Maintainence Management Analysis CDC 2r051 Volume 3

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Maintainence Management Analysis CDC 2r051 Volume 3 - Quiz
About This Quiz

This is volume 3 study questions for Airman to use to study and pass to certify them as a 5 level analyst.

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  • 2. 

    (401) A natural number is stated as a positive number that

    • A. has any actual value from zero to infinity.

    • B. has its own unique properties.

    • C. can be added or subtracted.

    • D. can be summed.

    Correct Answer
    A. A. has any actual value from zero to infinity.
    Explanation
    A natural number is defined as a positive integer that includes all values from zero to infinity. This means that it can take on any actual value within this range. The other options, such as having unique properties, being able to be added or subtracted, or being able to be summed, do not accurately describe what a natural number is.

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  • 3. 

    (401) How do you write: “The square root of 25 is 5.” as a mathematical expression?

    Correct Answer
    A.
    Explanation
    The mathematical expression for "The square root of 25 is 5" can be written as √25 = 5.

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  • 4. 

    (405) A sample of a population that is taken in such a manner that each value has an equal chance of being selected is referred to as a

    • A. biased sample.

    • B. random sample.

    • C. sampling theory.

    • D. sampling application.

    Correct Answer
    A. B. random sample.
    Explanation
    A random sample is a sample taken from a population in such a way that every individual in the population has an equal chance of being selected. This ensures that the sample is representative of the entire population and reduces the risk of bias. The other options, biased sample, sampling theory, and sampling application, do not accurately describe the specific method of sampling where each value has an equal chance of being selected.

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  • 5. 
    - ProProfs

    • A. 0.3.

    • B. 8.4.

    • C. 15.0.

    • D. 30.0.

    Correct Answer
    A. C. 15.0.
  • 6. 

    (401) Compute the difference of the signed numbers –17 – (–10).

    • A. +3.0.

    • B. –3.0.

    • C. –7.0.

    • D. –27.0.

    Correct Answer
    A. C. –7.0.
    Explanation
    The expression -17 - (-10) can be simplified by changing the subtraction of a negative number to addition. Therefore, -17 - (-10) becomes -17 + 10. When we add -17 and 10, we get -7. Therefore, the correct answer is c. –7.0.

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  • 7. 

    (410) Analysts frequently use the median because it is easy to compute and gives a better picture of data than the mean and mode when data are

    • A. normal.

    • B. skewed.

    • C. incomplete.

    • C. incomplete.

    Correct Answer
    A. B. skewed.
    Explanation
    Analysts frequently use the median because it is easy to compute and gives a better picture of data than the mean and mode when data are skewed. Skewed data means that the distribution of values is not symmetrical, with a longer tail on one side. In such cases, the mean can be heavily influenced by extreme values, while the mode may not accurately represent the central tendency. The median, on the other hand, is less affected by extreme values and provides a more robust measure of the central value in skewed distributions.

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  • 8. 

    (404) In the equation Y=X+2, what does the symbol “Y” represent?

    • A. Exponent.

    • B. Inequality.

    • C. Subscript.

    • D. Variable.

    Correct Answer
    A. D. Variable.
    Explanation
    In the equation Y=X+2, the symbol "Y" represents a variable. In mathematical equations, variables are used to represent unknown values or quantities that can vary. In this equation, "Y" is the variable that represents the value that is equal to "X" plus 2. Therefore, "d. Variable" is the correct answer.

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  • 9. 

    (402) What is 22 percent of 12?

    • A. 1.83.

    • B. 2.64.

    • C. 18.30.

    • D. 26.40.

    Correct Answer
    A. B. 2.64.
    Explanation
    To find 22 percent of 12, we can multiply 12 by 0.22. This calculation gives us 2.64, which is the correct answer.

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  • 10. 

    (405) If you construct a QLP retrieval to select every 8th record, you are using which sampling technique?

    • A. Selective.

    • B. Stratified.

    • C. Systematic.

    • D. Purposeful.

    Correct Answer
    A. C. Systematic.
    Explanation
    A systematic sampling technique involves selecting every nth item from a population, where n is a fixed interval or "skip" value. In this case, selecting every 8th record fits this definition, as it follows a systematic pattern. Selective sampling involves intentionally choosing certain items based on specific criteria, stratified sampling involves dividing the population into subgroups and selecting from each subgroup, and purposeful sampling involves selecting specific individuals or cases that are of particular interest.

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  • 11. 

    (427) What is the full range of Spearman’s rank correlation coefficient?

    • A. −1 to +1.

    • B. −1 to 0.

    • C. 0 to +1.

    • D. +1 to +2.

    Correct Answer
    A. A. −1 to +1.
    Explanation
    The full range of Spearman's rank correlation coefficient is from -1 to +1. This means that the coefficient can take any value between -1 and +1, indicating the strength and direction of the relationship between two variables. A value of -1 indicates a perfect negative correlation, a value of +1 indicates a perfect positive correlation, and a value of 0 indicates no correlation.

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  • 12. 

    (401) Which phrase is true regarding signed numbers?

    • A. Only whole numbers are used.

    • B. Negative numbers are not used.

    • C. Dividing by zero is permitted.

    • D. Both positive and negative numbers have values.

    Correct Answer
    A. D. Both positive and negative numbers have values.
    Explanation
    This phrase is true because both positive and negative numbers have values. In mathematics, signed numbers are used to represent both positive and negative quantities. They are essential for representing quantities such as gains and losses, temperatures above and below zero, and directions in coordinate systems. Therefore, option d is the correct answer.

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  • 13. 

    (406) You are given two pieces of test equipment that must be loaded on a pallet. One piece weighs 125 pounds and the other piece weighs 3.5 times as much. Using the ratio measurement scale, how much does the second piece of equipment weigh?

    • A. 375.0 pounds.

    • B. 415.5 pounds.

    • C. 437.5 pounds.

    • D. 500.0 pounds.

    Correct Answer
    A. C. 437.5 pounds.
    Explanation
    The second piece of equipment weighs 3.5 times as much as the first piece, which weighs 125 pounds. To find the weight of the second piece, we multiply 125 by 3.5, which equals 437.5 pounds. Therefore, the correct answer is c. 437.5 pounds.

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  • 14. 

    (416) Where does the most frequent value of a normal curve occur?

    • A. At the center of the distribution.

    • B. At all points in the distribution.

    • B. At all points in the distribution.

    • D. Away from the center of the distribution.

    Correct Answer
    A. A. At the center of the distribution.
    Explanation
    The most frequent value of a normal curve occurs at the center of the distribution because the normal curve is symmetric and bell-shaped. The center of the distribution represents the mean, which is the average value of the data. Since the normal curve is symmetrical, the highest point of the curve is at the mean, making it the most frequent value.

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  • 15. 

    (424) In statistics, what are the two control charts for attributes?

    • A. C and X charts.

    • B. C and P charts.

    • C. R and P charts.

    • D. X and P charts.

    Correct Answer
    A. B. C and P charts.
    Explanation
    The two control charts for attributes in statistics are the C chart and the P chart. The C chart is used to monitor the number of defects or nonconformities in a sample, while the P chart is used to monitor the proportion of defects or nonconformities in a sample. These charts help in identifying any variations or shifts in the process, allowing for timely corrective actions to be taken.

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  • 16. 

    (401) When using natural numbers, a number placed directly behind brackets, with no sign of operation between, indicates that

    • A. you must multiply and divide before adding and subtracting.

    • B. you can perform the calculation with or without the brackets.

    • C. the brackets should be removed before performing the calculation.

    • D. the quantity within the brackets must be multiplied by that number.

    Correct Answer
    A. D. the quantity within the brackets must be multiplied by that number.
    Explanation
    When using natural numbers, a number placed directly behind brackets, with no sign of operation between, indicates that the quantity within the brackets must be multiplied by that number.

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  • 17. 

    (407) With a noncumulative frequency distribution range of 3.6, which class interval will give you 18 classes?

    • A. 0.1.

    • B. 0.2.

    • C. 0.3.

    • D. 0.4.

    Correct Answer
    A. B. 0.2.
  • 18. 

    (410) What must you do first to determine the median from ungrouped data?

    • A. Arrange the data in classes.

    • B. Determine the numerical average.

    • C. Determine the total of the values.

    • D. Arrange the data in ascending order.

    Correct Answer
    A. D. Arrange the data in ascending order.
    Explanation
    To determine the median from ungrouped data, the first step is to arrange the data in ascending order. This is because the median is the middle value of the data set when it is arranged in order. By arranging the data in ascending order, it becomes easier to identify the middle value and calculate the median accurately.

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  • 19. 

    (417) The causes of variation that can be identified on a control chart, regulated, and possibly eliminated are

    • A. natural.

    • B. random.

    • C. assignable.

    • D. due to chance.

    Correct Answer
    A. C. assignable.
    Explanation
    The correct answer is c. assignable. Assignable causes of variation are those that can be identified and controlled, leading to possible elimination. These causes are not random or due to chance, but rather can be attributed to specific factors or events. By identifying and addressing these assignable causes, organizations can improve their processes and reduce variation in their outputs.

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  • 20. 

    (418) When identifying processes out of control and using a control chart, what action should you take if you have set your control limits at three standard deviations and later find not enough time is spent looking for assignable causes?

    • A. Switch to tighter limits.

    • B. Recalculate the standard deviation.

    • C. Keep established limits and do not investigate.

    • D. Discard current data and recalculate the standard deviation.

    Correct Answer
    A. A. Switch to tighter limits.
    Explanation
    If not enough time is spent looking for assignable causes, switching to tighter limits can help in identifying any potential issues or variations in the process. Tighter limits would make it easier to detect any deviations from the expected performance and take appropriate corrective actions. This ensures that the process remains in control and any potential problems are addressed promptly. Recalculating the standard deviation or discarding the current data would not address the issue of not enough time being spent on investigating assignable causes.

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  • 21. 

    (412) As the number of values in a normal distribution sample decreases, the standard deviation

    • A. becomes more representative of the population.

    • B. becomes less representative of the population.

    • C. remains the same.

    • D. increases.

    Correct Answer
    A. B. becomes less representative of the population.
    Explanation
    As the number of values in a normal distribution sample decreases, the standard deviation becomes less representative of the population. This is because with a smaller sample size, there is a higher chance of sampling error and less precision in estimating the true population standard deviation. Therefore, the standard deviation calculated from a smaller sample may not accurately reflect the variability of the entire population.

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  • 22. 

    (432) If 140 seasonal deviations occurred in 2001 and 150 occurred in 2002, how many deviations would you predict for 2003?

    • A. 130.

    • B. 135.

    • C. 155.

    • D. 160.

    Correct Answer
    A. D. 160.
    Explanation
    The question states that there were 140 seasonal deviations in 2001 and 150 in 2002. Since the number of deviations is increasing each year, it can be predicted that there will be even more deviations in 2003. Therefore, the most reasonable prediction would be 160 deviations, which is option d.

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  • 23. 

    (409) What measure of central tendency is the most typical value in a distribution?

    • A. Mean.

    • B. Mode.

    • C. Median.

    • D. Weighted mean.

    Correct Answer
    A. B. Mode.
    Explanation
    The mode is the measure of central tendency that represents the most frequently occurring value in a distribution. It is the value that appears the highest number of times, making it the most typical value. The mean represents the average value of the distribution, the median represents the middle value when the data is arranged in order, and the weighted mean is a variation of the mean that takes into account the weights assigned to different values. However, in terms of representing the most typical value, the mode is the correct answer.

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  • 24. 

    (415) If X equals 24 and s equals 6, what are the values of X ± 2s?

    • A. 24 and 48.

    • B. 18 and 36.

    • C. 12 and 36.

    • D. 12 and 24.

    Correct Answer
    A. C. 12 and 36.
    Explanation
    If X equals 24 and s equals 6, X + 2s would be 24 + 2(6) = 24 + 12 = 36. Similarly, X - 2s would be 24 - 2(6) = 24 - 12 = 12. Therefore, the values of X ± 2s are 12 and 36.

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  • 25. 

    (428) For a time series-type of trend analysis, what is the recommended minimum period of time for the amount of data required?

    • A. 6 months.

    • B. 12 months.

    • C. 18 months.

    • D. 24 months.

    Correct Answer
    A. D. 24 months.
    Explanation
    For a time series-type of trend analysis, a minimum period of 24 months is recommended for the amount of data required. This is because a longer time period allows for a more accurate analysis of trends and patterns over time. Shorter periods may not capture enough data points to accurately identify and analyze trends, leading to less reliable results. Therefore, a minimum of 24 months is recommended to ensure sufficient data for a comprehensive trend analysis.

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  • 26. 

    (428) What month or months is/are not used in plotting a semi-average trend analysis line?

    • A. Middle.

    • B. End only.

    • C. Beginning only.

    • D. Beginning and ending.

    Correct Answer
    A. D. Beginning and ending.
    Explanation
    In plotting a semi-average trend analysis line, the months that are not used are the beginning and ending months. This means that only the middle months are considered for this type of analysis. The beginning and ending months are excluded because they may contain outliers or seasonal variations that could distort the trend line. By focusing on the middle months, a more accurate representation of the underlying trend can be obtained.

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  • 27. 

    (407) One way of comparing class frequencies to the total frequency is by

    • A. indirect comparison.

    • B. direct comparison.

    • C. visual inspection.

    • D. percentage.

    Correct Answer
    A. D. percentage.
    Explanation
    One way of comparing class frequencies to the total frequency is by using percentages. By calculating the percentage of each class frequency in relation to the total frequency, we can easily compare the relative sizes of different class frequencies. This allows us to understand the distribution of the data and identify any significant patterns or trends.

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  • 28. 

    (412) For any distribution, the sum of the deviations is

    • A. one.

    • B. zero.

    • C. less than one.

    • D. more than one.

    Correct Answer
    A. B. zero.
    Explanation
    For any distribution, the sum of the deviations is zero. This is because the deviations from the mean can be positive or negative, but they cancel each other out when summed together. Some values will be above the mean and have positive deviations, while others will be below the mean and have negative deviations. The sum of these deviations will always equal zero, indicating that on average, the values in the distribution are evenly distributed around the mean.

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  • 29. 

    (413) In estimating the standard error of the mean, for what sample size do you use n–1 in the formula?

    • A. 10 or more.

    • B. 50 or more.

    • C. Less than 25.

    • D. Less than 30.

    Correct Answer
    A. D. Less than 30.
    Explanation
    The correct answer is d. Less than 30. In estimating the standard error of the mean, the formula typically uses n-1 for sample sizes less than 30. This adjustment is made to account for the fact that with smaller sample sizes, the sample mean is less likely to accurately represent the population mean. By using n-1 instead of n in the formula, it provides a more conservative estimate of the standard error.

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  • 30. 

    (414) A normal distribution contains what two parameters?

    • A. Mean and mode.

    • B. Standard error and mode.

    • C. Mean and standard deviation.

    • D. Standard error and standard deviation.

    Correct Answer
    A. C. Mean and standard deviation.
    Explanation
    A normal distribution is characterized by its mean and standard deviation. The mean represents the average or central tendency of the distribution, while the standard deviation measures the spread or variability of the data around the mean. These two parameters are essential in fully describing the shape and characteristics of a normal distribution. The mode, which represents the most frequently occurring value, is not necessary to define a normal distribution. Standard error, on the other hand, is a measure of the uncertainty or variability of sample estimates and is not directly related to the parameters of a normal distribution.

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  • 31. 

    (414) In a normal distribution, how many standard deviations on each side of the mean contain over 99 percent of the area under the normal area curve within?

    • A. 1.

    • B. 2.

    • C. 3.

    • D. 4.

    Correct Answer
    A. C. 3.
    Explanation
    In a normal distribution, approximately 99.7% of the area under the curve falls within three standard deviations on each side of the mean. This means that the range from three standard deviations below the mean to three standard deviations above the mean contains the vast majority of the data. Therefore, the correct answer is c. 3.

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  • 32. 

    (407) The second step in making a frequency distribution is to

    • A. determine the range of the data.

    • B. determine the class interval size.

    • C. range the data from largest to smallest.

    • D. range the data from smallest to largest.

    Correct Answer
    A. B. determine the class interval size.
    Explanation
    The second step in making a frequency distribution is to determine the class interval size. This is important because it helps to organize the data into manageable groups or intervals. The class interval size should be chosen in a way that captures the range of values in the data set while also allowing for a sufficient number of intervals to accurately represent the data. By determining the class interval size, we can then proceed to group the data into these intervals and count the frequency of values within each interval.

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  • 33. 

    (408) What does each rectangle in a histogram represent?

    • A. Value of the data.

    • B. One class of data.

    • C. Upper and lower limits.

    • D. Number of frequencies.

    Correct Answer
    A. B. One class of data.
    Explanation
    Each rectangle in a histogram represents one class of data. A histogram is a graphical representation of a frequency distribution, where the data is divided into intervals or classes. The height of each rectangle corresponds to the frequency or number of observations that fall within that class. Therefore, each rectangle represents a specific range or class of data values.

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  • 34. 

    (425) When performing correlation analysis, as values in one set of measure increase and the corresponding or paired values in the other set also increase, the relationship is considered to be

    • A. positive.

    • B. negative.

    • C. a coefficient of correlation.

    • D. a low degree of scattered data.

    Correct Answer
    A. A. positive.
    Explanation
    When performing correlation analysis, if the values in one set of measure increase and the corresponding or paired values in the other set also increase, it indicates a positive relationship between the two sets of data. This means that as one variable increases, the other variable also tends to increase, suggesting a direct relationship between them.

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  • 35. 

    (426) The data used for Pearson’s coefficient of correlation must

    • A. be discrete.

    • B. be from the ordinal scale.

    • C. display homogeneity of variance.

    • D. display heterogeneity of variance.

    Correct Answer
    A. C. display homogeneity of variance.
    Explanation
    The data used for Pearson's coefficient of correlation must display homogeneity of variance. This means that the variance of the variables being compared should be similar across all levels or categories of the data. If there is heterogeneity of variance, where the variance differs significantly between groups, it can lead to biased or inaccurate correlation results. Therefore, it is important for the data to have homogeneity of variance in order to obtain reliable correlation coefficients.

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  • 36. 

    (429) Whenever data tend to form a straight line, what is the most popular method for computing the secular trend analysis of a time series?

    • A. Line of regression.

    • B. Time series analysis.

    • C. Least-squares method.

    • D. Parabolic trend analysis.

    Correct Answer
    A. C. Least-squares method.
    Explanation
    The most popular method for computing the secular trend analysis of a time series when the data tend to form a straight line is the least-squares method. This method involves fitting a straight line to the data by minimizing the sum of the squared differences between the observed values and the values predicted by the line. It is widely used because it provides a good estimate of the trend and is relatively easy to calculate. The line of regression, time series analysis, and parabolic trend analysis are not specifically designed for computing the secular trend in a straight line time series.

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  • 37. 

    (406) Given measurements of 5.0 hours, 10.0 hours, 15.0 hours, and 20.0 hours, what type of data and measurement scale would you use to classify these data items?

    • A. Discrete; ratio.

    • B. Discrete; interval.

    • C. Continuous; ratio.

    • D. Continuous; interval.

    Correct Answer
    A. C. Continuous; ratio.
    Explanation
    The given measurements of hours can take on any value within a range, making it continuous data. Additionally, the measurements are on a ratio scale because there is a meaningful zero point (0 hours) and the ratios between the measurements are meaningful (e.g. 10 hours is twice as long as 5 hours). Therefore, the correct classification for these data items is continuous and ratio.

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  • 38. 

    (411) A unique feature of the harmonic mean is it

    • A. can only be used for grouped data.

    • B. will always be less than the arithmetic mean.

    • C. is only used to average skewed distributions.

    • D. is never weighted when various quantities of the denominator factors are used.

    Correct Answer
    A. B. will always be less than the arithmetic mean.
    Explanation
    The harmonic mean is a type of average that is used to calculate the average of rates or ratios. It is calculated by dividing the number of observations by the sum of the reciprocals of the observations. One unique feature of the harmonic mean is that it will always be less than the arithmetic mean. This is because the harmonic mean gives more weight to smaller values, which pulls the average down. In contrast, the arithmetic mean gives equal weight to all values. Therefore, the harmonic mean will always be lower than the arithmetic mean.

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  • 39. 

    (422) What statistical control chart is used to plot the percent of defective items?

    • A. C chart.

    • B. P chart.

    • C. Chart of averages.

    • D. Chart of individuals.

    Correct Answer
    A. B. P chart.
    Explanation
    The P chart is used to plot the percent of defective items. This control chart is specifically designed to monitor the proportion of defective items in a process. It is commonly used in quality control to track the variation in the percentage of defective items over time. By plotting the proportion of defective items on the chart, any significant changes or trends can be identified, allowing for timely corrective actions to be taken. The P chart is an effective tool for monitoring and improving the quality of a process.

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  • 40. 

    (425) In predictive analysis, a coefficient of correlation indicates

    • A. which set of data caused the other.

    • B. to what extent two sets of data are related.

    • C. to what extent two sets of data are not related.

    • D. which set of data is independent or dependent.

    Correct Answer
    A. B. to what extent two sets of data are related.
    Explanation
    A coefficient of correlation measures the strength and direction of the linear relationship between two sets of data. It indicates the extent to which the two sets of data are related. A high positive correlation coefficient suggests a strong positive relationship, while a high negative correlation coefficient suggests a strong negative relationship. A correlation coefficient close to zero indicates a weak or no relationship between the two sets of data. Therefore, option b is the correct answer as it accurately describes the role of a coefficient of correlation in predictive analysis.

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  • 41. 

    (428) What is the minimum time period required to use linear trend analysis techniques?

    • A. 6 months.

    • B. 12 months.

    • C. 18 months.

    • D. 24 months.

    Correct Answer
    A. D. 24 months.
    Explanation
    The minimum time period required to use linear trend analysis techniques is 24 months. This is because linear trend analysis involves analyzing data over a period of time to identify patterns and trends. In order to accurately identify and analyze these trends, a sufficient amount of data points is needed. A longer time period, such as 24 months, provides a more comprehensive dataset and allows for a more accurate analysis of trends.

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  • 42. 

    (411) Compute a weighted mean for a distribution containing two values of 3 each, four values of 2 each, and four values of 5 each.

    • A. 1.0.

    • B. 3.4.

    • C. 6.6.

    • D. 11.3.

    Correct Answer
    A. B. 3.4.
    Explanation
    The weighted mean is calculated by multiplying each value by its corresponding weight, summing up these products, and then dividing by the total sum of the weights. In this case, we have two values of 3 with a weight of 2 each, four values of 2 with a weight of 4 each, and four values of 5 with a weight of 4 each. Therefore, the calculation would be (2*3 + 4*2 + 4*5) / (2+4+4) = 3.4.

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  • 43. 

    (413) Given a large number of random samples, the mean of all the sample means related to the population mean is

    • A. the same.

    • B. radically different.

    • B. radically different.

    • D. more than 3 standard deviations apart.

    Correct Answer
    A. A. the same.
    Explanation
    The mean of all the sample means related to the population mean is expected to be the same. This is because the sample means are calculated from random samples, which are expected to be representative of the population. Therefore, the average of all these sample means should converge to the population mean, resulting in the mean of all the sample means being the same as the population mean.

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  • 44. 

    (414) When plotted on normal probability graph paper, data from a normal distribution shows up as a

    • A. circle.

    • B. curved line.

    • C. straight line.

    • D. bell-shaped curve.

    Correct Answer
    A. C. straight line.
    Explanation
    When plotted on normal probability graph paper, data from a normal distribution shows up as a straight line. This is because normal probability graph paper is specifically designed to represent a normal distribution, with the x-axis representing the z-scores (standard deviations from the mean) and the y-axis representing the cumulative probability. When the data points are plotted on this graph paper, they form a straight line because the data is evenly distributed around the mean and follows a symmetrical pattern.

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  • 45. 

    (406) Which measurement scale consists of equal intervals between scale values and an arbitrary zero point?

    • A. Ratio.

    • B. Nominal.

    • C. Ordinal.

    • D. Interval.

    Correct Answer
    A. D. Interval.
    Explanation
    The interval measurement scale consists of equal intervals between scale values and an arbitrary zero point. This means that the differences between the values on the scale are meaningful and can be compared. However, the zero point is arbitrary and does not indicate the absence of the measured attribute.

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  • 46. 

    (409) The mode is the only measure of central tendency that can be used with what measurement scale?

    • A. Ratio.

    • B. Interval.

    • C. Ordinal.

    • D. Nominal.

    Correct Answer
    A. D. Nominal.
    Explanation
    The mode is the most appropriate measure of central tendency to use with nominal measurement scales. Nominal scales categorize data into distinct categories or groups, such as colors or categories of a variable. The mode represents the category that occurs most frequently in the data, making it the only measure of central tendency that can be applied to nominal data. The other measures of central tendency (mean and median) require numerical values and cannot be used with nominal scales.

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  • 47. 

    (423) In statistics, a C chart may be used to measure the

    • A. number of defective units.

    • B. number of defects per unit.

    • C. percent of defective units.

    • D. percent of defects per unit.

    Correct Answer
    A. B. number of defects per unit.
    Explanation
    A C chart is a type of control chart used in statistics to measure the number of defects per unit. It is commonly used in quality control processes to monitor and control the number of defects in a production process. The C chart allows for the identification of variations and trends in the number of defects, helping to identify potential issues and improve the overall quality of the process.

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  • 48. 

    (424) On what statistical control chart is the number of defects per unit plotted?

    • A. C chart.

    • B. P chart.

    • C. Chart for averages.

    • D. Chart for individuals.

    Correct Answer
    A. A. C chart.
    Explanation
    The C chart is used to plot the number of defects per unit. This control chart is commonly used when the number of defects can vary from unit to unit and does not follow a normal distribution. It helps to monitor and control the variation in the number of defects over time, allowing for early detection of any changes in the process that may lead to an increase in defects. The C chart is particularly useful in industries where the number of defects is discrete and countable, such as manufacturing or quality control.

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  • 49. 

    (411) The arithmetic mean should be weighted when

    • A. like values are found in a data series.

    • B. all items in a series are equal.

    • C. a mean of means is desired.

    • D. a series cannot be grouped.

    Correct Answer
    A. C. a mean of means is desired.
    Explanation
    When a mean of means is desired, the arithmetic mean should be weighted. This means that instead of treating all values equally, certain values are given more importance or weight in the calculation of the mean. This is useful when there are multiple subgroups or categories within a data series, and we want to calculate the mean of each subgroup and then take the mean of those subgroup means. Weighting allows us to give more importance to larger subgroups or subgroups with more variability, resulting in a more accurate representation of the overall data.

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Quiz Review Timeline (Updated): Mar 18, 2023 +

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  • Mar 18, 2023
    Quiz Edited by
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  • Aug 17, 2012
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    Magniciousx
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