")
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