1.
Two dice are thrown and the side of both dice facing up are observed. Which of the following events are mutually exclusive events?
Correct Answer
C. E: One of the dice shows a 2.
F: The sum is greater than 8.
Explanation
E= {(1,2), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,2), (4,2), (5,2), (6,2)}
F= {(3,6), (4,5), (4,6), (5,4), (5,5), (5,6), (6,5), (6,6)}
Therefore, events E and F are mutually exclusive events.
B= {(
2.
In a basketball tournament, 3 of the participating teams - Lion, Panther and Jaguar have the probabilities of 4/15, 3/10 and 1/5 respectively of winning the tournament. Find the probability that Lion or Jaguar will win the tournament.
Correct Answer
C. 7 / 15
Explanation
Let L be the event Lion will win the tournament and J be the event Jaguar will win the tournament.
L and J are mutually exclusive events.
Therefore, P(L or J) = P(L) + P(J) = 4/15 + 1/5 = 14/30 = 7/15
3.
In a basketball tournament, 3 of the participating teams - Lion, Panther and Jaguar have the probabilities of 4/15, 3/10 and 1/5 respectively of winning the tournament. Find the probability that neither Panther nor Jaguar will win the tournament.
Correct Answer
D. 1 / 2
Explanation
Let P be the event Panther will win the tournament and J be the event Jaguar will win the tournament.
P and J are mutually exclusive events.
P(neither P nor J) = 1 - P(P or J) = 1 - (9/30 + 6/30) = 1 - 15/30 = 1 - 1/2 = 1/2
4.
In a basketball tournament, 3 of the participating teams - Lion, Panther and Jaguar have the probabilities of 4/15, 3/10 and 1/5 respectively of winning the tournament. Find the probability that neither of the 3 teams will win the tournament.
Correct Answer
A. 7 / 30
Explanation
Let L be the event Lion will win the tournament, P be the event Panther will win the tournament and J be the event Jaguar will win the tournament.
L, P and J are mutually exclusive events.
P(neither L, P nor J) = 1 - P(L,P or J) = 1 - (4/15 + 9/30 + 6/30) = 1 - 23/30 = 7/30
5.
The letters of the word 'MUTUALLY' and the word 'EXCLUSIVE' are written on individual cards and the cards are put into a box. A card is picked at random.
What is the probability of picking the letter 'U' or 'E'?
Correct Answer
D. 5 / 17
Explanation
Let U be the event for picking the letter U and E be the event for picking the letter E.
U and E are mutually exclusive events.
Therefore, P(U or E) = P(U) + P(E) = 3/17 + 2/17 = 5/17
6.
The letters of the word 'MUTUALLY' and the word 'EXCLUSIVE' are written on individual cards and the cards are put into a box. A card is picked at random.
What is the probability of picking the letter 'U' or a consonant?
Correct Answer
B. 13 / 17
Explanation
Let U be the event for picking the letter U and C be the event for picking a consonant.
U and C are mutually exclusive events. Note: U is not a consonant.
Therefore, P(U or C) = P(U) + P(C) = 3/17 + 10/17 = 13/17
7.
The letters of the word 'MUTUALLY' and the word 'EXCLUSIVE' are written on individual cards and the cards are put into a box. A card is picked at random.
What is the probability of not picking the letter 'U' or 'E' or 'L'?
Correct Answer
D. 9 / 17
Explanation
Let U be the event for picking the letter U, E be the even for picking the letter E and L be the event for picking the letter L.
U, E and L are mutually exclusive events.
P(neither U, E or L) = 1 - P(U, E or L) = 1 - (3/17 + 2/17 + 3/17) = 1 - 8/17 = 9/17
U and C are mutually exclusive events. Note: U is not a consonant.
Therefore, P(U or C) = P(U) + P(C) = 3/17 + 10/17 = 13/17
8.
Ten cards numbered 11, 12, 13, 14, ..., 20 are placed in a box. A card is removed at random from the box. Find the probability that the number on the card is either even or prime.
Correct Answer
D. 9 / 10
Explanation
Let E be the event that the number of the card is an even number and P be the event that the number of the card is a prime.
P(E or P) = P(E) + P(P) = 5/10 + 4/10 = 9/10
9.
Ten cards numbered 11, 12, 13, 14, ..., 20 are placed in a box. A card is removed at random from the box. Find the probability that the number on the card is either even or divisible by 3.
Correct Answer
B. 3 / 5
Explanation
Let E be the event that the number of the card is even and T be the event that the number is divisible by 3.
E and T are NOT mutually exclusive events.
E or T = {12, 14, 15, 16, 18, 20}
P(E or T) = n(E or T) / n(S) = 6/10 = 3/5
10.
Ten cards numbered 11, 12, 13, 14, ..., 20 are placed in a box. A card is removed at random from the box. Find the probability that the number on the card is either odd or prime.
Correct Answer
D. 1 / 2
Explanation
Let O be the event that the number of the card is odd and P be the event that the number is prime.
O and P are not mutually exclusive events.
Note: ALL prime numbers (except 2) are odd number. Therefore, P(O or P) = P(O)
P(O or P) = P(O) = 5/10 = 1/2