Pvhs Algebra 2 Final
(300).webp "Pvhs Algebra 2 Final - Quiz")
This test will contain information from the PVHS Algebra 2 coursework from sections 5-9
- 1.
Compound Interest 1 How much will you have in your account if:$57387 is invested at 11.2% compounded semi-annually for 84 years
- A.
$211637693.12
- B.
$542440089.7
- C.
$2184.39
- D.
$167350.18
Correct Answer
B. $542440089.7 -
- 2.
Compound Interest 1 How much will you have in your account if:$4865 is invested at 10.4% compounded monthly for 62 years
- A.
$68986.34
- B.
$65096.82
- C.
$2987779.59
- D.
$90372.21
Correct Answer
C. $2987779.59 -
- 3.
Population Growth 1 In the population of 1931 Geekville was 29214. If the growth rate is 2.9%, what was the population in ? 1944
- A.
269870
- B.
577048
- C.
27657
- D.
42591
Correct Answer
D. 42591 -
- 4.
Population Growth 1 In the population of 1925 Geekville was 1329. If the growth rate is 8.6%, what was the population in ? 1971
- A.
69437
- B.
44812812
- C.
132696
- D.
77889
Correct Answer
A. 69437 -
- 5.
Population Growth 1 In the population of 1931 Geekville was 11931. If the growth rate is 5.8%, what was the population in ? 1993
- A.
10494
- B.
434910
- C.
202718
- D.
139437
Correct Answer
B. 434910 -
- 6.
Continuous Compound Interest 2 How long will it take: $6574 to grow into $53287 if it is invested at 2.8% compounded continuously
- A.
25.23 years
- B.
12.39 years
- C.
74.73 years
- D.
50.79 years
Correct Answer
C. 74.73 yearsExplanation
The correct answer is 74.73 years. This can be calculated using the formula for continuous compound interest, which is A = P * e^(rt), where A is the final amount, P is the initial principal, e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time in years. In this case, we have P = $6574, A = $53287, r = 2.8%, and we need to solve for t. Rearranging the formula, we get t = ln(A/P) / r. Plugging in the values, we get t = ln($53287/$6574) / 0.028, which is approximately equal to 74.73 years.Rate this question:
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- 7.
Continuous Compound Interest 2 How long will it take: $49835 to grow into $85721 if it is invested at 10.6% compounded continuously
- A.
38.02 years
- B.
11.56 years
- C.
8.58 years
- D.
5.12 years
Correct Answer
D. 5.12 yearsExplanation
The correct answer is 5.12 years. This can be calculated using the formula for continuous compound interest: A = P * e^(rt), where A is the final amount, P is the initial principal, r is the interest rate, and t is the time in years. Rearranging the formula to solve for t, we have t = ln(A/P) / r. Plugging in the values given in the question, we get t = ln(85721/49835) / 0.106. Evaluating this expression gives t ≈ 5.12 years.Rate this question:
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- 8.
Compound Interest 2 How long will it take: $27065 to grow into $88726 if it is invested at 2.3% compounded semi-annually
- A.
18.12 years
- B.
26.47 years
- C.
51.92 years
- D.
15.81 years
Correct Answer
C. 51.92 years -
- 9.
Compound Interest 2 How long will it take: $42192 to grow into $80437 if it is invested at 6.4% compounded daily
- A.
15.8 years
- B.
9.23 years
- C.
7.48 years
- D.
10.08 years
Correct Answer
D. 10.08 years -
- 10.
Radioactive Decay 1 The half-life of boogonium is 10 years. If you have 15 grams in 1930, how much will be left in 2053?
- A.
8.05 grams
- B.
0 grams
- C.
6.91 grams
- D.
18.21 grams
Correct Answer
B. 0 gramsExplanation
Since the half-life of boogonium is 10 years, it means that half of the substance will decay every 10 years. From 1930 to 2053, there is a time difference of 123 years, which is equivalent to 12.3 half-lives. Therefore, after 12.3 half-lives, there will be no boogonium left, resulting in 0 grams remaining.Rate this question:
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- 11.
Radioactive Decay 1 The half-life of boogonium is 326 years. If you have 36 grams in 1923, how much will be left in 2080?
- A.
25.45 grams
- B.
34.64 grams
- C.
25.78 grams
- D.
18.21 grams
Correct Answer
C. 25.78 grams -
- 12.
Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 10 a.m., you have 31 mg in your petrie dish and at 2 p.m., you measure only 18 mg. What's the half-life?
- A.
Half-life = 8.54 hours
- B.
Half-life = 9.27 hours
- C.
Half-life = 4.85 hours
- D.
Half-life = 5.1 hours
Correct Answer
D. Half-life = 5.1 hours -
- 13.
Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 5 a.m., you have 85 mg in your petrie dish and at 6 p.m., you measure only 25 mg. What's the half-life?
- A.
Half-life = 7.36 hours
- B.
Half-life = 4.85 hours
- C.
Half-life = 4.35 hours
- D.
Half-life = 7.48 hours
Correct Answer
A. Half-life = 7.36 hours -
- 14.
Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 9 a.m., you have 74 mg in your petrie dish and at 7 p.m., you measure only 56 mg. What's the half-life?
- A.
Half-life = 60.62 hours
- B.
Half-life = 24.87 hours
- C.
Half-life = 20.65 hours
- D.
Half-life = 24.2 hours
Correct Answer
B. Half-life = 24.87 hours -
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Oct 17, 2024Quiz Edited by
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Jan 12, 2009Quiz Created by
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