Genetics Homozygous Quiz Questions
There are two types of Allele that a person can have and they are either dominant or recessive. Over the past week in genetics class. The quiz below is made up on a series of questions that are designed to test your understanding when it comes to genetics homozygous. Do you feel like you can tackle it with ease? Give it a shot and see how much you understood.
- 1.
In cats, the Manx (M) allele results in cats without tails, while the recessive allele (m) allows for tail growth. Homozygous M/M cats dies before birth. If 2 Manx cats mate, and they have 3 offspring, what is the chance that at least one has a tail?
- A.
2/3
- B.
1/3
- C.
8/27
- D.
19/27
Correct Answer
D. 19/27Explanation
The chance that none of the Manx cats has a tail is 2/3 X 2/3 X 2/3 =8/27
The chance that at least one has a tail is 27/27-8/27=19/27Rate this question:
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- 2.
Red hair is recessive to dark hair. Jenny has red hair and has 2 children with Tony who does not have red hair, but his mother does. What is the chance that both of their kids have red hair?
- A.
1/4
- B.
1/2
- C.
1/8
- D.
3/4
Correct Answer
A. 1/4Explanation
R= Dark hair r=red hair. Jenny is r/r Tony must be R/r since his mother has red hair but he does not. If they have 2 kids, the chance they both have red hair is 1/2 X 1/2 =1/4Rate this question:
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- 3.
The A and B blood types differ by a carbohydrate at the end of a chain of carbohydrates. In type O blood neither type of carbohydrate is added to the chain. There is a condition called The Bombay phenotype in which the carbohydrate which normally has the A or B carbohydrates attached is missing. This is a recessive condition on another chromosome. Individuals who have this condition cannot have blood type A, B or AB even if their ABO alleles give that blood type. We will use M to indicate the dominant allele and m to indicate the recessive allele. Someone who is type O; +/- ; M/m has children with someone who is type AB; +/-; M/m. What is the chance that they have a type B positive child? Note that the M gene has no effect on the +/- gene.
- A.
3/4
- B.
9/32
- C.
9/64
- D.
1/32
Correct Answer
B. 9/32Explanation
There is a 3/4 chance of not having the Bombay phenotype. There is a 1/2 chance of being B and there is a 3/4 chance of being positive. 3/ X 1/2 X 3?4 =9/32Rate this question:
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- 4.
Billy has the following genotype IA IB ; +/- Penny has the following genotype IA IA; +/-What is the chance that they have a child who is type A negative?
- A.
None
- B.
1/4
- C.
1/8
- D.
1/16
Correct Answer
C. 1/8Explanation
There is a 1/2 chance that the child is type A and a 1/4 chance that the child is -. 1/2 X 1/2 =1/4Rate this question:
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- 5.
Billy has the following genotype IA IB ; +/- Penny has the following genotype IA IA; +/- Which one of the following blood types could be found among the offspring
- A.
Type O positive
- B.
Type AB negative
- C.
Type B positive
- D.
All of the above could be found
Correct Answer
B. Type AB negativeExplanation
Neither parent has an i allele, so the offspring can not be type 0. All offspring get at least one A allele, so the offspring can not be type B.Rate this question:
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- 6.
This disease is lethal and strikes early in childhood.
- A.
True
- B.
False
Correct Answer
B. FalseExplanation
Since parents pass it on to their offspring, it is unlikely to have a child hood onset.Rate this question:
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- 7.
The pedigree below is
- A.
Autosomal Recessive
- B.
Autosomal Dominant
- C.
Sex linked Recessive
- D.
Sex linked Dominant
Correct Answer
B. Autosomal DominantExplanation
Every individual who has it has at least one parent who has it. Males pass it to both sons and daughters so it can not be sex linked dominant.Rate this question:
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- 8.
The pedigree below is
- A.
Autosomal Recessive
- B.
Autosomal Dominant
- C.
Sex linked recessive
- D.
Sex linked dominant
Correct Answer
C. Sex linked recessiveExplanation
It skips generations so it can not be dominant. It only affects males, making it likely to be sex linked.Rate this question:
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- 9.
The genotype off the individual indicated by the arrow is
- A.
XA/Y (A should be superscript)
- B.
X/A/Xa (A and a should be superscript)
- C.
XA/XA (A should be superscript)
- D.
A/a
Correct Answer
B. X/A/Xa (A and a should be superscript)Explanation
Since it is sex linked, the X designation is used. Since the indicated female gives rise to both affected and unaffected males, she must be heterozygous. (Also see that her father has it and she does not. This also means she must be heterozygousRate this question:
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Quiz Review Timeline +
Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.
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Current Version
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Oct 08, 2024Quiz Edited by
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Feb 04, 2014Quiz Created by
Adwohlwill
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