Math 1 Mean Absolute Deviation

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| By Klrhinehart3843
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Quizzes Created: 6 | Total Attempts: 12,389
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  • 1/5 Questions

    Sherrie just registered for her wedding.  So far 6 items have been fulfilled on her registry.  Find the mean price of the fulfilled items. $29, $58, $15, $129, $75, $22

    • 43.5
    • 129
    • 54.7
    • 114
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About This Quiz

This Math 1 Mean Absolute Deviation quiz assesses skills in statistical analysis, focusing on calculating mean absolute deviation and understanding variability across different data sets. It is designed to enhance learners' proficiency in practical statistics application.

Math 1 Mean Absolute Deviation - Quiz

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  • 2. 

     Find the mean absolute deviation for the set below. S = {85, 90, 68, 75, 79}

    • 79.4

    • 6.48

    • 32.4

    • 79

    Correct Answer
    A. 6.48
    Explanation
    The mean absolute deviation (MAD) is a measure of the average distance between each data point and the mean of the set. To find the MAD, we first calculate the mean of the set, which is (85+90+68+75+79)/5 = 79.4. Then, we find the absolute difference between each data point and the mean: |85-79.4| = 5.4, |90-79.4| = 10.6, |68-79.4| = 11.4, |75-79.4| = 4.4, and |79-79.4| = 0.4. Finally, we calculate the average of these absolute differences: (5.4+10.6+11.4+4.4+0.4)/5 = 6.48. Therefore, the mean absolute deviation for the set S is 6.48.

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  • 3. 

    Find the mean absolute deviation for the set below. S = {65, 90, 85, 70, 70, 95, 55}

    • 12.24

    • 75.7

    • 85.7

    • 40

    Correct Answer
    A. 12.24
    Explanation
    The mean absolute deviation is a measure of how spread out the data points are from the mean. To find the mean absolute deviation, we first find the mean of the set. The mean of the set {65, 90, 85, 70, 70, 95, 55} is 75.7. Then, we find the absolute value of the difference between each data point and the mean, and calculate the average of these absolute differences. The mean absolute deviation for this set is 12.24.

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  • 4. 

    Find the mean absolute deviation of the fulfilled items on Sherrie's registry. $29, $58, $15, $129, $75, $22

    • 196

    • 54.7

    • 114

    • 32.67

    Correct Answer
    A. 32.67
    Explanation
    The mean absolute deviation is a measure of the average distance between each data point and the mean of the data set. To find the mean absolute deviation, we first calculate the mean of the data set, which is the sum of all the numbers divided by the total count. In this case, the mean is (29 + 58 + 15 + 129 + 75 + 22) / 6 = 328 / 6 = 54.67.

    Next, we find the absolute deviation for each data point by subtracting the mean from each number and taking the absolute value. The absolute deviations are: |29 - 54.67| = 25.67, |58 - 54.67| = 3.33, |15 - 54.67| = 39.67, |129 - 54.67| = 74.33, |75 - 54.67| = 20.33, |22 - 54.67| = 32.67.

    Finally, we calculate the mean of these absolute deviations, which is (25.67 + 3.33 + 39.67 + 74.33 + 20.33 + 32.67) / 6 = 196 / 6 = 32.67. Therefore, the mean absolute deviation of the fulfilled items on Sherrie's registry is 32.67.

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  • 5. 

    Family A and Family B both have 8 people in their family.  The ages of each member is listed below.  Which statement is correct about the variability of the two families. Family A:  35, 5, 42, 9, 16, 3, 8, 12 Family B:  1, 5, 29, 3, 7, 35, 6, 9

    • The variability is the same for both Family A and Family B because t hey have the same mean absolute deviation.

    • The variability for Family A is greater because the mean is greater for Family A.

    • The variability for Family B is greater because the mean absolute deviation is greater for Family B.

    • There is not enough information to determine the variability.

    Correct Answer
    A. The variability for Family B is greater because the mean absolute deviation is greater for Family B.
    Explanation
    The correct answer is that the variability for Family B is greater because the mean absolute deviation is greater for Family B. This can be determined by calculating the mean absolute deviation for both families. The mean absolute deviation measures the average distance between each data point and the mean of the data set. By comparing the mean absolute deviation for both families, we can determine which family has a greater variability.

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  • Current Version
  • Oct 21, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Mar 05, 2010
    Quiz Created by
    Klrhinehart3843
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